How many milimetres of 0.114 M sulphuric acid solution provide the sulfuric acid required to react with the sodium hydroxide in 32.3 ml of 0.122 M NaOH according to the following equation?
H2SO4 + 2 NAOH ---> Na2SO4 + 2 H20
A millimeter is a unit of length, not volume. I am sure you intended to write milliliters.
How many mols NaOH do you have?
mols NaOH = L x M = 0.0323 L x 0.122 M = ?? mols NaOH.
Mols H2SO4 required = ??mols NaOH x (1 mol H2SO4/2 mols NaOH) = xx mols H2SO4.
mols H2SO4 = M x L
xx mols H2SO4 = 0.114 M x L
Solve for L and change to mL.
I hope this helps. We shall be happy to check your work if you wish to post it.
Yes, I did mean millilitres.
And thank you so much, I was just stuck on how to find the mol of H2SO4... you have no idea how much I appreciate your help!!!
:D:D:D:D:D!
I assume you understand that the numbers I used (1/2; i.e., 1 mol H2SO4/2 mols NaOH) came from the coefficients of the balanced chemical equation. Thanks for posting.
You're welcome! I'm glad I could help. Yes, the coefficients in the balanced chemical equation determine the mole ratio between the reactants and the products. This ratio allows us to convert between the number of moles of one substance and another.
If you have any more questions or if there's anything else I can assist you with, feel free to ask!