# MATH

posted by
**fiaie**
.

In a triangle ABC, angle A is 2 times angles C and angle B is 20 degrees less than angle C find the number of degrees in these angles

In a triangle ABC, angle A is 2 times angles C and angle B is 20 degrees less than angle C find the number of degrees in these angles

A = 2C

B = C - 20

Since the sum of the degrees of any triangle *always* = 180 degrees, A + B + C = 180. Substituting the above values of C for A and B will give you the value of C. Substitute the value of C in the other formulas and then check by putting all three values in A + B + C = 180.

I hope this helps. Thanks for asking.

um i am still confuse.. that helps alittle i did the problem and C= 50 do u plug that answer in the equation? i needa find the number of degrees in these angles...

** 50 degrees is correct for angle C.
You know A = 2C; therefore, A = 2 x 50 = 100.
You know B = C - 20. I will let you finish. I hope this helps. Check to make sure all of them add to 180.
**