inverse
posted by kristie .
find f^1 (x). (this is asking me to find the inverse)
f(x) = (x2)^2, x <= 2
how do I solve this problem?
find f^1 (x). (this is asking me to find the inverse)
f(x) = (x2)^2, x <= 2
how do I solve this problem?>>
If f(x)=(x2)^2 x<2, then
let y=f(x)
 y = (x2)^2
sqrt(y)= x2
x(y)= sqrt (y) + 2
g(x)= sqrt(x) + 2
and that is the inverse function
check:
g(f(x))= sqrt( (x2)^2) +2 =x
f(g(x)= ((sqrt(x) + 2 2)^2= x
since g(f(x))=f(g(x)=x, then g(x) above is the inverse. Practice these.
I did not mean x<2, but x is less than or equal to. How is this going to change the answer?
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