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Sebin PS
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Sebin PS
Answers (1)
nth term is a+(n-1)d sum of 1st n terms = n/2(T1+Tn) a = 2 sum of 1st 5 terms = 5/2 (2 + 2+4d) = 10+10d 6th term = 2+5d sum of terms 6-10 = 5/2 (2+5d + 2+9d) = 10+35d 10+10d = 1/4 (10+35d) 40+40d = 10 + 35d 5d = -30 d = -6 sequence is 2 -4 -10 -16 -22 -28
