algebra

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What is the width of a rectangle with a perimeter of 70 feet if its length is 1 foot? 2 feet? L.feet?

perimeter = 2(length + width)
If perimeter = 70 then 35= length + width
Now substitute 1,2,and L and solve for width.

how do you find the L. feet?

L is supposed to be any length L
Perimeter/2 = L + width so
perimeter/2 - L = width
Here 35 - L = width

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