# Geometry

posted by
**Mishka**
.

How do I write an equation of a line perpendicular to the graph of

-2y + x =-5 that passes through the point at (1,2)

Given the line -2y + x =-5, solve for y so the equation is in this form:

y = mx + b

Once you know the slope, m, you also know the slope of the perpendicular line.

As a reminder, the slope of the perpendicular line will be the negative reciprocal, or -1/m, m being the slope of the line above.