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Sabuda stephen
Questions and answers by visitors named
Sabuda stephen
Answers (1)
Time of flight: That would be twice the time it takes the ball to fall H = 150 m, which is t = 2*sqrt(2H/g) = 11.07 s (You double the fall time to get the total time of flight) Launch angle: V*sinA/g = t/2 = 5.533 s sin A = 0.5422 A = 32.8 degrees Range:
