# Geometry

posted by Mishka

How do I write an equation of a line perpendicular to the graph of
-2y + x =-5 that passes through the point at (1,2)

Given the line -2y + x =-5, solve for y so the equation is in this form:

y = mx + b

Once you know the slope, m, you also know the slope of the perpendicular line.

As a reminder, the slope of the perpendicular line will be the negative reciprocal, or -1/m, m being the slope of the line above.

1. Anonymous

XY 3x+2y=-6,z(3,2)

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