TO DRWLS/MATH HELP PLEASE
posted by Jasmine202005 .
How do i solve inequalitites with three variables. I still can't figure it outplease help.
x+y=1
yz=3
2x+3y+z=1
THE ANSWERS ARE X=3,Y=2,Z=1
i KNOW THE ANSWERS I JUST DON'T KNOW HOW THE BOOK GOT THE ANSWERS . i 'VE TRIED MANY DIFFERENT WAYS AND I STILL DONT' UNDERSTAND IT PLEASE EXPLAIN IT.
i KNOW THAT I HAVE TO ADD EQUATION 2 AND THREE TO GET THE FOLLOWING
2X+3Y+Z=1
YZ=3
IN ORDER TO GET
2X+4Y=2
THEN I DON'T KNOW FROM HERE
There a couple ways to solve this. You have
x+y = 1
yz =3
2x+3y+z= 1
You could first show
x=1y and z=y+3 and substitute them into the 3rd equation to get
2(1y)+3y+y+3=1 and solve for y to get
22y+3y+y+3=1
5+2y=1 so 2y=4 and y=2
then put this into the first two equations to solve for x and z.
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