equation
pete and tom sold 41cds and tom sold 9more,.how many did pete sold. how do i get the anwser,
It isn't clear to me how many Tom sold? IF he sold nine more than Pete
then X = # Pete sold
X + 9 = # Tom sold
X + X + 9 = 41.
Solve for X.
Post your work if you get stuck.
explain to me how i get the x, the question is how many more did tom sold, if both sold 41 but tom sold 9 more than pete. i don't understand this,
TomSold + Petesold=41 That is given.
also given is that Tomsold= Petesold+9
So putting that into the first equation..
(Petesold+9) + Petesold =41
2*Petesold + 9=41
2*Petesold = 41-9
2*petesold= 32
Petesold=32/2 = 16
and tomsold is that Plus 9
100
To solve the equation, let's assign variables to the unknowns. Let's say Pete sold X number of CDs and Tom sold Y number of CDs.
From the given information, we can determine two equations:
1. Pete and Tom sold 41 CDs: X + Y = 41
2. Tom sold 9 more CDs than Pete: Y = X + 9
To find the answer, you need to solve this system of equations. You can substitute the value of Y from equation 2 into equation 1:
X + (X + 9) = 41
Simplifying, we combine like terms:
2X + 9 = 41
Subtract 9 from both sides:
2X = 32
Divide both sides by 2:
X = 16
So, Pete sold 16 CDs. To find out how many Tom sold, we can substitute X into equation 2:
Y = 16 + 9
Y = 25
Therefore, Tom sold 25 CDs.