ahhhhhh...i cant seem to figure out how you graph an equation(linear)
a linear equation is y=mx+b right.
so m is the slope, b is y intercept. x and y are points. so what you can do is substitute a point to get another.
for x: y=5x+3
For x=1, y=8 so (1,8)
for x=0, y=3 so (0,3)
so on.... then graph all these points and connect
Yes, you are correct about the form of a linear equation, y = mx + b. To graph the equation, you need to follow a few steps:
1. Identify the slope (m) and y-intercept (b) from the equation. The slope represents how steep the line is, and the y-intercept is the point where the line intersects the y-axis.
2. Plot the y-intercept, (0, b), on the graph. This is the point where x = 0 and y = b.
3. Use the slope (m) to find additional points on the line. You can choose any x-values you like, substitute them into the equation, and solve for y. This will give you corresponding coordinate pairs (x, y) that lie on the line.
4. Plot these additional points on the graph.
5. Connect all the points with a straight line. This line represents the graph of the linear equation.
In your example, the equation is y = 5x + 3.
- The slope is 5, which means that for every increase of 1 in x, there is an increase of 5 in y.
- The y-intercept is 3, which is the point (0, 3).
To find more points for the graph, we can substitute other x-values into the equation:
- For x = 1, y = 5(1) + 3 = 8. This gives us the point (1, 8).
- For x = 2, y = 5(2) + 3 = 13. This gives us the point (2, 13).
- For x = -1, y = 5(-1) + 3 = -2. This gives us the point (-1, -2).
- For x = -2, y = 5(-2) + 3 = -7. This gives us the point (-2, -7).
You can continue this process to find more points, but with just a few points, you can already plot the graph by plotting these points and connecting them with a straight line.