# algebra--distributive

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how would you do this prob.
negative4-(5y+6) = negative 7y+3
thanks.
happy halloween

I'm going to assume your problem is this:

-4 - (5y + 6) = -7y + 3

If that's the case, distribute the negative over the terms in the parentheses first:

-4 - 5y - 6 = -7y + 3

Combine like terms:

-5y - 10 = -7y + 3

Let's add 7y to both sides of the equation (whatever operation you do to one side of an equation you must do to the other side as well):

-5y + 7y - 10 = -7y + 7y + 3

2y - 10 = 3 -->we now have the variable on one side of the equation.

Let's add 10 to both sides:

2y - 10 + 10 = 3 + 10

2y = 13

Now divide both sides by 2 to get y by itself and solve the equation:

2y/2 = 13/2

y = 13/2

Substitute this value for y into the original equation to check. It always helps to check your work!

I hope this was your problem.

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