PreAlgebra
posted by Tammy Evert .
Find two consecutive odd integers such that 5 times the first integer is 12 more than 3 times the second.
let X = 1st odd number.
and Y = 2nd odd number = X + 2 since it is consecutive.
Now set up two equations (the first is Y = X + 2). The second is
5X = 3Y + 12.
Substitute in this last equation for Y = X + 2 and solve for X.
I hope this helps. If you get stuck please post your work to that point and tell us why you are confused as to the next step to take.
Let A and (A + 2) be the two consecutive integers.
Then,5A = 3(A + 2 + 12.
Can you take it from here?
6 (5 * 3 + 2}
Respond to this Question
Similar Questions

math
Determine whether there are 2 consecutive odd integers such that 5 times the first exceeds three times the second by 54. Can anyone help? 
maths
1. If the first and third of three consecutive odd integers are added, the result is 51 less than five times the second integer. Find the third integer. 2. Write as a subtraction problem and evaluate. 15 less than 2 n, n+1, N+2, ... … 
maths
1. If the first and third of three consecutive odd integers are added, the result is 51 less than five times the second integer. Find the third integer. Let the 3 numbers be x, (x + 1) and (x + 2). Then, x + (x + 2) = 5(x + 1)  51 … 
prealgebra
The perimeter of a triangle is 195 mm.If the lengths of the sides are consecutive odd integers,find the length of each side. what steps do i need to do in order to get the answre? 
algebra
Find the two consecutive odd integers such that 5 times the first integer is 12 more than 3 times the second. can some explain to me how to get this i was thinking the formula would be ' 5x+12=3x No, that's not it. The second integer … 
algebra
I have been working this one for awhile and have become more confused. Please assist. Problem: Find two consecutive odd integers such that 5 times the first interger is 12 more than 3 times the second. The key thing is to realize that … 
Algebra
Find two consecutive odd integers such that 5 times the first integer is 12 more than 3 times the second. I've gotten this far but confused as to what the two intergers are. 5x=3(x+2)=12 5x=3x+2+12 5x=3x+14 2x=14 2x/2x=14/2 x=7 Let … 
algebra 2
consecutive odd integer problem find two odd integers the sum of whose squares is 130. (sq)=squared let x= 1st odd int let x+2=2nd odd int (2x+2)(2x+2)=130 4x(sq) + 4x+ 4x +4=130 4x(sq) + 8x 126= 0 2(2x(sq)+4x63)=0 My question: WHAT … 
algebra 2
consecutive odd integer problem find two odd integers the sum of whose squares is 130. (sq)=squared let x= 1st odd int let x+2=2nd odd int (2x+2)(2x+2)=130 4x(sq) + 4x+ 4x +4=130 4x(sq) + 8x 126= 0 2(2x(sq)+4x63)=0 My question: the … 
Algebra
The sum of two consecutive odd integers is 56. A. Define a variable for the smaller integer. B. What must you add to an odd integer to get the next greater odd integer?