A rocket weighs 1 x10^7 N while on the surface of the earth. The ignition of its engines results in a lift off force of 1.5 X 10^7 N
a) what is the mass of the rocket.
b) what is its acceleration at lift -off
c)How fast will it be moving if it acceleartion at this rates for 10 minutes.
d) How high will it be after 10 minutes.
1 the weight is mg, solve for m
2 Lift off force=mg + ma solve for a
vf=at change t to seconds
h=1/2 a t^2
The reality is that the weight of the rocket decreases as fuel is burned. I suppose your teacher wants to ignore that.
Thank you Mr Bob Pursley
a) To find the mass of the rocket, we can use the equation w = mg, where w is the weight of the rocket and g is the acceleration due to gravity. In this case, the weight of the rocket on the surface of the Earth is given as 1 x 10^7 N. Since the acceleration due to gravity on Earth is approximately 9.8 m/s^2, we can calculate the mass (m) of the rocket by dividing the weight (w) by the acceleration due to gravity (g):
m = w / g
m = 1 x 10^7 N / 9.8 m/s^2
b) To find the acceleration at lift-off, we can use the equation F = ma, where F is the force exerted and a is the acceleration. In this case, the lift-off force is given as 1.5 x 10^7 N. Using the mass (m) from part a, we can calculate the acceleration (a):
a = F / m
a = 1.5 x 10^7 N / (1 x 10^7 N / 9.8 m/s^2)
c) To calculate the speed at which the rocket will be moving after 10 minutes, we can use the equation vf = at, where vf is the final velocity, a is the acceleration, and t is the time. Convert 10 minutes to seconds by multiplying by 60:
t = 10 minutes * 60 seconds/minute
t = 600 seconds
vf = a * t
d) To find the height the rocket will reach after 10 minutes, we can use the equation h = 1/2 * a * t^2, where h is the height, a is the acceleration, and t is the time. We already have the time in seconds:
h = 1/2 * a * t^2