how do u find the lest common multiple
4a^2c & 14abc^5
and
what decimal part of 40 is 102?
if somone could..... can u explain how to do these thanks
The least common multiple
4a^2c & 14abc^5 :
First look at the factors of each term, and to what power they appear.
4a^2c: 2,2,a(twice) and c
14abc^5: 2,7,a,b,c(five times)
Now form a term that contains all of the factors of both, for the maximum number of times that they appear: You getsounds cool
2*2*7*a^2*b*c^5 = 28 a^2 b c^5
To express 40/102 as a decimal, divide 102 into 40 (or 51 into 20), using long division. If I use my hand calculator, I get
0.392156863...
(That is not really an algebra question)
so the ssecond proble would be 40 divided by102?
Yes
how do you do weighted averages?
ex. a pineapple drink contains 15% juice. how much pure pineapple juice should be added to 8 quarts of the drink to obtain a mixture containing 50% juice.
a cup of pie = pieman so... that answer is BOGGER
yes i know i am soo smart
thank you
To solve a weighted averages problem, you need to consider the proportions of the different components.
In this case, you have a pineapple drink containing 15% juice and you want to add pure pineapple juice to obtain a mixture containing 50% juice.
Let's assume x quarts of pure pineapple juice need to be added.
The total quantity of the mixture after adding the pure pineapple juice will be 8 + x quarts.
Now, set up an equation based on the proportion of juice in the mixture:
(15% of 8) + (100% of x) = 50% of (8 + x)
This can be written as:
0.15 * 8 + 1 * x = 0.50 * (8 + x)
Simplifying the equation:
1.2 + x = 4 + 0.5x
0.5x - x = 4 - 1.2
-0.5x = 2.8
x = 2.8 / -0.5
x = -5.6
Since the quantity of juice cannot be negative, there is no solution. Therefore, it is not possible to add pure pineapple juice to obtain a mixture containing 50% juice with the given conditions.
Just a note: Be careful when stating unrelated facts or using irrelevant expressions as they may confuse the reader and detract from the clarity of your explanation.