25.0 cm cubed of Barium hydroxide,Ba(OH)2 solution neautralises 35.0 cm cubed of aqueous hydrochloric acid of concentration 0.09 mol dm-3. what is the concentration of the barium hydroxide?
I like the titration equation
Normalitybase*volumebase*concentrationBase equals Normalityacid*volumeacid*concentrationacid.
Here, the normality of the base and acid is 2 and 1, respectively. Solve for the concentration of the base.
To find the concentration of the Barium hydroxide (Ba(OH)2) solution, we can use the given information and the titration equation you provided.
First, let's write down the equation based on the information given:
2 * Vbase * Cbase = 1 * Vaccid * Cacid
where:
Vbase is the volume of the base (Barium hydroxide) in cm³
Cbase is the concentration of the base (Barium hydroxide) in mol dm³
Vaccid is the volume of the acid (hydrochloric acid) in cm³
Cacid is the concentration of the acid (hydrochloric acid) in mol dm³
From the information given, we have:
Vbase = 25.0 cm³
Cbase = ?
Vaccid = 35.0 cm³
Cacid = 0.09 mol dm³
Now we can plug in these values and solve for Cbase:
2 * 25.0 cm³ * Cbase = 1 * 35.0 cm³ * 0.09 mol dm³
Simplifying the equation:
50.0 * Cbase = 3.15 mol
Now, divide both sides of the equation by 50.0 to solve for Cbase:
Cbase = 3.15 mol / 50.0
Cbase = 0.063 mol dm³
Therefore, the concentration of the Barium hydroxide solution is 0.063 mol dm³.