In a triangle ABC, angle A is 2 times angles C and angle B is 20 degrees less than angle C find the number of degrees in these angles
In a triangle ABC, angle A is 2 times angles C and angle B is 20 degrees less than angle C find the number of degrees in these angles
A = 2C
B = C - 20
Since the sum of the degrees of any triangle always = 180 degrees, A + B + C = 180. Substituting the above values of C for A and B will give you the value of C. Substitute the value of C in the other formulas and then check by putting all three values in A + B + C = 180.
I hope this helps. Thanks for asking.
um i am still confuse.. that helps alittle i did the problem and C= 50 do u plug that answer in the equation? i needa find the number of degrees in these angles...
50 degrees is correct for angle C.
You know A = 2C; therefore, A = 2 x 50 = 100.
You know B = C - 20. I will let you finish. I hope this helps. Check to make sure all of them add to 180.
Yes, you are correct. Angle C is 50 degrees.
Now, let's proceed to finding the values of angles A and B.
Given that A is 2 times angle C, we can substitute the value of C (50 degrees) into the equation A = 2C:
A = 2 x 50
A = 100 degrees
So, angle A is 100 degrees.
Now, let's find the value of angle B. We're given that angle B is 20 degrees less than angle C. Substitute the value of C (50 degrees) into the equation B = C - 20:
B = 50 - 20
B = 30 degrees
Therefore, angle B is 30 degrees.
To verify our solution, we can check if the sum of all three angles is equal to 180 degrees:
A + B + C = 100 + 30 + 50 = 180
So, our solution is correct.
In conclusion, the number of degrees in each angle is:
Angle A: 100 degrees
Angle B: 30 degrees
Angle C: 50 degrees