At a construction site, a brick fell and hit the ground at 24m/s
a) from what height did the brick fall?
b) how long was it falling?
for a) i got 29.387m and for b) I got 2.448s
I got a) by using v^2=v0^2 +2a(x-x0)
for b) I used v=v0+at
Did I do this problem correctly?
If we use
(v_f)^2 = (v_0)^2 +2g*d where v_0 = 0, g=9.8m/s^2, and v_f=24m/s we have d=29m.
a) looks correct to me with that formula.
For b) v/g=t so the 2.4s looks right.
So yes, it appears to me you used the correct formulas and you did the calculations correctly too. Nice job.
(Be careful not to overstate the digits.)
Yes, you have correctly solved the problem using the appropriate formulas.
For part a) to calculate the height from which the brick fell, you used the equation v^2 = v0^2 + 2a(x - x0), where v is the final velocity (24 m/s), v0 is the initial velocity (0 m/s), a is the acceleration due to gravity (approximately 9.8 m/s^2), and x - x0 is the distance traveled by the brick (the height to be determined). By rearranging the equation and plugging in the given values, you correctly obtained a height of approximately 29.387 meters.
For part b) to calculate the time the brick was falling, you used the equation v = v0 + at, where v is the final velocity (24 m/s), v0 is the initial velocity (0 m/s), a is the acceleration due to gravity (approximately 9.8 m/s^2), and t is the time (to be determined). By rearranging the equation and plugging in the given values, you correctly obtained a time of approximately 2.448 seconds.
Your calculations are accurate, and you applied the correct formulas. Great job! Just be mindful of significant digits when reporting your answers.