posted by kris .
A horizontal translation is applied to the graph of y= X^ 3 + 2 so that it will pass through (3, 10) what is the new equation for the graph?
how do I do this?
When x=3, one wants y to be 10
y= (x+a)^3 + 2
20= (3+a)^3 + 2
solve for a. I would change it to
18=(3+a)^3 and take the cube root of each side to solve for a.
I think we need to make it
10=(x+a)^3 + 2 or
8=(x+a)^3 so 8^(1/3)=x+a, then solve this when x=3
Then substitute that into y=(x+a)^3 + 2.
thanks for your help but I am still confused of how to find a right like i got up to here:8=(3+a)^3
then I have to cube it but how? like what would i end up with? I am a little confused!
Ok, here's what we know.
y=x^3 + 2
We first determine the value of x that corresponds to y=10, thus
10=x^3 + 2, which means 8=x^3 and x=2
We know that we want the value x=2 to now be shifted to the right to correspond to x=3. This means we need to subtact 1 from x in shifting to the right (it seems a little counter-intuitive, but study it a bit.)
Thus y=(x-1)^3+2 is the desired shift.
Substitute x=3 and we have y=(3-1)^3+2=2^3 + 2=10.
What would be the shift if we wanted the same graph to coincide with (3,2)?
How about (-4,10)?
Take the cube root of each side...
2= a+3 solve for a. My solution above is wrong, a typo.
repost if you have questions.