Hello, I am looking for the equation to solve this problem:

1. A .75 kg object with dimensions 24 and 20 are on a table.

What force does the object apply to the table? What pressure does the book apply?

Thanks!

Force = Mass * Acceleration (or in this case, gravity)
F = (.75kg)*(9.8m/s^2)
F = 7.35

Pressure = Force/Area
p = 7.35N/(??)
I am going to assume that the dimensions 24 and 20 are in meters and refer to a box.
The surface area of a side of a box is 24*20 = 480m
so
p = 7.35/480
p = 0.0153125 :)

To solve the problem, we start by finding the force that the object applies to the table. We can use the equation F = m * a, where F represents force, m represents mass, and a represents acceleration (in this case, due to gravity). Given that the mass of the object is 0.75 kg and the acceleration due to gravity is 9.8 m/s^2, we can calculate the force as follows:

F = (0.75 kg) * (9.8 m/s^2)
F = 7.35 N

The force exerted by the object on the table is 7.35 Newtons.

Next, we can find the pressure that the object applies to the table using the equation P = F/A, where P represents pressure, F represents force, and A represents area. To calculate pressure, we need to know the area over which the force is distributed. Assuming that the dimensions provided (24 and 20) are in meters and represent the sides of a box, we can find the surface area of one side of the box as follows:

Surface area = length * width = 24 m * 20 m = 480 m^2

Now we can calculate the pressure:

P = 7.35 N / 480 m^2
P = 0.0153125 N/m^2

The pressure applied by the object on the table is approximately 0.0153125 Newtons per square meter (N/m^2).