Geometry
posted by Mishka
How do I write an equation of a line perpendicular to the graph of
2y + x =5 that passes through the point at (1,2)
Given the line 2y + x =5, solve for y so the equation is in this form:
y = mx + b
Once you know the slope, m, you also know the slope of the perpendicular line.
As a reminder, the slope of the perpendicular line will be the negative reciprocal, or 1/m, m being the slope of the line above.

Anonymous
XY 3x+2y=6,z(3,2)
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