# stats

posted by .

x and y independent exponential r.v with respctive parameters 2 and 3. find the cdf and density of z = x/y.

## Similar Questions

1. ### Calculus

Suppose X is a random variable whose CDF is given by F(x) = 0, X<0 X^3, 0<X<1; 1, 1<X Then the mean for this random variable is: I don't understand how to do CDF (cumulitive distribution function) or how to get the mean …

h t t p: //tinypic . co m/r/309lnac/3 1. The population growth exhibited by population A to the right is what?

h t t p: //tinypic . co m/r/309lnac/3 1. The population growth exhibited by population A to the right is what?

I posted this yesterday and someone said i did not haveoriginal data but it is in the link. Please take out spaces h t t p: //tinypic . co m/r/309lnac/3 1. The population growth exhibited by population A to the right is what?
5. ### stats

you are given the probabilities listed below P(A)= 0.25, P(B) = 0.30, P(C)=0.55, P(A&C) = 0.05, P(B&C)=0, P(B/A)=0.48. A) ARE A AND B INDEPENDENT?
6. ### Probability

Consider an RV X with the following density given parameters α and γ . f (x) = {(1/γ)e^(-(x-α)/γ) if x>α {0 if x ≤ α. a. Find E[X]. b. Find V[X]. c. If α = 4, γ = 2, ﬁnd …
7. ### Stats

In each of the four examples listed below, one of the given variables is independent (x) and one of the given variables is dependent (y). Indicate in each case which variable is independent and which variable is dependent. I. Rainfall; …
8. ### stats

Suppose that f(x) = 1:5x2 for -1 < x < 1 (0 elsewhere). Determine the following probabilities: (a) P(X > 0) (b) P(X > 0:5) (c) P(-0.5 < X </= 0.5) (f) Determine x such that P(X > x) = 0.05 (g) Find the cdf of …
9. ### Statistics

2. Given the cumulative distribution function (cdf) F(x)=(0 x<4 (x-4)/4 4 <= x <8 1 x >=8 2.1 Using the cdf, compute P(5<X<6). 2.2 What is the pdf of X?
10. ### probability

For each one of the following figures, identify if it is a valid CDF. The value of the CDF at points of discontinuity is indicated with a small solid circle. (original images belonging to: "The science of uncertainty") 1. No, it is …

More Similar Questions