Post a New Question

Calculus

posted by .

Okay so I have the following question and I am totally stuck:

Newton's Law of Gravitation says that the magnitude F or the force exerted by a body of mass m on a body of mass M given by
F=(GmM)/r^2
where G is the gravitational constant and r the distance between the bodies. A cosmonaut insde a spaceship is approahing a newly disvoered Planet Htrea. Looking at his instruments, he notices that at a distance of 20000km from the planet, its gravitational pull is increasing at 1N/km as he approaches the planet. Compute the gravitational force that the planet will exert on the spaceship at a distance of 10000km from it.

I don't see how I can do this without the mass of the plants or anything, theres to many variables. I don't know, in great need of help, please.


A note on distances: The distance in the law of gravitation is distance to the center of mass, normally the geometric center of the body.

F=(GmM)/r^2 Let M be the new Planet.

F/M= Gm/r^2 This quantity is called gravitational field, in N/kg units.

The gravitation field is dependent on distance squared from the center of the planet. So at half the distance, it ought to be four times as great. Think that out. You can get the new gravitational pull from that, in N/kg.

Now you are correct, the actual force will require the mass of the space ship.
Force= g * massspaceship where g is the field value of gravitational pull, in N/kg


Wow I am still totally lost. At half the distance it will be 4 times as great, this means that the new gravitational pull will be 4N/kg?

But I still don't know how that will let me find the gravitational force on the spaceship if we don't have the mass of the spaceship. I was thinking filling in the equation based on the first information given and find the mass, but I don't think I'm sure we have all the numbers, so that still wouldnt work. G=1N/km, m=?, M=? r=20000km. So it still can't work..


Yes, at half the distance..

g= 1N/kg (2E7/r )^2 so as r becomes 1E7, then g is 4N/kg.

You cant get the Force without the mass of the spaceship.

F=ma= mg you have to have m.


Okay that's what I was thinking and what was confusing me, but I thought maybe there was a way around that since they didn't give us one. Thanks = )


Well actually,what that guy got is wrong.The answer would e the recipicol of that.By the way Hello,I'm Keira.


Hello Keira.
I still can't get the answer from that though can I?

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Physics, 4 short questions

    VERY IMPORTANT FOR AN ESSAY ASSIGNMENT. PLEASE HELP ASAP! THANK U VERYYYYY MUCH! 1. What force is needed to give a mass of 25 kg an acceleration of 20m/s squared?
  2. Physics

    Q.1:When a force is applied to a body,several effects are possible.Which of the folloeing could NOT occur?
  3. calculus

    newtons law of gravitation says that the magnitude F of the force exerted by a body of mass m on a bod of mass M is F=GmM/r^2 where G is the gravitational constant and r is the distance between the bodies. a)find dF/dr and explain …
  4. Science Maths

    Sir, My question is as below:- Three particles a b & c of mass m are connected to each other by three massless rigid rods to from a rigid, equilateral triangular body of side 'l'.This body is is placed on a horizontal frictionless …
  5. physics

    Proponents of astrology claim that the positions of the planets at the time of a baby's birth will affect the life of that person in important ways. Some assert that this effect is due to gravity. Examine this claim with Newton's law …
  6. Physics

    Ok I guess the reason why I do not know how to do this problem is because I can not draw the proper free-body diagram... Three blocks on a frictionless horizontal surface are in contact with each other as shown in Fig. 4-5. A force …
  7. Calc

    Newton's Law of Gravitation says that the magnitude F of the force exerted by a body of mass m on a body of mass M is the following. F=(GmM)/r^2 Here G is the gravitational constant and r is the distance between the bodies. (a) Find …
  8. physics

    The figure below shows the speed of a person's body as he does a chin-up. Assume the motion is vertical and the mass of the person's body is 73.4 kg. Determine the force exerted by the chin-up bar on his body at the following times. …
  9. Newton' law of motion

    A resultant force of 50N pulls a body of mass 10kg along a smooth horizontal surface. Calculate the acceleration with which the body is moved
  10. Science

    A hirozontal force F works on a body of mass m1 and accelerates it by 5m/s^2. The same magnitude of horizontal force is exerted to another body of mass m2, which accerelates it by 2m/s^2. If m1 and m2 are combined, the acceleration …

More Similar Questions

Post a New Question