Another student determined the concentration of a vinegar solution to be 0.240 mol/L. If the accepted value for the concentration of the vinegar is 0.250 mol/L, the student's percentage erreo is
A. 1.00%
B. 1.24%
C. 2.40 %
D. 4.00%
D. because the difference between the two is .01. If you put .01 over .25 you will get .04 which is 4
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%error = [(0.250 - 0.240)/0.250] x 100 = ??
[(exp value - true value)/true value] x 100 = % error
To calculate the percentage error, you can use the formula:
% error = [(accepted value - measured value) / accepted value] x 100
In this case, the accepted value for the concentration is 0.250 mol/L, and the measured value is 0.240 mol/L. Plugging these values into the formula:
% error = [(0.250 - 0.240) / 0.250] x 100
Simplifying this calculation:
% error = [0.01 / 0.250] x 100
% error = 0.04 x 100
% error = 4%
Therefore, the correct answer is D. 4.00%.