How many diangonals are there in a hexagon?
Is there a simple formula for this? I think I am doing this the hard way.
Thank you!
Three diagonals per vertex. There are six vertexs. However, each diagonal has two ends (vertexes), so divide the number by two.
Using exactly 4-4's, make the equations using +,-,x, and divide to equal 0-9.
3 students will represent your school at a conference at the state capital. A drawing will be held to select the 3 representatives from a group of 5 finalsts. If you and your friend are both finalists, what are the chances that both of your names will be drawn?
Is it 2 out of 5 chance? Not sure how to figure this one.
Thank you
3 students will represent your school at a conference at the state capital. A drawing will be held to select the 3 representatives from a group of 5 finalsts. If you and your friend are both finalists, what are the chances that both of your names will be drawn?
Is it 2 out of 5 chance? Not sure how to figure this one.
Thank you
The chances that both you and your friend will be selected can be calculated using probability.
To solve this, we need to consider the number of possible outcomes and the number of favorable outcomes.
The total number of possible outcomes is the number of ways to select 3 students from a group of 5 finalists, which can be calculated using combinations. In this case, it is denoted as C(5, 3), which is equal to 10.
Now, for favorable outcomes, we want to select both you and your friend. Since you both need to be chosen, there is only one way for that to happen.
Therefore, the probability of both you and your friend being selected is 1 out of 10.
So, it is not a 2 out of 5 chance, but rather a 1 out of 10 chance that both of your names will be drawn.
I hope this helps!