math  marginal analyis
posted by becky .
A factory's output is Q=600K^1/2L^1/3 units, (read 600 x K to the 1/2 power x L to the 1/3 power). K denotes capital investment and L denotes the size of the labor force. Estimate the percentage increase in output that will result in a 2% increase in the size of the labor force if capital investment is not changed.
Q = 600K^1/2L^1/3
Q' = 300K^1/2L2/3 (read 300 x K to the negative 1/2 power x L to the negative 2/3 power.)
Percentage Change equation
100[Q'(.02)/Q]
100[300K^1/2L^2/3(0.02)/600K^1/2L^1/3]=
100[6K^1/2L^2/3]/600K^1/2L^1/3=
600K^1/2L^2/3/600K^1/2L^1/3
I'm not sure if this is correct so far and where do I go from here?
Your derivative should be with respect to labor force L.
Q = 600(K^1/2)*(L^1/3)
dQ/dL=600(K^1/2)(1/3)(L^2/3)
200(K^1/2) (L^2/3)
check that.
Percent change..
dQ=100[Q'(.02)/Q]
100[200*K^1/2)(L^2/3)dL/600(K^1/2)*(L^1/3)
]
=1/3*1/L*dL]
check that.
And from there..
percent change=1/3*1/L*dL]
= 1/3 (dL/L) where you are given
dL/L=.02
comments? check it all, it is hard to type an error when in ASCII
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