how can you get the answer 16 using these numbers 4,3,2,1=16 you can not use any number more than one time. Help!
3-1=2
2x2=4
4x4=16
Bold face type show numbers in the problem.
please help
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How about 4 x 2 x (3 - 1) = 16
If the order matters but no operations are specified then how about
4^(3-2)*1=16
Oops! I think I did that wrong. I thought I could get 16, but this is wrong.
4^(3-1^2)=16 I think is what I had the first time and then changed it.
4^(3-2+1)=16 The order is preserved too.
If we can use the factorial too, then how about
4! - 3^2 + 1 = 16
4 + 3! * 2* 1 =16
To get the answer of 16, using the numbers 4, 3, 2, and 1 only once, you can try various mathematical operations. Here are a few possible solutions:
1. 4 x 2 x (3 - 1) = 16 - In this equation, you multiply 4 by 2, and then subtract 1 from 3. Finally, you multiply the result of the subtraction by the product of 4 and 2, resulting in 16.
2. 4^(3 - 1^2) = 16 - Here, you subtract 1 squared from 3, giving you 2. Then, you raise 4 to the power of 2. The result is 16.
3. 4^(3 - 2 + 1) = 16 - In this equation, you subtract 2 from 3, obtaining 1. Then, you add 1 to the previous result, giving you 2. Finally, you raise 4 to the power of 2, resulting in 16.
These are just a few examples. Depending on the specific rules or constraints you have, there may be other valid solutions as well.