If the perimeter of a rectangle is 38 ft and the width is 9 ft, find its length. [Hint: The perimeter of a rectangle is given by P = 2L + 2W.]
I don't know why this is a problem for you. P = 38 and W = 9. Solve for L. You have only one unknown in the equation. If you don't know what to do next, please explain why you don't know how to proceed.
Let P = 38 and W = 9 and solve the perimeter equation "hint" for the length, L. As DrBob222 has stated, it is just a matter of plugging in the numbers and solving for the single unknown, L.
To find the length of the rectangle, you can use the perimeter formula: P = 2L + 2W, where P is the perimeter, L is the length, and W is the width.
In this problem, you are given that the perimeter (P) is 38 ft and the width (W) is 9 ft.
Substituting these values into the formula, you get: 38 = 2L + 2(9)
To solve for L, you need to isolate it on one side of the equation. Start by distributing the 2 to the 9: 38 = 2L + 18
Next, subtract 18 from both sides of the equation to move the constant term to the other side: 38 - 18 = 2L + 18 - 18
This simplifies to: 20 = 2L
Now you can solve for L by dividing both sides of the equation by 2: 20/2 = 2L/2
This gives you: 10 = L
Therefore, the length of the rectangle is 10 ft.