posted by Cadi Almond .
How many milimetres of 0.114 M sulphuric acid solution provide the sulfuric acid required to react with the sodium hydroxide in 32.3 ml of 0.122 M NaOH according to the following equation?
H2SO4 + 2 NAOH ---> Na2SO4 + 2 H20
A millimeter is a unit of length, not volume. I am sure you intended to write milliliters.
How many mols NaOH do you have?
mols NaOH = L x M = 0.0323 L x 0.122 M = ?? mols NaOH.
Mols H2SO4 required = ??mols NaOH x (1 mol H2SO4/2 mols NaOH) = xx mols H2SO4.
mols H2SO4 = M x L
xx mols H2SO4 = 0.114 M x L
Solve for L and change to mL.
I hope this helps. We shall be happy to check your work if you wish to post it.
Yes, I did mean millilitres.
And thank you so much, I was just stuck on how to find the mol of H2SO4... you have no idea how much I appreciate your help!!!
I assume you understand that the numbers I used (1/2; i.e., 1 mol H2SO4/2 mols NaOH) came from the coefficients of the balanced chemical equation. Thanks for posting.