Intermediate Algebra
posted by Richard .
Am I going in the right track?
8x 1/x + 5x  3/2x
= 16x^2  2x/2x^2 + 5x^2  3x/2x^2
16x^2  2x + 5x^2  3x/2x^2
=21x^2  5/2x^2
Find the LCD
6/7z 28, 8/x^2 4x
= 7x(x4)
Simplify
3x^2  2x/15x10
= x/5
Let's start by looking at your first problem:
8x 1/x + 5x  3/2x
To simplify, use a common denominator, which is 2x.
16x^2/2x  2/2x + 10x^2/2x  3/2x
Now we have:
(16x^2  2 + 10x^2  3)/2x
Combining like terms in the numerator:
(26x^2  5)/2x
And that's as far as we can go on this one.
Is your second problem supposed to be 6/(7x  28), 8/(x^2  4x)?
If so, your LCD is correct!
For your third problem, I'm going to assume it is this:
(3x^2  2x)/(15x  10)
If so, your answer is correct!
If your first problem was this:
(8x  1)/x + (5x  3)/2x
...then your answer is close. The common denominator would still be 2x, but the answer would be (21x  5)/2x instead.
I hope this helps.
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