# algebra

posted by
**christine**
.

What is the width of a rectangle with a perimeter of 70 feet if its length is 1 foot? 2 feet? L.feet?

perimeter = 2(length + width)

If perimeter = 70 then 35= length + width

Now substitute 1,2,and L and solve for width.

how do you find the L. feet?

L is supposed to be any length L

Perimeter/2 = L + width so

perimeter/2 - L = width

Here 35 - L = width