chemistry

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At 9.20 cm cubed air bubble forms in a deep late at a depth where the temperature and pressure are 6 degress Celcius and 4.50 atm, respectively. Assuming that the amount of air in the bubble has not changed, calculate its new volume at STP.


Use the combined gas law for this:

P1V1/T1 = P2V2/T2

change the temps to Kelvins.


With anonymous answering anonymous I'll just agree that p1v1/t1 = p2v2/t2 is the formula to use and remember to change T to Kelvin
C _ 273 = K.

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