inverse
posted by kristie .
the direction was to find f^(1)x.
f(x) = x^2+2x+1, x >= 1
as a final answer, I got:
f^(1)x = sqrt(x)  1, x >= 0
is this right? I don't understand the restriction rules.
It is right. If originally x>=1, that puts f(x) >=0, and in the inverse function, this restriction travels to the new domain.
kristie, Bob is correct. The restriction rule carries to finv.
In general, even funcions, those with a poly. whose degree is an even integer, must be restricted. They are not 11. 11 means that each horizontal line through f(x) intersects f in at most one point.
Note that restricting f here makes it 11, thus invertible.
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