An athlete starts at point A and runs at a constant speed of 5.40 m/s around a round track 250 . in diameter.
Find the x component of this runner's average velocity between points A and B.
GOT THIS!!! 3.4 m/s
Find the y component of this runner's average velocity between points A and B.
GOT THIS!!! 3.4 m/s
Find the x component of this runner's average ACCELERATION between points A and B.
nope. thought it was 0.95 because of a formula i found, but it is not.
Find the y component of this runner's average ACCELERATION between points A and B.
nope. thought it was 0.95 because of a formula i found, but it is not.
The change in velocity/time = average acceleration. I'm not sure how far apart the points are, so you'll need to figure that out.
it is -0.95 because it is in the y-direction
To find the x component of the runner's average acceleration between points A and B, you'll need to determine the change in the x component of velocity over time. The x component of velocity remains constant since the runner is moving in a circular path, so there is no change in the x component of velocity. Therefore, the x component of average acceleration is 0 m/s^2. There is no acceleration in the x direction.
Similarly, to find the y component of the runner's average acceleration between points A and B, you'll need to determine the change in the y component of velocity over time. The y component of velocity also remains constant since the runner is moving in a circular path, so there is no change in the y component of velocity. Therefore, the y component of average acceleration is also 0 m/s^2. There is no acceleration in the y direction.
In conclusion, both the x and y components of the runner's average acceleration between points A and B are 0 m/s^2.