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Fatiya
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Fatiya
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Mass of ZnCO3= mole × molar mass = 1 × 125= 125g ZnO + 2HCl ZnCl +H2O If 12.5g of ZnCO3 _ Xg of ZnO 125g of ZnCO3 _ 81g of ZnO ( molar mass of ZnO = 81g) Therefore Xg of zno _ 12.5g×81 ÷ 125 = 8.1 g of Zno. So 8.1g of Zno = yg of Zncl2 81g of Zno = 136
