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Gokul Gopakumar
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Gokul Gopakumar
Answers (1)
I have 2 answers 1. u=521m/s v=0 s= 0.840 now we use v^2=u^2+2as 0^2=521^2+2xax0.840 0=2771441+1.68a 1.68a=2771441 a= 2771441 by 1.68 a=161572.02 that's the first answer 2.velocity= distance by time velocity = 521ms distance = 0.840m therefore time =0.840
