# physics

posted by .

2) A proton is moving parallel to a uniform electric field. The electric field accelerates the proton and increases its linear momentum to 8.6 x 10^-23 kg·m/s from 2.4 x 10^-23 kg·m/s in a time of 5.7 x 10^-6 s. What is the magnitude of the electric field?

3) A uniform electric field has a magnitude of 3.1 x 10^3 N/C. In a vacuum, a proton begins with a speed of 2.5 x 10^4 m/s and moves in the direction of this field. Find the speed of the proton after it has moved a distance of 1.5 mm.

Here is what i did, but its not coming out correct

#2
i used the V= Vo +at to find the acceleration of the proton, then multiply that by the mass of proton (1.67262 x 10^-27 kg) to get the Force, than used the equation E = F/q where q is the charge on an electron and since its a proton its positive with the unit (1.6022×10-19 C) and i get 1.355268 x 10^-25

#3, i used the equation F = Eq = ma to find the acceleration of the proton, then used it in the equation V^2 = Vo^2 + 2ad and i got 25017.8105

2) examine the math:
Vf-Vo= at
MVf-MVo= ma*t
(MomentumF-momentumI)/t= force

(MomentumF-MomentumF/qt= E

E= (8.6E-23 - 2.4E-26)/((1.6E-19)(5.7E-6))
or about 94 volts/meter. check that.

3) a= Eq/m= (3.1E3*1.6E-19)/(1.67262E-27)
Then Vf^2=Vi^2 + 2ad
Vf= sqrt ((2.5E4)^2+ 2*.0015*(3.1E3*1.6E-19)/(1.67262E-27))

I don't get your answer.

thanks i get #2 now, but in #3, a= Eq/m= (3.1E3*1.6E-19)/(1.67262E-27)
, where did the q go?

thanks i get #2 now, but in #3, a= Eq/m= (3.1E3*1.6E-19)/(1.67262E-27)
, where did the q go?

#3, a= Eq/m= (3.1E3*1.6E-19)/(1.67262E-27)
, where did the q go?

check to make certain I typed all this correctly.

ahh thank you very much, i get it now, for #3 I mistaken 1.5mm as 1.5E-6 for some reason i though it was micrometers. thank you for your help, i get it now ^^

## Respond to this Question

 First Name School Subject Your Answer

## Similar Questions

1. ### Physics

I need help on the following questions, I am stuck and not sure on what to do, can someone work it out and or tell me steps to obtain the answer. Thank you 1) A point charge of -0.90 microC is fixed to one corner of a square. An identical …
2. ### Physics

A proton is moving parallel to a uniform electric field. The electric field accelerates the proton and increases its linear momentum to 5.0 10-23 kg m/s from 1.4 10-23 kg m/s in a time of 6.5 10-6 s. What is the magnitude of the electric …
3. ### Physics

please tell me where I went wrong. A proton is moving parallel to a uniform electric field. The electric field accelerates the proton and increases its linear momentum to 5.0x 10^-23 kg m/s from 1.4x 10^-23 kg m/s in a time of 6.5x …
4. ### physics

A proton traveling at 10^4 m/s in the positive x-direction, enters a region where there is uniform electric field of magnitude 10 v/m and a uniform magnetic field of magnitude 10^-2 T. The electric and magnetic fields are parallel …
5. ### physics

A proton traveling at 10^4 m/s in the positive x-direction, enters a region where there is uniform electric field of magnitude 10 v/m and a uniform magnetic field of magnitude 10^-2 T. The electric and magnetic fields are parallel …
6. ### physics-Electric & magnetic fields

A proton traveling at 10^4 m/s in the positive x-direction, enters a region where there is uniform electric field of magnitude 10 v/m and a uniform magnetic field of magnitude 10^-2 T. The electric and magnetic fields are parallel …
7. ### Physics

A proton is released from rest in a uniform electric field. After the proton has traveled a distance of 10.0 cm, its speed is 1.4 x 106 m/s in the positive x direction. Find the magnitude and direction of the electric field.
8. ### Physics

A proton with mass 1.67×10−27 kg and charge 1.60×10−19 C accelerates from rest in a uniform electric field of strength 500 N/C. (a) What is the magnitude of the acceleration of the proton?
9. ### Physics

A proton is released from rest inside a region of constant, uniform electric field E1 pointing due North. 14.8 seconds after it is released, the electric field instantaneously changes to a constant, uniform electric field E2 pointing …
10. ### physics

a particle having a charge of -2.0 x 10^-9 is acted on by a downward electric force of 3.0 x 10^-6 in a uniform electric field. what is the magnitude and direction of the electric force exerted on a proton placed in this field. what …

More Similar Questions