Sunday

April 20, 2014

April 20, 2014

Number of results: 98

**Trignometry**

yes I have.
*Monday, April 12, 2010 at 7:32pm by sarah*

**trig**

graphs of trignometry
*Saturday, November 20, 2010 at 6:07am by zainab*

**trignometry**

y = sin 8x + 3 period ?
*Friday, July 1, 2011 at 5:27pm by Anonymous*

**Trignometry questions EASY HELP**

I dont know
*Wednesday, June 29, 2011 at 6:03pm by Chandu*

**Trignometry**

Ok i ll do research on it. Thank you very much for your help.
*Monday, July 1, 2013 at 11:02pm by hello*

**Trignometry questions EASY HELP**

PLEASE HELP ME OUTTTTTTTTTTTTTTTTTTT
*Wednesday, June 29, 2011 at 6:03pm by kalakalikalakali*

**trignometry**

how to find derivative of (2+cotx)/(7-tanx)
*Friday, October 28, 2011 at 2:26am by Xie*

**math**

how to find points of continuity in trignometry
*Wednesday, January 18, 2012 at 11:51pm by saphire*

**trignometry**

tanx=1/1,tany=1/3 then cos2x=sin2y
*Friday, December 28, 2012 at 4:09am by gopi*

**trignometry**

find the exact value of sec theta?
*Thursday, February 14, 2008 at 1:00pm by b*

**trignometry**

prove: sin(a+b)/cosacosb=tana+tanb
*Tuesday, March 9, 2010 at 2:06am by Sarah Fuller*

**maths-trignometry**

The value of (secpi/7)+(sec3pi/7)+(sec5pi/7) is
*Wednesday, March 13, 2013 at 10:39am by anoynomous*

**maths-trignometry**

The value of (secpi/7)+(sec3pi/7)+(sec5pi/7) is
*Wednesday, March 13, 2013 at 12:38pm by anoynomous*

**maths-trignometry**

The value of (secpi/7)+(sec3pi/7)+(sec5pi/7) is
*Thursday, March 14, 2013 at 4:00am by anoynomous*

**Trignometry**

well what are sin,cos of π/3? Just plug them in.
*Tuesday, July 2, 2013 at 11:06am by Steve*

**trignometry**

these nonsense posts won't get you much help, and just waste time.
*Friday, September 27, 2013 at 5:31pm by Steve*

**trignometry**

if 12 cot^3 A - 31cosecA+32=0 thend find SinA ?
*Wednesday, March 31, 2010 at 11:51am by pramod*

**trignometry**

Solve sin(2è) < cos(è). Give an exact answer.
*Sunday, April 19, 2009 at 3:38pm by m*

**mathematics trignometry**

if tanA=ntanX sinA=msinX then prove that cos^2A=(m^2-1)/(n^2-1)
*Sunday, March 20, 2011 at 12:01pm by Anonymous*

**maths-TRIGNOMETRY**

show that: 2^5 cos^2a sin^4a=cos6a-2cos4a- cos2a + 2
*Thursday, February 21, 2013 at 11:35am by Anonymous*

**maths-trignometry**

without using calculator, find the Value of following is cosec(-38888)
*Friday, June 21, 2013 at 10:11am by anoynomous*

**trignometry**

how to find the value of any standard angle ??? for example sin 60*??? without using table
*Thursday, December 6, 2012 at 8:15am by suraj*

**maths-trignometry(urgent)**

without using calculator, find the Value of following is cosec(-38888)
*Friday, June 21, 2013 at 12:50pm by anoynomous*

**trignometry**

,linytron reduce amount of gas tons chase direct deposit. Deactivate ac.done
*Friday, September 27, 2013 at 5:31pm by Nasanasa*

**trignometry**

,linytron reduce amount of gas tons chase direct deposit. Deactivate ac.done
*Friday, September 27, 2013 at 5:51pm by Nasanasa*

**algebra2/trignometry**

in right triangle PQR,Q=90DEGREE,PQ=4 AND PR=7 WHAT IS ANGLE R TO THE NEARST TENTH OF A DEGREE
*Wednesday, April 27, 2011 at 9:14pm by mathew*

**Trignometry**

How can I find the exact value of 4cos(7ð/4)-2sin(ð/3) without using a calculator (show work)?
*Tuesday, January 31, 2012 at 10:31pm by Anonymous*

**maths-trignometry**

I saw this before, I know the answer is exactly 4 , but at the moment I cannot see how to show that. Been messing around with it for a while,
*Thursday, March 14, 2013 at 4:00am by Reiny*

**Trignometry**

ABCD is a square where M and N are midpoints of AD and CD, respectively. If sin∠MBN=a/b, where a and b are coprime positive integers, what is the value of a+b?
*Monday, March 18, 2013 at 3:39am by Stranger*

**Trignometry**

that weird symbol is suppose to be pi (3.14...) I punched in the alt code but it seems after I submitted the question it turned out like this
*Tuesday, January 31, 2012 at 10:31pm by Anonymous*

**algebra/trignometry**

Verify that each trigonometric equation is an identity tan^2+1/sec Î± =sec Î±
*Wednesday, July 13, 2011 at 9:18am by maria*

**trignometry**

Prove That 2sin^pi/6 + cosec^7pi/6cos^pi/3 = 3/2
*Wednesday, June 15, 2011 at 3:44am by Anonymous*

**11th grade Maths**

Can someone help me understand what that even function & odd function is, in trignometry
*Sunday, August 8, 2010 at 8:49am by Aishwarya*

**algebra/trignometry**

if angle x is 30 degrees and side yz is 10ft, how long is side xy?
*Wednesday, June 29, 2011 at 11:52pm by maria*

**Trignometry**

Find the missing parts of the triangle. C = 124.2° a = 6.90 km b = 11.60 km
*Sunday, June 30, 2013 at 1:25pm by jolly*

**Trignometry**

Write the complex number in the form a=bi √(3)(cos π/3 + isin π/3)
*Tuesday, July 2, 2013 at 11:06am by yes*

**trignometry**

1. if sin 2A = Psin2B, prove that tan(A+B)/tan(A-B)=P+1/P-1.
*Monday, June 13, 2011 at 6:26am by seema*

**algebra/trignometry**

x=-16 ,y=17 when x squared -4y squared
*Wednesday, July 13, 2011 at 9:18am by kathy*

**Calculus(Pre)**

What is linear speed and angular speed (In Trignometry)
*Thursday, November 17, 2011 at 4:43pm by Professor Calculus*

**pre algebra**

This is not trignometry. What kind of class are you taking that doesn't give you a text book or online text materials????
*Sunday, June 20, 2010 at 9:38pm by Ms. Sue*

**mathematics trignometry**

if sina, cosa, tana are in geometric progression then prove that cot^6a-cot^2a=1
*Sunday, March 20, 2011 at 11:49am by Anonymous*

**Trignometry**

Unless these are right triangles, more information is needed to answer your questions. Is there a figure that is supposed to go with these questions?
*Saturday, September 11, 2010 at 4:22am by drwls*

**Trignometry**

solve the triangle. B=77.0deg b=13.95 a=20.6 I got A=38.5deg C=64.5deg c=34.55
*Tuesday, July 2, 2013 at 11:01am by yes*

**trignometry**

Hora aderat briligi. Nunc et Slythia Tova Plurima gyrabant gymbolitare vabo; Et Borogovorum mimzebant undique formae, Momiferique omnes exgrabure Rathi.
*Friday, September 27, 2013 at 5:51pm by Steve*

**Trignometry**

sinA/a = sinB/b sinA = sin77°/13.95 * 20.6 sinA = 1.43 BZZZT!
*Tuesday, July 2, 2013 at 11:01am by Steve*

**Physics**

I assume you have had some trignometry. x component=10+10cos30 + 10cos(70+30) go thru that and make certain you understand it. I will be happy to check your y component.
*Thursday, July 21, 2011 at 2:34pm by bobpursley*

**Trignometry**

on the paper all the info is given is : Given Trianlge ABC, and i think all of em are right triangles...
*Saturday, September 11, 2010 at 4:22am by Anonymous*

**Trignometry**

Have you learned the expansion formulas for sin(A-B) and cos(A-B) that is, sin(A-B) = sinAcosB - cosAsinB I will have to know to determine which approach to show you
*Monday, April 12, 2010 at 7:32pm by Reiny*

**Trignometry**

domain of arcsin is [-1,1] So, we want -1 <= x^2-35 <= 1 34 <= x^2 <= 36 now you can figure M and m easily
*Monday, March 18, 2013 at 3:29am by Steve*

**Trignometry**

If two angles are supplementary, then their sines are equal. Explain why. What about the cosines of supplementary angles? If you are not sure, calculate some examples.
*Monday, April 12, 2010 at 7:32pm by sarah*

**trignometry**

x = pi/4, so cos2x = 0 since y ≠ pi/2, sin2y ≠ 0 I suspect a typo somewhere
*Friday, December 28, 2012 at 4:09am by Steve*

**correction - Trignometry questions EASY HELP**

in #2 I had my formula backwards should say cos 2A = 2cos^2 A - 1 cos 30 = 2cos^2 15 - 1
*Wednesday, June 29, 2011 at 6:03pm by Reiny*

**maths-trignometry**

Prove that tan-1 (1/7) + tan-1 (1/13) = tan-1(2/9)
*Saturday, March 16, 2013 at 2:41pm by anoynomous*

**trignometry**

show that cos2x=1-tan^ 2 x /1+tan^2x=2cos^2x-1
*Saturday, October 6, 2012 at 12:20pm by help me out it's urgent*

**Trignometry**

Can you please help me prove that ((1-cosx)/(1+cosx))=(cscx-cotx)^2? I can only do work on one side to prove that its end result is equal to the other side.
*Monday, December 16, 2013 at 7:50pm by Potterhead*

**Trignometry**

Let m and M be the minimum and maximum values of the domain of f(x)=sin^−1(x2−35), respectively. What is the value of M−m? sin^-1 is sin inverse
*Monday, March 18, 2013 at 3:29am by Stranger*

**Trignometry**

use the law of cosines to start and find side c. Then use the law of sines to find remaining angles.
*Sunday, June 30, 2013 at 1:25pm by Joe*

**algebra2/trignometry**

(PQ)^2 + (QR)^2 = (PR)^2, 4^2 + (QR)^2 = 7^2, (QR)^2 = 7^2 - 4^2 = 49 - 16 = 33, QR = 5.7. cosR = QR/PR = 5.7/7 = 0.8207. R = 34.8 deg.
*Wednesday, April 27, 2011 at 9:14pm by Henry*

**Trignometry**

Suppose the ends of the cylindrical storage tank in the figure arc circles of radius 3 ft and the cylinder is 20 ft long. Determine the volume of the oil in the tank to the nearest cubic foot if the rod shows a depth of 2 ft.
*Friday, March 29, 2013 at 3:10pm by CiCi*

**physics**

Use trignometry to compute how much higher he is at the 35 degree angular position that at the bottom of the swing. Call that distance h. You will need to subtract a cosine term from the length to get h. This is something you should be able to do. Then use conservation of ...
*Wednesday, November 11, 2009 at 9:27am by drwls*

**Trignometry**

A car is moving at a rate of 55 mph and the diameter of its wheels is 2 feet. A) Find the number of revolutions per minute the wheels are rotating. B) Find the angular speed of the wheels in radians per minutes.
*Tuesday, February 12, 2013 at 10:57pm by David*

**Trignometry**

Solve the equation. Express your answer in trigonometric form. x^5-11=0 I know the answer is: 11^1/5(cos α + i sin α) for α = 0°, 72°, 144°, 216°, 288°. But I don't know where to even start working on this problem.
*Monday, July 1, 2013 at 11:02pm by hello*

**trignometry**

In the right triangle shown below, the length of AB is 8 units, ¡ÏA measures 60¡ã, sin 60¡ã ¡Ö 0.866, cos 60¡ã ¡Ö 0.5, and tan 60¡ã ¡Ö 1.73. Approximately how many units long is BC , to the nearest hundredth of a unit? A. 4.00
*Wednesday, April 24, 2013 at 11:56pm by gt*

**trignometry**

In the right triangle shown below, the length of AB is 8 units, ¡ÏA measures 60¡ã, sin 60¡ã ¡Ö 0.866, cos 60¡ã ¡Ö 0.5, and tan 60¡ã ¡Ö 1.73. Approximately how many units long is BC , to the nearest hundredth of a unit? A. 4.00
*Wednesday, April 24, 2013 at 11:57pm by gt*

**Trignometry**

An isosceles triangle has two sides of length w that make a 2á-degree angle. Write down two different formulas for the area of this triangle, in terms of w and á (Greek “alpha”). By equating the formulas, discover a relation involving sin 2á, siná, and cosá.
*Monday, April 12, 2010 at 7:25pm by Lydia*

**Trignometry**

The angles in triangle ABC satisfy 6sin∠A=3√(3)sin∠B=2√(2)sin∠C. If sin^2∠A=a/b, where a and b are coprime positive integers, what is the value of a+b?
*Monday, March 18, 2013 at 3:27am by Stranger*

**trignometry**

Your expression makes no sense We use the ^ symbol as an exponent sign. so your 2 sin^π/6 would be 2(sin)^(π/6) which is meaningless if you simply meant: 2 sin(π/6) + cosec(7π/6)cos(π/3) that would be 2(1/2) + (-2)(1/2) = 0 retype your problem.
*Wednesday, June 15, 2011 at 3:44am by Reiny*

**maths-trignometry(urgent)**

got me. can't think of a trick that will reduce that number (degrees or radians!) without using a calculator. I can tell you right off that no trig function of a rational number of radians will come out to an easy value. As for degrees, well -38888 is equivalent to -8, but I ...
*Friday, June 21, 2013 at 12:50pm by Steve*

**Trignometry**

If we let x = ∠MBN and y=∠ABM=∠NBC, then x+2y = pi/2 sin x = sin(pi/2-2y) = cos 2y = 1-2sin^2 y Now, siny = 1/√5, so sinx = 1 - 2(1/5) = 3/5 a+b=8
*Monday, March 18, 2013 at 3:39am by Steve*

**trignometry**

if alpha and beta are 2 different values of θ lying between 0 and 2π which satisfy the equation 6cosθ+8 sinθ=9 find the value of sin alpha + beta.i want the answer by quadratic method. can u help solving sum by that method
*Saturday, June 11, 2011 at 11:14am by usha*

**Trignometry questions EASY HELP**

1. Which is a solution to the equation below? sin2xsecx=1 2. What is the exact value of cos15 degrees? 3. Which expression is equivalent to the expression below? cos^2 xsin^2? 4. What is the exact value of cos2theta? one side is 8 and the other is 15 5. The angle x lies in ...
*Wednesday, June 29, 2011 at 6:03pm by kalakalikalakali*

**Trignometry questions EASY HELP**

This assignment is obviously meant to study the double angle formulas 1. sin 2x secx = 1 2sinxcosx(1/cosx) = 1 sinx = 1/2 so x is in I or II x = 30 or 150 degrees or pi/6, 5pi/6 radians 2. use cos2A = 1 - 2cos^2 A cos 30 = 1 - 2cos^2 A you should know cos 30, sub it in and ...
*Wednesday, June 29, 2011 at 6:03pm by Reiny*

**Trignometry**

Let θ be the angle between the x-axis and the line connecting the origin O(0,0) and the point P(−3,−4), where 180∘<θ<270∘. Given that sinθ+cosθ+tanθ=−a/b, where a and b are coprime positive integers. What is the ...
*Saturday, March 16, 2013 at 8:45am by Trigno with cordinates*

**trignometry**

the derivative of cot x = -csc^2 x the derivative of tan x = sec^2 x .. and you do this: [ low*d(high) - high*d(low) ] / (low)^2 where high = numerator low = denominator d(high) and d(low) = respective derivatives
*Friday, October 28, 2011 at 2:26am by Jai*

**trignometry**

use degree measure for your answers. use a calculator and round the results to one decimal place for (c) and (d) (a) in triangle ABC, sin B = square root of 2 all over 2. What are the possible values for angle B? my thought: since sin is positive in the first and second ...
*Tuesday, November 28, 2006 at 12:14am by tracy*

**mathematics trignometry**

prove that the following are identity 1. (cotA+cosecA-1)/(cotA-cosecA+1)=cosecA+cotA 2. (sinA-cosA+1)/(sinA+cosA-1)= 1/(secA-tanA)
*Sunday, March 20, 2011 at 11:55am by Anonymous*

**Trignometry**

LS = (1-cosx)/(1+cosx) = (1-cosx)/(1+cosx) * (1-cosx)/(1-cosx) = (1-cosx)^2 /(1 - cos^2 x) = (1-cosx)^2 /sin^2 x = ( (1-cosx)/sinx )^2 = (1/sinx - cosx/sinx)^2 = (cscx - cotx)^2 = RS
*Monday, December 16, 2013 at 7:50pm by Reiny*

**algebra/trignometry**

Please check with your previous post before re-posting the same question. http://www.jiskha.com/display.cgi?id=1310559328
*Wednesday, July 13, 2011 at 9:18am by Reiny*

**trignometry**

make yourself a sketch of the 30-60-90 ° and the 45-45-90 ° right angled triangles the ratios of those sides are (in the same order) 1--√3--2 and 1--1--√2 so sin30 = 1/2 --- csc30 = 2 cos30 = √3/2 --- sec30 = 2/√3 tan30 = 1/√3 ----cot 30 = √...
*Thursday, December 6, 2012 at 8:15am by Reiny*

**Math trignometry**

how can you condense these cos^3x* cos2x^2 cos^3x+ cos2x^2 cos^3x- cos2x^2 Thanks a lot :)
*Sunday, January 23, 2011 at 6:21pm by Sabrina*

**Trignometry**

then take sin(180-x) , where we know x and 180-x are supplementary = sin180cosx - cos180sinx = 0 - (-1)sinx = sinx so sinx = sin(180-x) now for the second cos(180-x) = cos180cosx + sin180sinx = (-1)cosx + 0 = - cosx and cos(180-x) = -cosx
*Monday, April 12, 2010 at 7:32pm by Reiny*

**algebra/trignometry**

Draw a triangle. Label the angles x, y, and z. Label what are given. Determine whether what you have is SOH, CAH, or TOA. http://www.mathsisfun.com/algebra/sohcahtoa.html
*Wednesday, June 29, 2011 at 11:52pm by TutorCat*

**Trignometry**

Given Triangle ABC: I think there are suppose to be right triangles... 1) If <A = 30º, and c = 20, find a, b, and <B 2) If a = 10 and b = 14, find c, <A, and <B 3) If a = 6 and <B = 53º, find b, c, and <A 4) If c = 13 and b = 12, find a, <A, and <B 5) ...
*Saturday, September 11, 2010 at 6:52pm by Anonymous*

**trignometry**

cos 2x = cos(x+x) = cosxcosx - sinxsinx = cos^2 x - sin^2 x = cos^2 x - (1 - cos^2 x) = 2 cos^2 x - 1, the last part of your equation. all we need it to look at now is the middle part of (1 - tan^2 x)/(1 + tan^2 x) , notice the necessary brackets = (1 - sin^2 x/cos^2 x)/(1 + ...
*Saturday, October 6, 2012 at 12:20pm by Reiny*

**Trignometry**

so the radius is 1 ft and the circumference is 2π 55 mph = 55(5280)/60 ft/min = 4840 ft/min so rotations per min = 4840/2π = 770.31 since 1 rotation is 2π radians angular speed = 4840/(2π) * 2π = 4840 radians/min
*Tuesday, February 12, 2013 at 10:57pm by Reiny*

**Trignometry**

I'm assuming all rt triangles. 1. Given: A = 30, c = 20. a = csinA = 20sin30 = 10, b = ccosA = 20cos30 = 17.3, B = 90 - A = 90 - 30 = 60. 2. Given: a = 10, b = 14. c^2 = a^2 + b^2 = 10^2 + 14^2 = 100 + 196 = 296, c = sqrt(296) = 17.2 tanA = a/b = 10/14 = 0.7143, A = 35.5, B = ...
*Saturday, September 11, 2010 at 6:52pm by Henry*

**trignometry**

Since you posted this twice, I think you realized that the symbols did not come out like you intended. I think you meant this: AB = 8, angle A = 60° then you are given sin60° = .866 cos60° = .5 tan60° = 1.73 the problem is that we don't know where the 90° angle is, could be at...
*Wednesday, April 24, 2013 at 11:57pm by Reiny*

**Trignometry**

assuming the rod lies along a diameter of the circle, you need to find the area of a circular segment, knowing its height and the circle's radius. Draw a diagram. If the depth is d, then the central angle subtending the surface of the oil can be found using cos(θ/2) = (r-...
*Friday, March 29, 2013 at 3:10pm by Steve*

**trignometry**

Oh well, if you do not like WLS' cool method then cos T = sqrt(1 - sin^2 T) 6 sqrt(1 -sin^2 T) + 8 sin T = 9 let sin T = x 6 sqrt(1-x^2) + 8 x = 9 6 sqrt (1-x^2) = 9-8x 36 (1-x^2) = 81 - 144x + 64 x^2 36 -36 x^2 = 81 - 144x + 64 x^2 100 x^2 -144 x + 45 = 0 x = [ 144 +/- sqrt (...
*Saturday, June 11, 2011 at 11:14am by Damon*

**Trignometry**

For the whole triangle Area = (1/2)(w)(w)sin 2a = (1/2)w^2sin 2a draw in an altitude h, bisecting the angle 2a because we have an isosceles triangle Area of triangle = (1/2)hwsin a + (1/2)whsina = whsin a but cos a = h/w h = wcos a then whsin a = w(wcos a)sin a = w^2sin a cos ...
*Monday, April 12, 2010 at 7:25pm by Reiny*

**Trignometry**

1) If <A = 30º, and c = 20, find a, b, and <B 2) If a = 10 and b = 14, find c, <A, and <B 3) If a = 6 and <B = 53º, find b, c, and <A 4) If c = 13 and b = 12, find a, <A, and <B 5) If <A = 20º and b = 10, find <B, a and c 6) If c = 30 and <A = ...
*Saturday, September 11, 2010 at 4:22am by Anonymous*

**Trignometry pls help**

1. The radius of the circumscribed circle of the triangle ABC is 15 cm. Given that B is a 49-degree angle, find the length of side AC. 2. The radius of the circumscribed circle of the triangle ABC is r cm. Given that B is a â-degree angle, find the length of side AC, in terms ...
*Sunday, April 11, 2010 at 11:41pm by Sally K*

**maths-trignometry**

let tanA = 1/7 and tanB = 1/13 then tan(A+B) = (tanA + tanB)/( 1 - tanAtanB) = (1/7 + 1/13)/(1 - (1/7)(1/13) ) = (20/91) / (90/91) = 20/90 = 2/9 and if we let tanC = 2/9 then A + B = C thus tan^-1 (1/7) + tan^-1 (1/13) = tan^-1 (2/9) check with your calculator take 2nd Tan (1/...
*Saturday, March 16, 2013 at 2:41pm by Reiny*

**maths-TRIGNOMETRY**

1/32(cos6a-cos2a-2cos4a+2) let us find the value of cos6a-cos2a-2cos4a+2 by applying the formula cos c-cos d = 2sin(c+d/2)sin(d-c/2) =2sin4a(sin(-2a)-2cos4a+2 =-2sin4asin2a-2cos4a+2 =2(1-cos4a-sin4asin2a) =2(cos^2(2a)+sin^2(2a)-(cos^2(2a)-sin^2(2a))-2sin2acos2a(sin2a) (since ...
*Thursday, February 21, 2013 at 11:35am by Venkatesh*

**Trignometry**

Huh? You have all the answers! If you let r = 11^(1/5), the numbers are r cis 0° r cis 72° ... The n * (cosθ + i sinθ) is the trigonometric or polar form. a + bi is the complex or rectangular form. Hmmm. I see that you don't know how to arrive at the answers. Well, ...
*Monday, July 1, 2013 at 11:02pm by Steve*

**trignometry**

sin(a+b)/cos(a)cos(b) = = (sin(a)cos(b)+cos(a)sin(b))/cos(a)cos(b) = sin(a)cos(b)/(cos(a)cos(b) + cos(a)sin(b)/(cos(a)cos(b) = sin(a)/cos(a) + sin(b)/cos(b) = tan(a) + tan(b)
*Tuesday, March 9, 2010 at 2:06am by FredR*

**Science / Geography**

Losing Your Bearings 1. Begin journey at 40 degrees N by 77 degrees W. 2. Travel 4200 miles with a compass bearing of 130 degrees. 3. Travel 2800 miles with a compass bearing of 180 degrees. 4. Travel 5250 miles with a compass bearing of 90 degrees. 5. Travel 1750 miles with a...
*Saturday, October 7, 2006 at 9:18pm by Suzanne*

**trigonometric functions**

im compeletely lost with the trigonometric functions...can anyone explain clearly to me? Are you lost on the definitions?...where is the problem. You need to be able to draw and label all the parts of a triangle, the hypotenuse and legs. Then be able to define sine, cosine, ...
*Thursday, September 14, 2006 at 6:51pm by Katrina*

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