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I just don't understand this question:
h(t)=A*b^x h(3)=4 h(5)=40
Solve for b
Would you plug 3 into the x and set it equal to 4? (4=A*b^3) How would you solve for that because in the next question they go on to ask you to solve for A using the b you found...

Almost looks like your textbook has made a typo.

Yes, if this is a typo, you should "plug 3 into x and set it equal to 4".

You have two constants,a and b, and two equations to solve them.


divide the first equation into the second.


solve for b, then go back and substitute and solve for A.

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