Friday

April 18, 2014

April 18, 2014

Number of results: 8,048

**Physics**

Static Friction Coefficient = Cfs For of Static Friction = Fs Normal Force = Fn Centripetal Force = Fc mass = m radius = r speed = v period of time = T Fs = Cfs * Fn so Cfs = Fs/Fn Fc = Fs and since Fs = mv^2/r Cfs = Fs/Fn = mv^2/r*Fn v = 2πr/T and Fn = mg so.... mv^2 (2...
*Monday, February 20, 2012 at 4:12pm by Erica*

**PHYSICS HELP PLEASE !!!!!**

A mass of 17 kg lies on a horizontal surface with a coefficient of static friction of 0.54 and a coefficient of kinetic friction of 0.22. If a force, F, is applied parallel to the surface (+x direction if you prefer), what is the magnitude that F needs to be to begin to move ...
*Tuesday, October 25, 2011 at 10:08pm by Amanda *

**PHYSICS PLEASE HELP !!!!!**

A mass of 30 kg lies on a horizontal surface with a coefficient of static friction of 0.72 and a coefficient of kinetic friction of 0.31. If a force of 25.1 Newtons is applied parallel to the surface (+x direction if you prefer), what is the magnitude of the acceleration of ...
*Tuesday, October 25, 2011 at 10:16pm by Amanda *

**physics**

Find the coefficient of static and kinetic friction of a block on a table surface. The mass of the weight is 200g and with the friction block overall the mass is 0.3 kg. With a spring scale we found Fs to be 1N and Fk to be 0.8N. Draw free body diagram.
*Monday, January 28, 2013 at 10:10pm by Mary*

**physics cars! **

Car A uses tires for which the coefficient of static friction is 0.175 on a particular unbanked curve. The maximum speed at which the car can negotiate this curve is 28.3 m/s. Car B uses tires for which the coefficient of static friction is 0.740 on the same curve. The cars of...
*Thursday, February 10, 2011 at 7:10pm by Hannah*

**Physics**

A box of textbooks of mass 25.3 kg rests on a loading ramp that makes an angle (ALFA) with the horizontal. The coefficient of kinetic friction is 0.260 and the coefficient of static friction is 0.330 . A) As the angle (ALFA) is increased, find the minimum angle at which the ...
*Saturday, November 18, 2006 at 3:30am by Jasijo*

**physics**

A 4.170 kg block of wood rests on a steel desk. The coefficient of static friction between the block and the desk is μs = 0.505 and the coefficient of kinetic friction is μk = 0.255. At time t = 0, a force F = 12.7 N is applied horizontally to the block. State the ...
*Thursday, October 25, 2012 at 10:29pm by ashley*

**Physics**

ΣFy=0 Normal Force = mass*gravity N=m*g ΣFx=ma Force of Friction = mass*velocity^2/radius F=m*v^2/r Force of Friction = Coefficient of static friction*Normal force F=Us*N So... Us*m*g=m*v^2/r Us=v^2/(r*g)
*Sunday, March 6, 2011 at 3:11pm by Jason*

**Physics**

A block is sitting on a ramp. The block feels a force of friction sufficient to keep it from sliding down the ramp, which makes an angle of 30 degrees w.r.t. horizontal. What is the minimum coefficient of static friction between the block & ramp?
*Monday, February 21, 2011 at 3:48pm by Paige*

**physics**

Here on earth and also on the moon two identical heavy crates (300kg) sit at rest on 2 identical level platforms with coefficients of static friction equal to (0.90). If one end of both platforms is slowly raised at the same time in both locations, will the crates eventually ...
*Sunday, March 16, 2008 at 1:43am by James*

**college physics**

you find that it takes a horizontal force of 160 newtons to slide a box along the surface of a level floor at constant speed . the coefficient of static friction is 0.52, and the coefficient of kinetic friction is 0.47. if you place the box on a dolly of mass 5.3 kg and with ...
*Saturday, August 14, 2010 at 7:56am by oslec*

**physics**

does that equation work for both kinetic and static friction
*Tuesday, September 25, 2007 at 7:33pm by Anonymous*

**physics**

M*g*(coefficient of static friction) = 14*9.8*0.65 = ___ N
*Friday, December 17, 2010 at 10:54am by drwls*

**physics**

static friciton is greater than sliding friction prove
*Tuesday, July 19, 2011 at 9:53am by jeffrey*

**Physics**

2 factors that increase static friction? Could it be weight or the ground?
*Saturday, May 18, 2013 at 5:06am by Kate*

**Physics **

The maximum possible value for the coefficient of static friction ?
*Saturday, November 16, 2013 at 7:58am by Maryam*

**Physics**

3.A car with a mass of 1500 kg is parked on a hill with an incline of 20°. a.What is the weight of the car? b.What is the normal force the car experiences? (hint: balance the forces parallel and perpendicular to the hill using Newton’s second law) c.What is the magnitude of ...
*Monday, June 20, 2011 at 9:03pm by Hunter*

**@ elena **

In the figure the coefficient of static friction between mass (MA) and the table is 0.40, whereas the coefficient of kinetic friction is 0.28 ? part a) What minimum value of (MA) will keep the system from starting to move? part b) What value of(MA) will keep the system moving ...
*Tuesday, May 8, 2012 at 9:30pm by ally*

**PHYSICS**

Wt. of stone = m*g Fp = mg*sin30=Force parallel to incline. Fn = mg*cos30 = Normal force = Force perpendicular to incline. Fs = u*Fn = Force of static friction. Fp-Fs = m*a = m*o = 0 Fp = Fs mg*sin30 = u*mg*cos30 Divide both sides by mg: sin30 = u*cos30 u = sin30/cos30 = 0.577...
*Sunday, February 23, 2014 at 7:21pm by Henry *

**physics. please help!**

A 2.5 kg block is pulled to the right by a horizontal string. The coefficient of static friction between the block and the floor is 0.30 and the coefficient of kinetic friction is 0.20. What value of force applied by the string will start the block moving?
*Sunday, October 31, 2010 at 7:44pm by caroline*

**Physics**

When there is no acceleration, the friction force (M g cosA *mu) equals the component of the weight in the direction down and parallel to the incline (M g sin A). Therefore mu = sin A/cos A = tan A Apply that equation both at the maximum ramp angle before slipping (in which ...
*Tuesday, November 3, 2009 at 1:46am by drwls*

**physics**

When you push a 1.95 kg book resting on a tabletop it takes 2.40 N to start the book sliding. Once it is sliding, however, it takes only 1.50 N to keep the book moving with constant speed. What are the coefficients of static and kinetic friction between the book and the ...
*Saturday, February 13, 2010 at 8:36am by janie*

**physics**

When you push a 2.05 kg book resting on a tabletop it takes 2.45 N to start the book sliding. Once it is sliding, however, it takes only 1.50 N to keep the book moving with constant speed. What are the coefficients of static and kinetic friction between the book and the ...
*Thursday, September 30, 2010 at 10:52pm by vonne*

**Physics**

he weight of the block in the drawing is 77.0 N. The coefficient of static friction between the block and the vertical wall is 0.490. (a) What minimum magnitude of the force is required to prevent the block from sliding down the wall? (Hint: The static frictional force exerted...
*Thursday, November 7, 2013 at 8:47pm by Samantha*

**PHYSICS**

The drawing shows a large cube (mass = 34 kg) being accelerated across a horizontal frictionless surface by a horizontal force P. A small cube (mass = 3.3 kg) is in contact with the front surface of the large cube and will slide downward unless P is sufficiently large. The ...
*Monday, June 4, 2007 at 7:07am by MJ*

**Physics**

A 10-kg wooden box rests on a wooden ramp. The coefficient of static friction is 0.50, and the coefficient of kinetic friction is 0.30. What is the friction force between the box and ramp if the ramp is at a 25o angle? the ramp is at a 45o angle? what is the acceleration of ...
*Tuesday, October 5, 2010 at 5:47pm by Anonymous*

**physics**

The required friction force will depend upon the static coefficient. The required downward force Fy to make the friction force equal the pulling force Fx is given by (Fy + Mg)*0.30 = Fx Solve for Fy. M = 30 kg and Fx = 125 N The kinetic friction coefficient is not needed.
*Monday, March 15, 2010 at 10:42am by drwls*

**Physics**

Suppose a hanging 1.0 kg lab mass is attached to a 4.0 kg block on the table. a. If the coefficient of kinetic friction, uk is 0.20, what is the acceleration of the block? b. What would be the minimum value of the coefficient of static friction, Us, in order for the block to ...
*Friday, January 28, 2011 at 6:07pm by jdajaljk*

**physics**

A 20.0kg block rests on a plane inclined at 20.0o to the horizontal. The coefficient of static friction is 0.250, and the coefficient of kinetic friction is 0.150. (a) What is the minimum magnitude of the force F, parallel to the plane that will prevent the block from slipping...
*Wednesday, March 21, 2007 at 6:28am by Jean*

**Physical science**

A box a weight of 100 N rests on a horizontal floor.The coefficient of static friction is 0,40 and the coefficient of kinetic friction is 0,30.DETERMISE THE FRICTIONAL FORCE ACTING ON THE BOX IF A HORIZONTAL FORCE IS APPLIED WITH A MAGNITUDE OF 0 N
*Sunday, February 16, 2014 at 10:53am by Confidence*

**physics**

a 2400-lb (=10.7-kn)car traveling at 30 mi/h (=13.4m/s)attempts to round an unbanked curve with a radius of 200ft (=61.0m).(a) what force of friction is required to keep the car on its path?(b) what minimum coefficient of static friction between the tires and road is required
*Thursday, March 11, 2010 at 10:33am by Anonymous*

**physics**

The chain is released from rest with a length b of overhanging links just sufficient to initiate motion. The coefficients of static and kinetic friction between the links and the horizontal surface have essentially the same value, μ. Determine the velocity v of the chain ...
*Thursday, August 29, 2013 at 6:18am by lovely*

**physics**

The initial force it takes to move the crate is given by μs*mg where μs is the coefficient of static friction. Similarly, the coefficient of kinetic friction can be calculated from the force it takes to maintain motion. Post for an answer check if you wish.
*Thursday, September 30, 2010 at 11:04pm by MathMate*

**Physics**

He can move the mule if he can overcome the static friction force M g * Us How big is that?
*Monday, October 8, 2007 at 10:26am by drwls*

**Physics**

i guess i'm just confused on the mu means static friction? .24?
*Thursday, November 4, 2010 at 5:29pm by Gage*

**Physics**

Find the fg y component because that is equal to the "n" in the equation: F(static friction) = mu x n
*Saturday, May 21, 2011 at 11:52am by Paul*

**East**

I need an equation that has something to do with the role of static friction in the design of tires
*Thursday, January 31, 2013 at 8:10pm by Jess*

**Physics**

(a) The friction force accelerates the box. (b) The box slides if mus*(M g) < M a mus = 0.30 < a/g "mus" is the static friction coefficient. It would normally be written as a Greek lower case "mu" with an "s" subscript. a = 0.3 g = 2.94 m/s^2 is the maximum acceleration ...
*Wednesday, September 23, 2009 at 9:17pm by drwls*

**Physics**

Any help pleeeze!! I'm totally lost on these!! 1. A 14 g coin slides upward on a surface that is inclined at an angle of 16° above the horizontal. The coefficient of kinetic friction between the coin and the surface is 0.23; the coefficient of static friction is 0.31. Find the...
*Sunday, May 20, 2007 at 11:03am by L.A.*

**Physics**

A box weighing 5kg sits on a box weighing 10kg. The static friction between them is .5. There is no friction under the bottom box. How much tension is needed on the bottom box to make the top box slide?
*Tuesday, October 6, 2009 at 10:22am by Bob*

**physics**

Why have you listed the subject as "Cleveland"? The static friction coefficient is the force reuired to start it moving, divided by M g. The kinetic friction coefficient is the force required to keep it moving at constant speed, divided by M g. M g in this case is 28 x 9.81 ...
*Thursday, December 17, 2009 at 11:53pm by drwls*

**physics**

The static coefficient of friction, which you call ìs=0.55, is the one to use. Equate the centripetal force to the friction force, and solve for R. The mass of the car will cancel out. 0.55 g = V^2/R Solve for R. 25 mph = 36.67 ft/s g = 32.2 ft/s^2
*Tuesday, November 23, 2010 at 8:28am by drwls*

**physics**

F1 = force to start movement μs = coefficient of static friction F2 = force to maintain movement μk = coefficient of kinetic friction m = mass The coefficients of friction are defined as follows: F1 = μs*mg F2 = μk*mg
*Thursday, September 30, 2010 at 10:52pm by MathMate*

**physics**

The coefficient of static friction between a block and a horizontal floor is 0.37, while the coefficient of kinetic friction is 0.10. The mass of the block is 3.8 kg and it is initially at rest. Once the block is sliding, if you keep pushing on it with the same minimum ...
*Sunday, November 21, 2010 at 12:37pm by anonymous*

**Physics**

a sled mass 50 kg is pulled along snow-covered, flat group. the static friction coefficent is 0.30, and the sliding friction coefficient is .10. what force is need to get the sled moving? then, what force is needed to keep the sled moving at a constant velocity?
*Sunday, November 28, 2010 at 10:27pm by Alex*

**Classical Mechanics Physics**

A block of mass m= 3 kg is initially at rest on a horizontal surface. At time t=0, we begin pushing on it with a horizontal force that varies with time as F(t)=βt2, where β= 1.2 N/s2. We stop pushing at time t1=5 s [F(t)=0 for t>t1]. (a) First, assume the surface ...
*Friday, December 6, 2013 at 3:38pm by Anonymous*

**PHYSICS**

you need to move a 500 kg crate of gazelle food from the garage along the 42 meter hall to the kitchen. If you apply a force of 1000 N at a 37 degree angle to the horizontal. How long will it take to move to the kitchen?(coefficient of static friction=.15, coefficient of ...
*Wednesday, September 26, 2007 at 7:01pm by HELP!!!*

**physics**

A student wants to determine the coefficients of static friction and kinetic friction between a box and a plank. She places the box on the plank and gradually raises one end of the plank. When the angle of inclination with the horizontal reaches 25°, the box starts to slip, ...
*Thursday, September 16, 2010 at 1:48am by Anonymous*

**physics**

Review the definitions of static and kinetic friction coefficents and the equations will tell you how to proceed.
*Sunday, January 23, 2011 at 1:38pm by drwls*

**physics**

What must be the magnitude of the force of static friction between the surface and the bottom of the crate?
*Friday, December 7, 2012 at 12:59am by Anonymous*

**physics**

the system is in static equilibrium. The coefficient of static friction between the block and the table's surface is = 1/3. The mass of the block that is hanging down is n1 Kg. The tangent of the angle shown in the figure is tan theta = n2. What is the minimum value of mass, ...
*Saturday, January 14, 2012 at 4:35pm by frank*

**physics**

Use the definitions to answer the questions: (a) coeficient of static friction = (force required to start motion)/weight (b) coefficient of kinetic friction = (force required to maintain constant velocity)/weight (Make sure you use weight = M*g)
*Thursday, November 18, 2010 at 9:40am by drwls*

**physics**

I'm trying to rearange this equation for Mu s That is the greek letter Mu subscript s... the static coeficent of friction m2 = m1 sin theta - Mu s m1 cos theta ok I got this Mu s = -((m1 cos theta)^-1 (m2 - m1 sin theta)) ok I know that sin over cosine is tangent but I cant ...
*Thursday, July 30, 2009 at 12:39pm by physics*

**physics**

A block of mass m= 3 kg is initially at rest on a horizontal surface. At time t=0, we begin pushing on it with a horizontal force that varies with time as F(t)=βt2, where β= 0.6 N/s2. We stop pushing at time t1=5 s [F(t)=0 for t>t1]. (a) First, assume the surface ...
*Monday, December 9, 2013 at 2:43pm by socorro*

**Physics**

Both are correct. Friction is opposite to the direction of motion or, in the case of static friction, an applied force that attempts to cause motion. A spring's force is opposite and proportional to the displacement from an equilibrium position. If I had to choose one answer ...
*Friday, April 10, 2009 at 1:25pm by drwls*

**Physics - help please!**

A 20 kg mass is at rest on a level surface where the coefficient of static friction is 0.68. a) How much force will it take to get the mass to move. b) If a horizontal applied force of 72 Newtons is acting on the mass, how much friction is acting?
*Monday, November 1, 2010 at 5:32pm by Leah*

**physics**

Two masses M1 = 3.00 kg and M2 = 7.50 kg are stacked on top of each other as shown in the figure. The static coefficient of friction between M1 and M2 is μs = 0.520. There is no friction between M2 and the surface below it
*Sunday, September 16, 2012 at 11:09pm by Kylie*

**English**

I do not remember answering that question. 55 km/h = 15.28 m/s Call that V If the car is banked for turns at that velocity, the normal force component in the vertical direction is Mg and the component in the hotizontal direction is M g tan A, which equals MV^2/R. Thus the ...
*Wednesday, December 22, 2010 at 12:07am by drwls*

**Physics**

A 54.0kilogram block is placed on a plane that is inclined 32 degrees to the horizontal. The coefficient of static friction between the block and the plane is 0.573 and the coefficiencet of kinetic friction is 0.310. Find the acceleration of the block down the plane. Please ...
*Monday, June 11, 2012 at 4:31pm by Genny*

**Physics**

What is the maximum speed with which a 1150-kg car can round a turn of radius 71 m on a flat road if the coefficient of static friction between tires and road is 0.80? May someone walk me through this problem step by step? Thank you *The equation friction coefficient= v^2/Rg ...
*Sunday, June 17, 2012 at 11:43am by Mike Joseph*

**Physics**

Since the object is not moving, the friction force is the equilibrant (the reverse of the resultant) of the two applied forces. This will only permit you to obtain a lower bound to the static friction coefficient. It is possible that a greater force could be applied without ...
*Monday, March 21, 2011 at 7:28pm by drwls*

**AP Physics B**

A penny of mass 3.1g rests on a small 28.2g block supported by a spinning disk of radius 12cm. The coefficients of friction between the block and disk are .73 (static) and .64 (kinetic) while those for the penny and black are .6 (static) and .45 (kinetic). What is the maximum ...
*Friday, November 9, 2012 at 8:56pm by Daisy*

**Physics**

The definition of the static coefficient of friction (ìs) tells you that Force required to move = 20 N = M*g*ìs Solve for ìs
*Saturday, February 11, 2012 at 10:34am by drwls*

**physics**

You have not asked a complete question. They might want to know a minimum required static friction coefficient.
*Thursday, December 6, 2012 at 9:57pm by drwls*

**Physics**

*I really don't know how to get started. I have done lots of the homework, but this one (and a couple of others) are really giving me PROBLEMS.* A pickup truck is carrying a toolbox, but the rear gate of the truck is missing, so the box will slide out if it is sent moving. The...
*Sunday, October 1, 2006 at 11:38am by John*

**Physics**

weight = 5*9.81 max static friction force =5*9.81*.8 = 39.24 N 5*9.81 * .22 = 10.8 moving friction 39.24 - 10.8 = 5 a a = 5.69 m/s^2
*Saturday, February 8, 2014 at 3:43pm by Damon*

**Physics**

A block of mass m1 is on top of a block of mass m2. Block 2 is connected by an ideal rope passing through a pulley to a block of unknown mass m3 as shown. The pulley is massless and frictionless. There is friction between block 1 and 2 and between the horizontal surface and ...
*Sunday, June 23, 2013 at 7:24pm by Rose*

**Physics**

4. A force of 48 N is required to start a 7.8 kg box moving across a horizontal concrete floor. (a) What is the coefficient of static friction between the box and the floor? = (b) Does the coefficent of friction have a unit? A. No, it is a ratio B. No, the units are not real C...
*Sunday, February 23, 2014 at 7:03pm by Rian*

**physics**

The angle A at which slipping starts can be used to determine the coefficient of static friction, u_s. M*g*sinA = u_s*cosA*M*g M and g cancel, leaving u_s = tanA = 0.466 The rate at which it accelerates after that can be used to determine the coefficient of kinetic friction, ...
*Thursday, September 16, 2010 at 1:48am by drwls*

**College Physics**

A 75.0 kg ladder that is 3.00 m in length is placed against a wall at an angle theta. The center of gravity of the ladder is at a point 1.20 m from the base of the ladder. The coefficient of static friction at the base of the ladder is 0.800. There is no friction between the ...
*Monday, October 25, 2010 at 4:03pm by Ali*

**Physics**

(a) A 10 kg box of candy rests on a floor with a coefficient of static friction of 0.30. What force is needed to move the box? b) What is the coefficient of kinetic friction between a rubber tire and the road if a 2000 kg car needs 1.57 × 104 N to keep the car moving at a ...
*Saturday, September 29, 2012 at 3:45pm by Hanu*

**Physics**

A 1200-kg car rounds a corner of radius r = 45 m. If the coefficient of static friction between tires and the road is 0.93 and the coefficient of kinetic friction between tires and the road is 0.75, what is the maximum velocity the car can have without skidding?
*Tuesday, October 5, 2010 at 5:52pm by Anonymous*

**phsics**

A block is at rest on an inclined plane whose elevation can be varied. The coefficient of static friction is μs= 0.4, and the coefficient of kinetic friction is μk = 0.16. The angle of elevation θ is increased slowly from the horizontal. At what value of θ ...
*Sunday, October 24, 2010 at 11:33pm by help*

**physcis **

What is the maximum acceleration a car can undergo if the coefficient of static friction between the tires and the ground is 0.82?
*Monday, May 7, 2012 at 10:29pm by ericka*

**Physics**

That would equal the centripetal force, M V^2/R, if the car does not skid. It will not depend upon the static friction coefficient
*Tuesday, October 16, 2012 at 1:00am by drwls*

**chemistry**

supposthat the surface area of the box reduced by half , what effects this will has on the coeficint of kintic and static friction
*Saturday, December 8, 2012 at 4:29pm by sano*

**chemistry**

supposthat the surface area of the box reduced by half , what effects this will has on the coeficint of kintic and static friction
*Saturday, December 8, 2012 at 4:30pm by sano*

**Physics (Static Friction)**

divide by a 1000 your original answer is in N i believe also i would like to know how you solved this
*Wednesday, July 28, 2010 at 7:06pm by andrew*

**physics**

What is the maximum acceleration a car can undergo if the coefficient of static friction between the tires and the ground is .90
*Wednesday, April 10, 2013 at 1:06pm by Amber *

**physics**

A box of textbooks of mass 24.8 rests on a loading ramp that makes an angle with the horizontal. The coefficient of kinetic friction is 0.25 and the coefficient of static friction is 0.35. At this angle, how fast will the box be moving after it has slid a distance 4.9 along ...
*Tuesday, September 27, 2011 at 11:27pm by Bradley*

**Physics**

In a pulley system, can the force of friction equal the tension in the rope? Let's say there is a mass on a table connected to a pulley system (placed at the corner of the table), while the other mass hangs from the table ... can the force of friction equal the tension? ...
*Saturday, October 17, 2009 at 1:59pm by Lisa*

**Physics**

A 10-kg wooden box rests on a ramp that is lying flat. The coefficient of static friction is 0.50, and the coefficient of kinetic friction is 0.30. What is the friction force between the box and ramp if no force horizontal force is applied to the box? a 20 N horizontal force ...
*Tuesday, October 5, 2010 at 5:46pm by Anonymous*

**physics**

A force of 48 N is required to start a 7.8 kg box moving across a horizontal concrete floor. (a) What is the coefficient of static friction between the box and the floor? \mu_s = (b) Does the coefficent of friction have a unit? A. No, it is a ratio B. No, the units are not ...
*Friday, February 21, 2014 at 1:13pm by shawn*

**physics**

A circular curve on a highway is designed for traffic moving at 27 m/s. The radius of the unbanked curve is 160 m. What is the minimum coefficient of friction between tires and the highway necessary to keep cars from sliding off the curve? Is the friction static or kinetic? (...
*Thursday, February 27, 2014 at 5:44pm by Anonymous*

**Physics (Mechanics)**

component of gravity force down ramp =10*9.8*sin 30 = 49 N component of gravity force normal to ramp = 10*9.8*cos 30 =84.9 N Max static friction force = .48*84.9 = 40.7 N so gravity wins, it slides and friction coef becomes .28 friction force then = .28*84.9 = 23.8 N
*Sunday, September 30, 2012 at 5:36pm by Damon*

**PHYSICS**

An object is placed on an incline with friction. The incline is slowly raised from a zero degrees and at 29.2 degrees, the object begins to slide down the incline. The incline is then raised to 40.5 degrees and the object is placed back on the incline. The coefficient of ...
*Friday, October 21, 2011 at 2:40pm by Ashley*

**physics**

It starts sliding when the static friction force reaches its maximum value. Its maximum value is Us*M*g. Us is the static coefficeint you want to determine After 7 seconds, the angular velocity is 5.6 rad/s and the centripetal acceleration is Rw^2 = -.15*(5.6)^2 = 4.7 m/s^2. ...
*Tuesday, April 13, 2010 at 11:05pm by drwls*

**Physics **

A person pushes on a 60-kg refrigerator with a horizontal force of -260 N; the minus sign indicates that the force points in the -x direction. The coefficient of static friction is 0.68. (a) If the refrigerator does not move, what are the magnitude and direction of the static ...
*Wednesday, February 2, 2011 at 7:05pm by Tiffany*

**Physics**

A person pushes on a 56-kg refrigerator with a horizontal force of -251 N; the minus sign indicates that the force points in the −x direction. The coefficient of static friction is 0.7. (a) If the refrigerator does not move, what are the magnitude and direction of the ...
*Wednesday, October 2, 2013 at 12:25am by Heather*

**physics**

Bob is pulling a 30kg filing cabinet with a force of 200N , but the filing cabinet refuses to move. The coefficient of static friction between the filing cabinet and the floor is 0.80.What is the magnitude of the friction force on the filing cabinet? Express your answer to two...
*Thursday, March 20, 2014 at 6:31pm by salar*

**physics**

no its on a flat surface with the static friction of .25. and W is hanging off the string at a 45 degree angle vertically.
*Friday, October 8, 2010 at 9:04pm by andrew*

**physics**

If your browser can't load certain text, the box after angle is theta, and the coefficient of static friction is u sub s
*Thursday, April 11, 2013 at 12:01pm by Nick*

**physics**

(a)block A weigh 60N. the coefficient of static friction between the block and the surface on which it rests is 0.25. the weight W is 12N and the system is at equilibrium. find the friction force exerted on block A. (b)find the maximum weight W for which the system will remain...
*Friday, October 8, 2010 at 9:04pm by andrew*

**physics**

Two blocks with mass m1 = 7.2 and m2 = 7.7 are connected by a massless string over a frictionless and massless pulley. The angle of the incline is equal to 45.0. The kinetic coefficient of friction between m1 and the incline is 0.22. What is the minimum value of the static ...
*Sunday, October 9, 2011 at 5:01pm by Jessica *

**physics**

a force F pushes on a box of mass m that initially is at rest on a rough, horizontal surface. the force F is directed at an angle theta = 30 degreees above the horizontal. the coefficants of friction between the plane and the box are static= .30 and kinetic = .28. if F=50N and...
*Friday, February 17, 2012 at 7:28am by Matt*

**Physics**

A force of 40 N is required to start a 5 kg box moving across a horizontal concrete floor. (a) What is the coefficient of static friction between the box and the floor? (b) If the 40 N force continues, the box accelerates at 0.70 m/s2. What is the coefficient of kinetic friction?
*Tuesday, December 4, 2012 at 10:10am by Harry*

**Physics **

a force of 48.0N is required to start a 5.Okg box moving across a horizonatl concrete floor.what is the coefficient of static friction between the box and the floor?If the 48.0-N force continues, the box accelerates at 0.70 m/s squared . What is the coefficient of kinetic ...
*Tuesday, February 15, 2011 at 3:54pm by Jen *

**physics**

if the weight of the block,W,is 2.5 kilogram,the coefficient of static friction,0.25,and the coefficient of kinetic friction,0.15,determine: (a) the force necessary to hold the block sliding down (b) the force necessary to pull the block up the plane with uniform speed
*Wednesday, March 6, 2013 at 9:21am by helpppp meeeeeeee PHYSICS.........................*

**Classical Mechanics - Need Help Please**

A block of mass m= 3 kg is initially at rest on a horizontal surface. At time t=0, we begin pushing on it with a horizontal force that varies with time as F(t)=βt2, where β= 1.2 N/s2. We stop pushing at time t1=5 s [F(t)=0 for t>t1]. (a) First, assume the surface ...
*Sunday, December 8, 2013 at 3:38am by Jeff*

**Physics**

Is the 0.20 a static friction coefficient? Is the 0.10 a kinetic friction coefficient? Those are the types you need to solve the problem. First calculate the maximum friction force (Ftop) that the top block can withstand without sliding. M(top)*g *0.2 = Ftop Then calculate the...
*Sunday, July 17, 2011 at 10:46pm by drwls*

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