The line y = 3x + 5 crosses the y axis at ______?
When it crosses the y-axis x has to be 0, so what is y when x=0 in the equation
y = 3x + 5
Isn't it 5?
Hmm, you don't sound too confident with your answer, but yes, it's 5.
If you have an equation y=mx+b, m is the slope and b is the y intercept.
write y = - 3x - 6; ( -1, 5) in an equation of a line parallel to the given line but passing through the given point
In the equation y = 3x + 5, the coefficient of x is 3, which is the slope. The constant term is 5, which is the y-intercept.
To find the point where the line crosses the y-axis, we need to find the value of y when x is 0.
Substituting x = 0 into the equation, we get:
y = 3(0) + 5
y = 0 + 5
y = 5
Therefore, the line y = 3x + 5 crosses the y-axis at the point (0, 5).
In this case, the equation is y = 3x + 5, where the slope is 3 and the y-intercept is 5.
The y-intercept is the value of y when x is 0. So, to find the y-intercept, we substitute x=0 into the equation:
y = 3(0) + 5
Simplifying this, we get:
y = 0 + 5
y = 5
Therefore, the line y = 3x + 5 crosses the y-axis at y=5.