Thursday

April 17, 2014

April 17, 2014

Number of results: 113,458

**Algebra**

Can someone please help with this? Allen bought 20 stamps at the post office in 37¢ and 20¢ denominations. If the total cost of the stamps was $7.06, how many 37¢ stamps did Allen buy? A) 15 B) 16 C) 17 D) 18
*Sunday, November 25, 2007 at 9:57pm by Word Problem*

**Algebra**

x+y=7.06
*Sunday, November 25, 2007 at 9:57pm by Word Problem*

**Algebra**

37x+20y=7.06
*Sunday, November 25, 2007 at 9:57pm by Word Problem*

**Algebra**

x+y=20 and 37x + .20y = 7.06
*Sunday, November 25, 2007 at 9:57pm by Word Problem*

**Algebra**

Would the answer be D - 18 .37 stamps?
*Sunday, November 25, 2007 at 9:57pm by Word Problem*

**math**

One number is 12 more than another. The sum of the smaller number and twice the larger number is 39. Find the larger number. This is what I have so far: x+y+12=39
*Sunday, November 25, 2007 at 10:39pm by Word Problem*

**ryan**

You propose to build a space ship that allows the entire population of the United States (280 million) to leave earth. Your plans allocate an average space of 1,000(=10*10*10) cubic feet to each person. You space ship is going to have the shape of a sphere. The radius of you ...
*Friday, October 8, 2010 at 5:07pm by math word problem*

**algebra phyics word problem**

ok but this is in algebra mathword problem about physic
*Saturday, October 15, 2011 at 6:51pm by marko*

**Algebra Word Problem**

My question is already posted, name pj , school subject, Algebra Word Problem
*Sunday, November 16, 2008 at 1:23pm by pj*

**Algebra - word problem**

Your friend is taking an algebra class that began one week after ours. Explain to your friend how to graph linear inequalities with two variables
*Monday, November 30, 2009 at 5:21pm by shelia*

**Algebra Word Problem (1)**

Chris and Josh have received walkie-talkies for Christmas. If they leave from the same point at the same time, Chris walking north at 2.5 mph and Josh walking east at 3 mph, how long will they be able to tlak to each other if the range of the walkie talkies is 4 miles? Round ...
*Saturday, July 9, 2005 at 12:10am by GetYourLeash*

**another algebra word problem**

okay guys, just one more word problem. and i don't think this one has any typos in it: The perimeter of a rectangle is 27 cm and its area is 35 square centimeters. Find the length and the wide of the rectangle. i just need help getting it started... Ok P=27cm where P is the ...
*Tuesday, September 12, 2006 at 8:31pm by nicole*

**Word Problem- Algebra**

1. Multiply a number by 4, then multiply this product by 5, then you get 80 Whats the way to solve it, the equation. 2. Add 4 to a number, then subtract 5 from the sum, and you get 43 Whats the equation to solving that if anyone can answer either of those, that'd be great. 1. ...
*Saturday, January 20, 2007 at 11:16pm by Sam*

**ALGEBRA WORD PROBLEM! HELP!**

And if a length of a rectangle is 3 more than twice the width and the are is 90 cm squared than what are the dimensions of the rectangle? The width of the rectangle is 43.5 and the length of the rectangle is 87. All together when you add it up it will make 90 cm squared. If ...
*Tuesday, January 23, 2007 at 7:01pm by Judy*

**word problem!!! algebra**

at noon, a cargo van crosses an intersection at 30 mph. At 12:30 pm, a car crosses the same intersection traveling in the opposite direction. At 1 pm, the van and car are 54 miles apart. How fast is the car traveling? I know the answer is 48 mph, but can you set it up for me? ...
*Sunday, March 11, 2007 at 5:33pm by susan*

**algebra word problem**

A small company produces both dollhouses and sets of doll furniture. The dollhouses take 3 hours of labor to produce, and the furniture sets take 8 hours. The labor available is limited to 400 hours per week, and the total production capacity is 100 items per week. Existing ...
*Tuesday, May 1, 2007 at 11:36am by TAMMY*

**Algebra word problem**

I have no idea how to start this problem can some one explain to me am i suppose to divid 1/10 by 1/4 which i get 4 but i feel i am missing some thing am i am Fungicides account for 1/10 of the pesticides used in the United States. Insecticides account for 1/4 of all the ...
*Wednesday, May 9, 2007 at 11:39pm by Tom*

**Algebra word problem**

In 2004, the population of Mexico was 106.5 million. If Mexico's population continues to grow at an annual rate of 1.43%, then the population in 2015 will be 106.5 (1.0143)^11 million. a. find the predicted population in 2015 to the nearest tenth of a million people. b. With ...
*Monday, July 30, 2007 at 2:51pm by Nik*

**Algebra, word problem**

A small firm produces both AM and AM/FM car radios. The AM radios take 15 h to produce, and the AM/FM radios take 20 h. The number of production hours is limited to 300 h per week. The plantâ€™s capacity is limited to a total of 18 radios per week, and existing orders require ...
*Friday, September 14, 2007 at 9:13pm by Marinda*

**Algebra word problem**

please help me with the following: The value of a particular investment follows a pattern of exponential growth. In the year 2000, you invested money in a money market account. The value of your investment t years after 2000 is given by the exponential growth model a=3000e^0....
*Thursday, October 25, 2007 at 10:06pm by Soph.*

**Algebra word problem**

Set 3000e^0.053t = $5097 e^0.053t = 5097/3000 = 1.699 Take the natural log of both sides .053 t = 0.53 t = _?_ years
*Thursday, October 25, 2007 at 10:06pm by drwls*

**Algebra word problem**

I got 10 years, but my answer choices are: a. 2010, b.2011, c.2009, d. 2012. And I dont understand how you took the natural log of both sides?
*Thursday, October 25, 2007 at 10:06pm by Soph.*

**Algebra word problem**

You add t to the year 2000 in this case, so the answer is a. Taking the natural log (to base e) was in my case done with a hand calculator. The natural log of e^x is x.
*Thursday, October 25, 2007 at 10:06pm by drwls*

**Algebra Word Problem**

A rectangle's length is 8 cm more than three times it's width. If the perimeter is 128 cm, find the length and width. What is the equation for this?
*Monday, November 5, 2007 at 10:22pm by Matthew*

**Algebra Word Problem**

You need to sove two simultaneous equations. L = length W = width L = 3W + 8 2(L + W) = 128 Substitute 3W +8 for L in the last equation. 2[(3W+8)+ 2W] = 128 8W + 16 = 128 8W = 112 W = ? L = 3W +8 = ?
*Monday, November 5, 2007 at 10:22pm by drwls*

**Algebra Word Problem**

L + L + W + W = 128 L - 8 = 3W ================ Two equations. Two unknowns. Solve simultaneously.
*Monday, November 5, 2007 at 10:22pm by DrBob222*

**Math / Algebra Word Problem**

The Parkhursts used 160 yd of fencing to enclose a rectangular corral and to divide it into two parts by a fence parrallel to one of the shorter sides. Find the dimensions of the corral if its area is 1000 yd^2 Thank you!
*Thursday, December 6, 2007 at 5:12am by Ray*

**Math / Algebra Word Problem**

Call the width W Call the length L Then you know tow things: W * L = 1000 and 3 * W + 2 * L = 160 then L = W/1000 so 3*W + 2000/W = 160 or 3 * W^2 - 160 * W + 2000 = 0 Solve that quadratic with the quadratic equation. You get two results. One of them has a short side, W, ...
*Thursday, December 6, 2007 at 5:12am by Damon*

**Algebra Word Problem**

A rectangle has dimensions of 12x8inches. If a uniform border is added, then the new rectangle has twice the area of the old rectangle. a) Find the width of the border b) find the new dimensions of the rectangle
*Thursday, December 13, 2007 at 12:50am by Ray*

**Algebra Word Problem**

Call the border width w. The bordered rectangle dimensions are (12+w) x (8+w) Solve the equation (12+w)(8+w)= 2*12*8 = 192 96 + 20w + w^2 = 192 w^2 + 20w - 96 = 0 (w+24)(w-4) = 0 w = 4 or -24 Take the positive root for w. Add it to the length and the width for the new ...
*Thursday, December 13, 2007 at 12:50am by drwls*

**Algebra Word problem**

I don't know how to put in a square root symbol here so know that it is over h. The equation D=1.2 square root h gives the distance D in miles that a person can see to the horizon from a height h in feet. Solve for h. Do I find the square root of 1.2?
*Tuesday, January 29, 2008 at 9:25am by Marysvoice*

**Algebra Word problem**

yes.
*Tuesday, January 29, 2008 at 9:25am by depressed.*

**Algebra Word problem**

Ignore the previous answer. According to your formula, you find the square root of h (in feet) and multiply it by 1.2. The answer will be in miles. A more correct factor to use is 1.23.
*Tuesday, January 29, 2008 at 9:25am by drwls*

**Algebra Word problem**

To determine how far in miles we can see from a building of height h ft., we use d = sqrt[1.5h]. To determine the height of a building we can see from a distance d off shore, we use h = sqrt(r^2 + d^2) - r, r and d in feet. r = the radius of the earth in feet d = the distance ...
*Tuesday, January 29, 2008 at 9:25am by tchrwill*

**Algebra Word problem**

so- D/1.2=the square root h Long's Peak in the rocky mountains is 14,255 feet I need to get the number of miles 5280 or 2.7 miles? then divide that by 1.2 or 2.25 miles?
*Tuesday, January 29, 2008 at 9:25am by Marysvoice*

**Algebra Word problem**

In the case of Long's Peak, using the formula you have been given, take the sqrt of 14255, multiply it by 1.2, and you will have the answer in miles for the distance d that you can see to the horizon. I get 143 miles. That's about to the next state, if you are looking east (...
*Tuesday, January 29, 2008 at 9:25am by drwls*

**Algebra word problem**

A 30 inch TV set has a width of 24 inches. What is its height?
*Saturday, February 2, 2008 at 11:54am by Micah*

**Algebra word problem**

Use this formula for finding the height and width of a triangle when you know the hypotenuse. Let a = the height. a^2 + b^2 = c^2 a^2 + 24^2 = 30^2 a^2 + 576 = 900 a^2 = 324 a = ?
*Saturday, February 2, 2008 at 11:54am by Ms. Sue*

**Algebra word problem**

324 divided by sqrt is 18?
*Saturday, February 2, 2008 at 11:54am by Micah*

**Algebra word problem**

Yep! 18 is correct.
*Saturday, February 2, 2008 at 11:54am by Ms. Sue*

**Algebra word problem**

Thank you
*Saturday, February 2, 2008 at 11:54am by Micah*

**Algebra word problem**

You're welcome.
*Saturday, February 2, 2008 at 11:54am by Ms. Sue*

**algebra-word problem**

Flying to Kampala with a tailwind a plane averaged 158 km/h. On the return trip the plane only averaged 112 km/h while flying back into the same wind. Find the speed of the wind and the speed of the plane in still air. TIA
*Sunday, March 23, 2008 at 2:58pm by jen*

**algebra-word problem**

speed out = 158 = v+w speed back = 112 = v-w add the two equations 2 v = 270 v = 135 w = 158 - 135 = 23
*Sunday, March 23, 2008 at 2:58pm by Damon*

**College Algebra Word Problem**

I have been racking my head with this one and dont know how to approach it. The question is: A bank loaned out $64,000, part of it at the rate of 13% per year and the rest at a rate of 5% per year. If the interest recieved was $6000, how much was loaned at 13%. I know the ...
*Tuesday, September 23, 2008 at 9:33pm by Marlon*

**College Algebra Word Problem**

.13x + .05(64000-x)=6000 solve for x.
*Tuesday, September 23, 2008 at 9:33pm by bobpursley*

**College Algebra Word Problem**

Wrong formula for this. Let x = amount loaned at 13%. Then 64,000-x = amt loaned at 5%. 0.05x + 0.13(64,000-x) = 6000 solve for x. I get 35,000 @ 13% (and 29,000 @ 5%). Check my thinking. Check my work. At the end of the problem, multiply the amount at 13% and the amount at 5...
*Tuesday, September 23, 2008 at 9:33pm by DrBob222*

**College Algebra Word Problem**

Thank you so much, I feel confident that I can tackle this type of problem now.
*Tuesday, September 23, 2008 at 9:33pm by Marlon*

**college algebra word problem**

Lisa drove 8 miles to pick up her friend Laurie, and then drove 11 miles to a mall at a speed 15 mph faster. If Lisa'a total travel time was 24 minutes, what was her speed on the trip to pick up Laurie? Thank you!!
*Sunday, October 19, 2008 at 8:51pm by jenny*

**college algebra word problem**

Let x = speed for first 8 miles. Then x + 15 = speed for next 11 miles. ======================================== distance = rate x time solve for time = d/r For first 8 miles, time is t = 8/x For next 11 miles, time is t = 11/(x+15). If we add them we get 24 minutes which is 0...
*Sunday, October 19, 2008 at 8:51pm by DrBob222*

**college algebra word problem**

Wayne can do a job in 6 hours, while Susan can do the same job in 7 hours. How long would it take them to do the job if the worked together? Thank you!!
*Monday, October 20, 2008 at 5:01pm by jenny*

**college algebra word problem**

the rate for each is 1job/6hrs,or 1job/7hours timetogehter=1job/combined rate = 1/(1/6 + 1/7) go for it.
*Monday, October 20, 2008 at 5:01pm by bobpursley*

**college algebra word problem**

An open box is made from a square piece of material 24 inches on a side by cutting equal squares from the corners and turning up the sides. Write the Volume V of the box as a function of x. Recall that Volume is the product of length, width, and height. Thank you!
*Friday, October 24, 2008 at 10:58am by jenny*

**college algebra word problem**

let each side of the cut-out square be x in then isn't the base 24-2x by 24-2x ? and isn't the height of the box x ? take it from there.
*Friday, October 24, 2008 at 10:58am by Reiny*

**college algebra word problem**

V(x)= x(24-x)^2 ?
*Friday, October 24, 2008 at 10:58am by jenny*

**college algebra word problem**

Or V=1/3(24-2x)^2*x I'm confused as to how you came up with the base as 24-2x. Thanks for your help!
*Friday, October 24, 2008 at 10:58am by jenny*

**college algebra word problem**

draw a square with sides 24 in draw small square cut-outs at each of the corners, each of those sides is x inches long. Now didn't you take away x inches from each end?? so 24 - x -x or 24-2x
*Friday, October 24, 2008 at 10:58am by Reiny*

**college algebra word problem**

How did you come up with that equation ?? Your equation of V(x)= x(24-x)^2 in your first response should have been V(x)= x(24-2x)^2 ?
*Friday, October 24, 2008 at 10:58am by Reiny*

**college algebra word problem**

Okay, I just forgot the 2. Thank you so much for your help! Have a nice day!
*Friday, October 24, 2008 at 10:58am by jenny*

**algebra word problem**

Describe the values for x that may not be appropriate value even when they are defined by a function A function could, for example, indicate the amount of bone strength (y) in a living human body over time in years(x) . It would not make sense to look at negative years, ...
*Wednesday, October 29, 2008 at 10:42pm by PJ*

**Algebra Word Problem**

Peanuts are selling for $2 per pound, and cashews are selling for $5 per pound. How much of each type of nut would be needed to create 20lb. of a mixture that would sell for $2.75 pre puund? Use the variables, p and c, to setup a system of equations. Solve. p=numver of pounds ...
*Sunday, November 16, 2008 at 1:00pm by pj*

**Algebra Word Problem**

One equation would obviousy be p + c = 20 The other equation would be based upon the total cost. 20 lb at 2.75/per lb should cost $55. The same amount of money must equal the costs of the two ingredients, added together. 2 p + 5 c = 55. Solve those two equations for the answer...
*Sunday, November 16, 2008 at 1:00pm by drwls*

**Algebra word problem help**

The average walking speed R of people living in a city of population P,in thousands, is given by R=0.37InP+0.05, where R is in feet per second. a.) The population of Honolulu, Hawaii is 395,790. Find the average walking speed. b.) A city's average walking speed is 2.70 ft/sec...
*Friday, November 21, 2008 at 2:54pm by Shawn*

**Algebra word problem help**

a) is just button-pushing on a calculator I got a rate of 4.82 ft/s b) 2.7 = .37(lnP) + .05 2.65 = .37lnP lnP = 2.65/.37 = 7.162162 P = 1289.6 P = 1290
*Friday, November 21, 2008 at 2:54pm by Reiny*

**Algebra word problem help**

Thank you. I was able to get the same answers.
*Friday, November 21, 2008 at 2:54pm by Shawn*

**College Algebra Word Problem**

A rectangular dog pen is to be made to enclose an area of 625 sq. ft. The pen is to be divided into 2 equal sections by a section of the fence. Find the dimensions of the pen that will require the least amount of fencing material. Thank you!
*Monday, December 1, 2008 at 6:48pm by Jenny*

**College Algebra Word Problem**

Calculus I assume? Length*Width= 625 fencelenght= 2L + 3W W= 625/L fencelength= 2L+ 3*625/L d fl/dl= 0=2 -3*625/L^2 or L= sqrt (3/2 * 625) and W= 625/sqrt (3/2 625) Now, if you are in algebra, I dont see any way of working this except graphing fencelength=2L -325/L and looking...
*Monday, December 1, 2008 at 6:48pm by bobpursley*

**algebra word problem**

The mass of Saturn is about 5.688 10^23 metric tons. The mass of the sun is about 1.998 x 10^27 metric tons. About how many times the mass of Saturn is the mass of the sun? Give answer in scientific notation. The mass of the sun is about ----- times the mass of Saturn. COULD ...
*Thursday, December 4, 2008 at 9:43pm by pj*

**algebra word problem**

Divide the mass of the sun by the mass of saturn. (1.998 x 10^27)/(5.688 x 10^23). What do you get when you do this on your calculator?
*Thursday, December 4, 2008 at 9:43pm by DanH*

** algebra word problem**

I NEED HELP PLEASE!!!!!!!!! A rectangular table is five times as long as it is wide. If the area is 50 ft.^2, find the length and the width of the table. The width of the table is______ ft. The lenght of the table is ______ ft.
*Tuesday, December 9, 2008 at 7:38pm by pj*

** algebra word problem**

x 5x
*Tuesday, December 9, 2008 at 7:38pm by Reiny*

**Algebra Word Problem**

I REALLY NEED YOUR HELP !!!!!!! Suppose it takes 3 days for a space vehicle to travel from Earth to the moon. About how long would it take the same vehichle traveling at the same speed to reach Venus? Closest Distance From Earth to: Moon 240,000mi Venus 26,000,000mi the space ...
*Saturday, December 13, 2008 at 5:30pm by pj*

**Algebra Word Problem**

Why not just set up a proportion. (3days/240,000 miles) = (?days/26,000,000 miles)
*Saturday, December 13, 2008 at 5:30pm by DrBob222*

**Algebra Word Problem**

COULD SOMEONE PLEASE HELP ME WITH THIS !!!!!!!!!! The base of a triangle is 3cm greater than the height. The area is 44cm^2. Find the height and length of the base. The height of the triangle is_______ cm The base of the traingle is_______cm
*Sunday, December 14, 2008 at 4:49pm by pj*

**Algebra Word Problem**

(1/2) b h = 44 so b h = 88 but b = h + 3 so (h+3)h = 88 h^2 + 3 h - 88 = 0 (h-8)(h+11) = 0 h = 8 take it from there
*Sunday, December 14, 2008 at 4:49pm by Damon*

**Algebra Word Problem**

I NEED HELP PLEASE!!!!!!!!!! Elena bicycles 7 km/h faster than Dennis. In the same time it takes Dennis to bicycle 60km, Elena can bicycle 81km. How fast does each bicyclist travel. Dennis travel_____ km/h Elena travel ______ km/h
*Thursday, January 8, 2009 at 8:22pm by pj*

**Algebra Word Problem**

let Dennis' rate be x km/h let Elena's rate be x+7 km/h time taken by Dennis = 60/x time taken by Elena = 81/(x+7) but their times are equal, so 60/x = 81/(x+7) cross-multiply and solve for x then find x+7 for Elena's rate
*Thursday, January 8, 2009 at 8:22pm by Reiny*

**College Algebra Word Problem**

0.05x + 0.13(64,000-x) = 6000 this is incorrect.. since you said that x is the amount of money loaned at 13% the equation should be; 0.13x + .05(64000-x)=6000 your answer though is correct 35K @ 13% and 29K @ 5%
*Tuesday, September 23, 2008 at 9:33pm by ryan*

**Intermediate Algebra Word Problem**

A river's current is 4mph. A boat travels 48 miles downstream in the same time it travels 24 miles upstream. Find the speed of the boat. A) What does the variable stand for? x stands for the speed of the boat. B) Write the equation. 24/x - 4 = 48/x + 4 C) Solve. 24/x - 4 = 48/...
*Wednesday, February 11, 2009 at 8:57am by Jennifer*

**Intermediate Algebra Word Problem**

Yes, it is correct. The upstream speed relative to land (8 mph) is half the downstream speed (16 mph), as required.
*Wednesday, February 11, 2009 at 8:57am by drwls*

**Intermediate Algebra Word Problem**

Thanks
*Wednesday, February 11, 2009 at 8:57am by Jennifer*

**Intermediate Algebra Word Problem**

A map's key indicates that 3/4 of an inch represents 60 miles. How many miles does 2 1/4 inches represent? in/mi 3/4 / 60 = 2 1/4 / x 3/4x = 60(2 1/4) .75x = 60 (2.25) .75x/.75x = 135/.75 x = 18mi. Is this correct?
*Thursday, February 12, 2009 at 5:31pm by Jennifer*

**Intermediate Algebra Word Problem**

Thanks!
*Thursday, February 12, 2009 at 5:31pm by Jennifer*

**Intermediate Algebra Word Problem**

Wrong! How can 2 1/4 inches represent less than 3/4 inch? Please try again -- watching your decimal places.
*Thursday, February 12, 2009 at 5:31pm by Ms. Sue*

**Intermediate Algebra Word Problem**

answer is 180 mi.
*Thursday, February 12, 2009 at 5:31pm by Jennifer*

**Intermediate Algebra Word Problem**

Right! :-)
*Thursday, February 12, 2009 at 5:31pm by Ms. Sue*

**Intermediate Algebra Word Problem**

Thank You!
*Thursday, February 12, 2009 at 5:31pm by Jennifer*

** Algebra Word Problem**

COULD SOMEONE PLEASE HELP ME WITH THIS PROBLEM!!!!!!!! Television Sets. What does it mean to refer to a 20-in TV Set? Such units refer to the diagonal of the screen. A 20-in TV Set also has a width of 16 inches. What is its height what is the height of a 20-in TV? ______ inches.
*Saturday, February 14, 2009 at 2:27pm by pj*

** Algebra Word Problem**

diagonal is the hypotenuse h^2 + 16^2 = 20^2 h^2 + 256 = 400 h^2 = 144 h = 12
*Saturday, February 14, 2009 at 2:27pm by Damon*

**college algebra word problem**

rachel allows herself 1 hour to reach a sales appt 50 miles away. after she has driven 30 miles, she realizes that she must increase her speed by 15mph in order to get there on time. what was her speed for the first 30 miles?
*Tuesday, February 17, 2009 at 6:56am by john*

**college algebra word problem**

let her speed for the first leg be x mph let her speed for the second leg be x+15 mph so her time for the first leg is 30/x her time for the second leg is 20/(x+15) but 30/x + 20/(x+15) = 1 multiplying both sides by x(x+15) and simplifying I got x^2 + 35x - 450 = 0 (x+10)(x-45...
*Tuesday, February 17, 2009 at 6:56am by Reiny*

**college algebra word problem**

But wouldnt that actually factor into (x-10)(x+45) which would imply that the positive value for x is actually 10. plugging that back into the problem, that means she can go 30 miles at 10 miles per hour and 20 miles at 25 miles per hour to arrive at 50 miles in an hour? how ...
*Tuesday, February 17, 2009 at 6:56am by john*

**college algebra word problem**

A goldsmith has two alloys that are different purities of gold. The first is 3/4 pure and the second is 5/12 pure. How many ounces of each should be melted and mixed in order to obtain a 6 oz mixture that is 2/3 pure gold?
*Wednesday, February 25, 2009 at 6:37pm by megan*

**college algebra word problem**

solve (3/4)x + (5/12)(6-x) = (2/3)(6) ,each term times 12 9x + 5(6-x) = 48 etc
*Wednesday, February 25, 2009 at 6:37pm by Reiny*

**college algebra word problem**

Since there are different quantities of each purity wouldn't there be an x and a y in the equation instead of both being x?
*Wednesday, February 25, 2009 at 6:37pm by amy*

**college algebra word problem**

Ok, x + y = 6 ----> y = 6-x (3/4)x + (5/12)y = (2/3)(6) sub in the value of y mmmhhh!
*Wednesday, February 25, 2009 at 6:37pm by Reiny*

**college algebra word problem**

oooh. okay! thanks!
*Wednesday, February 25, 2009 at 6:37pm by amy*

**college algebra word problem**

12
*Tuesday, February 17, 2009 at 6:56am by Anonymous*

**algebra interest word problem**

Solve the problem. Roberto invested some money at 7%, and then invested $2000 more than twice this amount at 11%. His total annual income from the two investments was $3990. How much was invested at 11%?
*Sunday, March 8, 2009 at 12:44pm by mark*

**algebra interest word problem**

see my answer to your re-post
*Sunday, March 8, 2009 at 12:44pm by economyst*

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