hi i'm doing a side to side stemplot and i have a question.here are a few numbers of the data:
186
181
176
149
184
190
158
139
175
148
152
is is best if i round the data like 190, 180, 180, 150, ... and then do the stemplot or just directly do it.
this is the i might do it if i round the figures?
then as the stems, what would i put because this is a three digit number? do i put 14, 15, 16, 17, 18, and so on? Do i have to start the stems with a 1 or just start numbering according to the data?
No, I don't think you should round the data.
The stems should probably be the numbers 13,14,15,...,19
Line them up like this with the leafs to the right
S L
13 |9
14 |8,9
15 |2,8
.
.
.
You can finish it.
Starting the stems with 1 would accomplish nothing here. You can order the data to begin with, the order shouldn't matter when doing stats.
When creating a stemplot, it is generally recommended to use the original, unrounded data. This helps to preserve the accuracy of the values and can provide a more precise representation of the data set.
To create a stemplot, you will need to arrange the data in ascending order. Here are the numbers you provided in ascending order:
139, 148, 149, 152, 158, 175, 176, 181, 184, 186, 190
Next, you can determine the stems for your stemplot. Since your data consists of three-digit numbers, you can start with the smallest three-digit number, which is 139. The stem for this number will be 13. You can continue incrementing the stem by 1 for each subsequent number. Here is how the stems will look for your data:
13 |
14 |
15 |
16 |
17 |
18 |
19 |
For each number, you will then record the leaf (the rightmost digit) in the corresponding row with the stem. The leaves will be placed in ascending order next to their respective stems.
Using the data you provided, your finished stemplot would look like this:
13 | 9
14 | 8,9
15 | 2,8
16 |
17 | 5,6
18 | 1,4,6
19 | 0
Remember, starting the stems with 1 or any other specific number is not necessary. The stems should be determined based on the range of your data.