# Chemistry

posted by
**Cadi Almond**
.

How many milimetres of 0.114 M sulphuric acid solution provide the sulfuric acid required to react with the sodium hydroxide in 32.3 ml of 0.122 M NaOH according to the following equation?

H2SO4 + 2 NAOH ---> Na2SO4 + 2 H20

A millimeter is a unit of length, not volume. I am sure you intended to write milliliters.

How many mols NaOH do you have?

mols NaOH = L x M = 0.0323 L x 0.122 M = ?? mols NaOH.

Mols H2SO4 required = ??mols NaOH x (1 mol H2SO4/2 mols NaOH) = xx mols H2SO4.

mols H2SO4 = M x L

xx mols H2SO4 = 0.114 M x L

Solve for L and change to mL.

I hope this helps. We shall be happy to check your work if you wish to post it.

Yes, I did mean millilitres.

And thank you so much, I was just stuck on how to find the mol of H2SO4... you have no idea how much I appreciate your help!!!

:D:D:D:D:D!

I assume you understand that the numbers I used (1/2; i.e., 1 mol H2SO4/2 mols NaOH) came from the coefficients of the balanced chemical equation. Thanks for posting.