If line k*+2y-3=0 passes through point (-5,9) then k=
Is that k*x+2y-3=0 ?
If so, then substitute -5 for x and 9 for y to get
-5*k + 2*9 - 3 =0 and solve for k.
Nevermind. I am unable to comprehend this on the computer. I will ask someone to do it on paper for me. Thank-you.
I apologize if my explanation was not clear. I can certainly guide you through the process of solving the equation if you would like to try again. Let me break it down step by step:
1. Start with the equation: k*x + 2y - 3 = 0.
2. Substitute the given values into the equation. In this case, (-5, 9) represents the coordinates (x, y) of a point on the line.
- Replace x with -5: k*(-5) + 2y - 3 = 0.
- Replace y with 9: k*(-5) + 2*9 - 3 = 0.
3. Simplify the equation using basic algebraic operations.
- Multiply: -5k + 18 - 3 = 0.
- Combine like terms: -5k + 15 = 0.
4. Now, the equation is in the form -5k + 15 = 0. To solve for k, isolate the variable k by moving 15 to the other side of the equation.
- Subtract 15 from both sides: -5k = -15.
5. Finally, solve for k by dividing both sides of the equation by -5.
- Divide by -5: k = 3.
So, the value of k that satisfies the equation and passes through the point (-5, 9) is k = 3.
I hope this clears up any confusion. If you have any further questions or need assistance with any other topic, feel free to ask!