im compeletely lost with the trigonometric functions...can anyone explain clearly to me?
Are you lost on the definitions?...where is the problem.
You need to be able to draw and label all the parts of a triangle, the hypotenuse and legs. Then be able to define sine, cosine, tangent, etc. After that you need to be able to identify identities and manipulate the trig functions.
You should be able to find plenty of sources to help to. Look at the jump box up above and find trignometry. There's plenty there to help you.
I need more specifics on your difficulties to continue here.
the problem is that..
i don't know what are sin, cos, and tan, and how to manipulate the trig functions
Be sure to check the jump box at the top. There is a trig section here. If you follow that link there is a page with a lot of trig exercises. The second section covers the definitions of the functions.
Sine is the ratio of a leg opposite an angle to the hypotenuse.
Cosine is the ratio of the leg adjacent to an angle to the hypotenuse.
Tangent is the ratio of ratio of a leg opposite an angle to the leg adjacent to the angle.
Check the site above and try some specific questions. Unfortunately this site is set up to help with homework, not for teaching. I'll do what I can to help you though.
sin can be written as y/r (r= radius)
cosine = x/r
tan= y/x
cosecant= r/y
secant= r/x
cotangent= x/y
as more of a definition, sin = opposite leg/hypotenus
cosine= adjacent leg/ hypotenuse
tangent= opposite leg/ adjacent
and cosecant is the inverse of sine, secant is the inverse of cosine, and cotangent is the inverse of tangent
Amiga, this is correct somewhat. But it is based on right triangles (x,y are right angles, and the lower definitions you gave are right triangles). But all angles have sin, cos, and tan functions whether or not they are in a triangle. But in a sense you are correct, a beginning student starts with the above. Thanks.
I need to learn to write algebraic expression that is equivalent to the expression...
sec[arcsin(x-1)]
I need to learn to write algebraic expression that is equivalent to the expression...
sec[arcsin(x-1)]
what are 2 equivalent statements on
sec15
cos80
csc70
and how do you get them??
To find two equivalent statements for sec 15, cos 80, and csc 70, you can use the trigonometric identities and apply some algebraic manipulations. Here's how:
1. sec 15:
To find an equivalent expression for sec 15, we can use the identity: secθ = 1/cosθ.
So, sec 15 = 1/cos 15.
2. cos 80:
To find an equivalent expression for cos 80, we can use the identity: cos(90 - θ) = sinθ.
So, cos 80 = sin(90 - 80) = sin 10.
3. csc 70:
To find an equivalent expression for csc 70, we can use the identity: cscθ = 1/sinθ.
So, csc 70 = 1/sin 70.
These equivalent statements can be obtained by applying the respective trigonometric identities to simplify the expressions.