1) Write 2^2 * 3 * 5 as a natural number? I get 60 is it right or should i put 4*3*5= 60
2) Write 420 as the product of its prime factors in exponent form?
What do i have to do ?
1) Write 2^2 * 3 * 5 as a natural number? I get 60 is it right or should i put 4*3*5= 60
2) Write 420 as the product of its prime factors in exponent form?
What do i have to do ?
60 is a natural number
420=divide by 2
2*210
2*2*105
divide by 5
2*2*5*51
divide by 17
2*2*5*17*3
2^2 * 3 *5* 17
so its 17, 5 and 2?
1) Yes, 60 is the correct representation of 2^2 * 3 * 5 as a natural number. You can simplify it further by multiplying the factors together, which gives you 4 * 3 * 5 = 60.
2) To write 420 as the product of its prime factors in exponent form, you need to factorize it by dividing it by prime numbers until you cannot divide anymore.
Start by dividing 420 by 2:
420 ÷ 2 = 210
Continue dividing by 2 until you cannot:
210 ÷ 2 = 105
Now divide by 5:
105 ÷ 5 = 21
Finally, divide by 3:
21 ÷ 3 = 7
At this point, 7 is a prime number, so you cannot divide any further. Therefore, the prime factors of 420 are 2, 2, 3, 5, and 7.
To express it in exponent form, you simply write down the prime factors with their respective exponents:
2^2 * 3^1 * 5^1 * 7^1
So the factorization of 420 in exponent form is 2^2 * 3^1 * 5^1 * 7^1.