An airplane is dropping bales of hay to cattle stranded in a blizzard on the Great Plains. The pilot releases the bales at 120 m above the level ground when the plane is flying at 80.0 m/s 55.0 degrees above the horizontal.

How far in front of the cattle should the pilot release the hay so that the bales will land at the point where the cattle are stranded?
Don't know!

The help I got last time was not right. But, this problem is confusing so it is very understandable!

Calculate how long (t) it takes the bales to hit the ground when dropped from an altitude of 120 m. The bales have a rather large initial upward velocity component when they are released becasue of the 55 degree flight angle

H = 120 + V sin 55 t - (1/2) g t^2 = 0 when the bales hit the ground. H is the elevation above the groud.
Solve that quadratic equation for t. V = 80 m/s; g = 9.8 m/s^2

The bales will travel a horizontal distance
V cos 55 * t
after release. That will tell you how far ahead of the cattle to release the hay.

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Resistance is a measure of how hard it is to make electricity flow through anything. It is defined as voltage divided by current.

In electrical circuits, resistance is measured in ohms (Ω). The higher the resistance, the more difficult it is for electricity to flow through the material. Materials with low resistance are called conductors, while materials with high resistance are called insulators.

Electrical resistance is the opposition to the flow of electric current in a material. It is a measure of how difficult it is for electricity to flow through a conductor. Resistance is determined by the material's properties and dimensions. In an electrical circuit, resistance is measured in ohms (Ω) and is calculated as the ratio of voltage (V) to current (I), according to Ohm's Law:

Resistance (R) = Voltage (V) / Current (I)

To calculate the time it takes for the bales to hit the ground when dropped from an altitude of 120 m, we can use the equation for vertical motion. The equation is as follows:

H = 120 + V*sin(55)*t - (1/2)*g*t^2 = 0

Here, H represents the elevation above the ground, V represents the initial velocity of the bales (which is 80 m/s), t represents time, and g represents the acceleration due to gravity (which is 9.8 m/s^2).

We can rearrange the equation to solve for t:

(1/2)*g*t^2 - V*sin(55)*t - 120 = 0

This equation is a quadratic equation in terms of t. To solve this equation, you can use the quadratic formula or factorization. Plugging in the values, you will find two solutions for t, one of which is negative and can be disregarded since time cannot be negative.

After calculating t, you can find the horizontal distance traveled by the bales after release using the equation:

horizontal distance = V*cos(55)*t

Plugging in the values of V, cos(55) (which is the cosine of the flight angle), and t will give you the distance in meters.

Now, to answer your question specifically, the amount of distance in front of the cattle where the pilot should release the hay is equal to the horizontal distance calculated above. This will ensure that the bales land at the point where the cattle are stranded.