If you fold a normal piece of paper in half and then fold that in half and then fold that in half etc and repeat the folding 50 times, How thick is your final result? You can assume that the original piece of paper is 1/1000 of an inch thick.
Let t denote the thickness. If we don't fold the paper, then it's thickness is
1*t=2^0 * t
If we fold the paper once, then the thickness is
2*t=2^1 * t
so if we fold it k times it should be
(2^k)*t
Now substitute k for the number of times it was folded and t for the thickness. I hope you're aware of how ridiculously large this number is with your given dimensions.
Papper can be only be folded again and again 8 times.
its 7
To calculate the thickness of the final result, you can use the formula: thickness = 2^k * t, where k is the number of times the paper is folded and t is the original thickness of the paper.
In this case, k is given as 50 (folded 50 times) and t is given as 1/1000 of an inch.
So, thickness = 2^50 * (1/1000) inch.
However, it's important to note that folding a normal piece of paper in half repeatedly will not be practically possible due to physical constraints such as the size and flexibility of the paper. The number of times a paper can be folded depends on various factors, including the creaseability and dimensions of the paper.
In reality, it is generally believed that a piece of paper can be folded in half about 7-8 times under normal conditions. Beyond that, the paper becomes too thick and stiff to fold easily.