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Agyeya
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Agyeya
Answers (1)
Solving after steve's step: (PQ/tan27°)^2 + (PQ/tan11°)^2 = 40^2 Take PQ^2 out as it is common to both: PQ^2(1/tan27^2 + 1/tan11^2)= 1600 PQ^2=1600/(1/tan27^2 + 1/tan11^2) PQ=√1600/(1/tan27^2 + 1/tan11^2) PQ=7.26( 3 significant figures)
