inverse trig functions

posted by .

evaluate the following expressions:




i know the answers.. i jus don't know how to solve them =( PLEASE help me

I assume your sec^-1 notation denot4es the arcsecant function, etc.

sec^-1 (5/3) = cos^-1 (3/5). Think of a 3,4,5 right triangle. The tangent of the angle is 4/3.

sec^-1 (25/7) = cos^-1 (7/25)
Think of a 7,25,24 right triangle. The hypotenuse is 25 and the adjacent side is 7. The tangent is 24/7

csc^(5/3) = sin^-1 (3/5). Think of a 3,4,5 right triangle again. The hypotenuse is 5 and the opposite side of the angle in question is 3. The cotangent is (adjacent side)/(opposite side) = 4/3.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Integration

    Intergrate ¡ì sec^3(x) dx could anybody please check this answer. are the steps correct?
  2. more trig.... how fun!!!!

    if you can't help me with my first question hopw you can help me with this one. sec(-x)/csc(-x)=tan(x) thanx to anyone who can help From the definition of the sec and csc functions, and the tan function, sec(-x)/csc(-x) = sin(-x)/cos(-x) …
  3. calculus

    find dy/dx y=ln (secx + tanx) Let u= secx + tan x dy/dx= 1/u * du/dx now, put the derivative of d secx/dx + dtanx/dx in. You may have some challenging algebra to simplify it. Use the chain rule. Let y(u) = ln u u(x) = sec x + tan x …
  4. trig

    If sinx = -3/5, tan x > 0, sec y = -13/5 and cot y < 0, find the following: a. csc(x + y) b. sec (x - y) How do I get the answers of a. -65/33 b. -65/16 Thank you
  5. Math - Trig

    I'm trying to verify these trigonometric identities. 1. 1 / [sec(x) * tan(x)] = csc(x) - sin(x) 2. csc(x) - sin(x) = cos(x) * cot(x) 3. 1/tan(x) + 1/cot(x) = tan(x) + cot(x) 4. csc(-x)/sec(-x) = -cot(x)
  6. Math - Trigonometry

    Verify the following: 1. cos x/(1-sinx)= sec x + tan x 2. (tanx+1)^2=sec^2x + 2tan x 3. csc x = )cot x + tan x)/sec x 4. sin2x - cot x = -cotxcos2x
  7. trigonometry repost

    Reduce (csc^2 x - sec^2 X) to an expression containing only tan x. (is this correct?
  8. Calculus 12th grade (double check my work please)

    2- given the curve is described by the equation r=3cos ¥è, find the angle that the tangent line makes with the radius vector when ¥è=120¨¬. A. 30¨¬ B. 45¨¬ C. 60¨¬ D. 90¨¬ not sure A or D 2.) which of the following represents …
  9. calculus (check my work please)

    Not sure if it is right, I have check with the answer in the book and a few integral calculators but they seem to get a different answer ∫ sec^3(x)tan^3(x) dx ∫ sec^3(x)tan(x)(sec^2(x)-1) dx ∫ tan(x)sec(x)[sec^4(x)-sec^2(x)] …
  10. Trig verifying identities

    I am having trouble with this problem. sec^2(pi/2-x)-1= cot ^2x I got : By cofunction identity sec(90 degrees - x) = csc x secx csc-1 = cot^2x Then split sec x and csc-1 into two fractions and multiplied both numerator and denominators …

More Similar Questions