Write the balanced net ionic equation for each of the following:
1) The reaction of dilute nitric acid with solid aluminum oxide.
2) The reaction of nitrous acid (HNO2) with potassium permanganate to produce nitrate and Mn(II) ions.
Thanks for any help.
How much of this do you know how to do? I don't want to duplicatre anything you already know. Do you know how to write the molecular equation? Can you balance it. Post what you know, then tell us exactly what you don't understand.Thanks for posting.
I'm not sure on how to do any of it. I'm not sure what the formulas are. I'm used to doing easier equations so I'm not quite sure how to do these.
what is the basic unit of mass in the metric system?
What is the basic unit of volume in the metric system?
What is the basic unit of lenght in the metric system?
You should post "New" questions separately using the "Post a new question" at the top of this page and not piggy-back onto a posted question. Posting pigg-back may lead to the question being missed.
When discussing basic units, we need to differentiate between what I assume you are calling the "basic metric system" from the accepted uses of the SI system.
While the basic unit in the metric system for mass is gram, the SI unit is kg.
The basic unit of length in the metric system is the meter. The SI unit is m.
The basic unit of volume in the metric system is the liter. There is no SI unit for volume (The SI system uses cubic meters.)
Write the balanced net ionic equation for each of the following:
1) The reaction of dilute nitric acid with solid aluminum oxide.
2) The reaction of nitrous acid (HNO2) with potassium permanganate to produce nitrate and Mn(II) ions.
Thanks for any help.
2. This is a redox (oxidation-reduction) reaction and there are rules for writing them. I will try to help you through it.
Step 1. Write what is given in the problem.
HNO2 + KMnO4 ==> Mn^+2 + NO3^-
Step 2. Separate into two half equations.
NO2^- ==> NO3^-
MnO4^- ==> Mn^+2
Step 3. Work on each equation separately.
a. Determine the oxidation state of the elements that changed. That is N in NO2^- and Mn in MnO4^-
i)N changes from +3 in NO2^- to +5 in NO3^-.
ii) Add electrons to the appropriate side to balance the change in electrons.
NO2^- ==> NO3^- + 2e
iii) Determine the charge on each side. I see a charge of -1 on the left and -3 on the right. This is an acid solution (since we have HNO2); therefore, add H^+ to the appropriate side to balance the charge.
NO2^- ==> NO3^- + 2e + 2H^+
iv) Now add H2O to the appropriate side to balance the H^+.
H2O + NO2^- ==> NO3^- + 2e + 2H^+.
v) Now check to make sure it is balanced.
3b. Do the same thing for Mn. I will give you the balanced equation but you need to practice these to see how they are done. Just follow the directions from above.
MnO4^- + 8H^+ + 5e ==> Mn^+2 + 4H2O
Step 4. Place the two equtions together and multiply each by whatever number is required to make the electrons the same. We must have the same number on the left as we have on the right; i.e., we want to make the electrons gained equal to the electrons lost.
NO2^- + H2O ==> NO3^- +2e + 2H^+
MnO4^- + 8H^+ + 5e ==> Mn^+2 + 4H2O
Multiply equation 1 by 5 and equation 2 by 2 (that makes 10 electrons gained and 10 electrons lost).
Step 5.Then add the two equations together. I will give you the final equation. Check to make sure it is correct. You need to do this yourself.
5H2O + 5NO2^- + 16H^+ + 10e + 2MnO4^- ==> 5NO3^- + 10e + 10H^+ + 2Mn^+2 + 8H2O
Step 6. Now cancel anything that appears on both sides of the equation.
That makes 10e on each side cancel. 16H^+ on the left and 10H^+ on the right will leave 6H^+ on the left. 5H2O on the left and 8H2O on the right will leave 3 H2O on the right. The final equation should be (you need to verify this):
5NO2^- + 6H^+ + 2MnO4^- ==> 5NO3^- + 2Mn^+2 + 3H2O
Step 5. Finally, check everything to make sure it balances. That means you
a. check atoms to make sure there are the same number of each atom on each side.
b. check the charge to make sure there is the same charge on each side.
c. Check to see that the electron change is the same.
I hope this helps. Please post specific questions you may have but tell me what trouble you are having. I suggest you print this page. It will come in handy in balancing other redox equations.
How do you balance the following equation using the half-reaction method?........
KClO3 --------> KCl + O2
unit of mass
what is the basic unit of length of the metric system?
645kg = cg
The basic unit of mass in the metric system is the gram (g).
The basic unit of length in the metric system is the meter (m).