algebra
posted by tams .
A church group has a fund raiser in which they raise $2,040.00. If there were 69 more people then everyones donations would be $23.00 less. How many members were there originally and how much did they donate?
let n be the number of folks
let D be the donation per person
n*D=2040
(n+69)(d23)=2040
With those two equations, it ought to work out. Repost if you have difficulties.
I've studied this several ways.
There are a few different equations that can be defined to represent the given conditins.
One is:
Let N = the initial number of contributors and d = the initial donations.
Then, Nd = 2040 and N(d  23) + =69(d  23) = 2040.
Substituting and simplifying yields d = 23 + N/3.
N must be divisible by 3.
N......3...6...9.......>
d.....24...25..26......> Answer
Nd....72..150..234....>
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