Wednesday
April 16, 2014

Search: sn

Number of results: 456

pre calc
If Sn represents the sum of the squares of the first n natural numbers, use proof by induction to find which of the following expressions for Sn is true? Sn=n(n-1)/(3) Sn=n(2n-1)/(3) Sn=n(n+1)/(3) Sn=n(n+1)(2n+1)/(3)
Tuesday, November 27, 2012 at 11:00am by ziya

Math - PreCalc (12th Grade)
If Sn represents the sum of the squares of the first n natural numbers, use proof by induction to find which of the following expressions for Sn is true? A) Sn = n(n − 1)/3 B) Sn = n(2n − 1)/3 C) Sn = n(n + 1)/3 D) Sn = n(n + 1)(2n + 1)/3
Thursday, March 20, 2014 at 12:23pm by Shawna

Math
Answer is 2.. From Lagrange's Theorem, we know that the number of cosets in An in Sn is [Sn:An] = |Sn|/|An| = 2 Note An = n!/2 = |Sn|/2
Saturday, October 13, 2012 at 11:51pm by Annoymous

Chemistry
Remember Leo the Lion goes Grr. The key word is Leo; i.e., loss electrons oxidation. So reduction is the gain of electrons. If you know it's Sn, then does Sn gain electrons in going from Sn+4 to Sn+2 or from Sn+2 to Sn+4.
Sunday, March 20, 2011 at 9:06pm by DrBob222

Chemistry
Your numbers aren't right and there is nothing to show "as written". Sn^2+ + 2e ==> Sn Eo = -0.14 Cr^2+ + 2e ==> Cr Eo = -0.91 Use E = Eo - (2.303*RT/n)log(Sn/Sn^2+), plug in R and T (59+273), Sn is 1 and Sn^2+ is 0.0170. Solve for E. Do the same for Cr^2+. Then reverse ...
Friday, March 29, 2013 at 10:52pm by DrBob222

chemistry
All you need to do is to correct for the half cell reaction Sn^+2 + 2e ==> Sn. Step 3: Half reaction for reduction of tin Sn^4+ + e- --> Sn^2+ amount of tin produced. 0.013mol e- x 1mol/4mol = 0.00325mol of Sn This step then would be 0.0129 x 1 mol e/2 mol(instead of 4...
Friday, April 18, 2008 at 12:55pm by DrBob222

Chemistry
Calculate Eo based on the reduction potential. E = Eo-(0.0592/n)log (red form/ox form) For Sn, Eo (written in reduced form)is Sn^+2(1.70M) + 2e = Sn Eo = whatever. you look it up. Substitute into the Nernst equation I have above. n = 2 in the equation and the log Q part is (Sn...
Sunday, April 18, 2010 at 4:28pm by DrBob222

Chem 1046
There are a couple of ways of doing this. I think the easier of the two is as follows: ClO2 + e ==> ClO2^- Eo = +0.95v Sn(s) ==> Sn^2+ + 2e Eo = -0.14 -------------------------- 2ClO2 + Sn(s) ==>2ClO2^- + Sn^2+ which is the cell rxn at standard states 1 atm, 1M, etc. ...
Saturday, July 14, 2012 at 10:48am by DrBob222

chemistry
If you are plating out Sn, then the half cell must be Sn^+2 + 2e = Sn. I'll look at the remainder but give me some time.
Friday, April 18, 2008 at 12:55pm by DrBob222

Chemistry
#5. You need to redo the Hg one as a result of my comments above. For Sn you want Sn ^2+ ==> Sn^4+ + 2e Eo = -0.15. Written this way it is an oxidation potential.
Sunday, April 8, 2012 at 4:55pm by DrBob222

chemistry
Start now! Let's call strychnine SN. SN + HOH ==> SNH^+ + OH^- Kb = (SNH^+)(OH^-)/(SN) (SNH^+) = x (OH^-) = x (SN) = 0.001 - x Plug into Kb and solve for x = (OH^-) pOH = - log(OH^-) and pH = 14 - pOH
Saturday, April 5, 2008 at 11:59pm by DrBob222

Chemistry
Try this. Sn + 2HCl ==> SnCl2 + H2 mols Sn = 42.8/atomic mass Sn mols H2 = mols Sn Then PV = nRT You know n, R, T, solve for PV and that is work of expansion of the gas. The unit is L*atm. Multiply by 101.325 to convert to joules.
Thursday, September 19, 2013 at 10:56pm by DrBob222

chemistry
First separate the reaction into reduction and oxidation reactions. Then add the right number of electrons to balance the charges. Reduction: Mn(2+) -> Mn(5+) Mn(2+) -> Mn(5+) + 3e- Oxidation: Sn(2+) -> Sn Sn(2+) + 2e- -> Sn And then balance both reactions such ...
Monday, October 21, 2013 at 7:09pm by Jai

calculus
I assume that Sn = sum(1..n) An, so Sn -> 3 Dunno where the x comes from, but if you mean when n > 1, An = Sn - s(n-1) = (3n-2)/(n+1) - (3(n-1)-2)/(n-1+1) = 5 / n(n+1)
Tuesday, January 28, 2014 at 1:06am by Steve

chem
Arrange the atoms in order of increasing IE1. As, Sb, Sn a. Sb < As < Sn ANSWER is it correct b. Sb < Sn < As c. Sn < Sb < As d. As < Sb < Sn
Friday, November 9, 2007 at 6:43pm by Sam

maths
(2/9)^2-(2/9)^3+(2/9)^4-(2/9)^5+ This is like a geometric series with the first terms missing 1 -1(2/9)^1 +1(2/9)^2-1(2/9)^3+(2/9)^4-(2/9)^5+ so if we find the sum of that series and subtract [1 -1(2/9)^1], we have it so g = 1 r = -2/9 in Sn = g (1-r^n)/(1-r) n is infinite and...
Friday, January 4, 2008 at 5:51am by Damon

Algebra II
find Sn for geometric sequence with A1 = 8, n = 9, and r = -1 Sn = A1 = 8, n = 9 and r = -1 Sn = A1(1-r^n) / 1-r = 8(1 - 1^-1)/(1-(-1)) = 8(0)/2 = 0 is this right ?
Monday, April 18, 2011 at 8:52am by anonymous

pre-algebra
An arithmetic progression or arithmetic sequence is a sequence of numbers such that the difference of any two successive members of the sequence is a constant. The sum of the members of a finite arithmetic progression is called an arithmetic series. The sum S of the first n ...
Sunday, August 14, 2011 at 12:45pm by Anonymous

Chemistry 30
I didn't look at the site but there is a lot of misinformation floating around out there. #1, Sn is a reducing agent, not an oxidizing agent. #2, Sn + Cu^+2 ==> Sn^+2 + Cu will occur spontaneously. You can take that to the bank.
Thursday, June 10, 2010 at 7:21pm by DrBob222

chemistry
A voltaic cell employs the following redox reaction: Sn^2+(aq)+ Mn(s)--> Sn(s) + Mn^2+(aq) Calculate the cell potential at 25 under each of the following conditions. a.)[Sn]= 1.51E-2 M [Mn]= 2.52M b.)[Sn]= 2.52 [Mn]= 1.51E-2 M
Sunday, April 19, 2009 at 9:56pm by help

physics
Sn=3.8+0.4-----(eqn 1) Sn=u+a(n-1/2) =u+an-a/2 Sn=(u-a/2)+an------(eqn 2) from 1 and 2 a=0.4m/s^2 u-a/2=3.8 u-0.4/2=3.8 u-0.2=3.8 u=6.0m/s
Sunday, May 20, 2012 at 3:24am by choco

Chemistry
The full equation you obtain from the set up. Read and write from left to right. Sn==> Sn^2+ + 2e Sn^4+ + 2e ==> Sn^2+ -------------------- Add the two half equations to obtain Sn + Sn^4+ ==> Sn^2+ + Sn^2+ Eo = ? Look up the Sn ==> Sn^2+ + 2e Eo value. You will ...
Friday, June 21, 2013 at 8:54pm by DrBob222

Chemistry
A piece of cadmium is placed in a solution in which [Cd^2+]=[Sn^2+]=1.00M. Will the following reaction proceed spontaneously? Cd(s)+Sn^2+(aq)-->Cd^2+(aq)+Sn(s)
Tuesday, November 9, 2010 at 1:36pm by Amanda

chemistry
It isn't correct although I didn't finish working the problem. Zn ==> Zn^2+ + 2e = +0.76 Sn^2+ + 2e ==> Sn = -=0.14 Therefore, for the rxn Zn + Sn^2+ ==> Sn + Zn^2+ E = 0.76+(-0.14) = 0.62 v. I changed the Zn to an oxidation, left the Sn as a reduction, added the ...
Thursday, June 7, 2012 at 2:28am by DrBob222

Discrete Math
So = 2 S1 = 5 Sn = - Sn - 1 + nSn - 2, n >_ 2 How do I interpret the value of n? Is this number equivalent to S1, S0, or 2? I have tried each option; finding S3 is difficult because I don't know what value to multiply Sn-2 with, when solving for S2. Your assistance would be...
Friday, April 1, 2011 at 1:10pm by Compstudent

CHEMISTRY
We really prefer that you not switch screen names. We can keep up better and answer faster if you use the same name for each post. Eu^3+ + e ==> Eu^2+ Sn^2+ ==> Sn^4+ + 2e --------------------- You have Eo for Eu3+ to Eu^2+. Look up Sn^4+ to Sn^2+, change the sign, and ...
Friday, November 30, 2012 at 11:14pm by DrBob222

chemistry
Strychnine, C21H22N2O2(aq) is a weak base but a powerful poison. Calculate teh pH of a 0.001 mol/L solution of strychnine. The Kb of strychnine is 1.0 x 10^-6 My work: I called Strychnine SN SN + HOH --> SNH+ + OH- Kb = (SNH+)(OH-)/(SN) (SNH+) = x (OH-) =x (SN) = 0.001-x ...
Monday, April 7, 2008 at 7:57pm by Ross

chemistry
Strychnine, C21H22N2O2(aq) is a weak base but a powerful poison. Calculate teh pH of a 0.001 mol/L solution of strychnine. The Kb of strychnine is 1.0 x 10^-6 My work: I called Strychnine SN SN + HOH --> SNH+ + OH- Kb = (SNH+)(OH-)/(SN) (SNH+) = x (OH-) =x (SN) = 0.001-x ...
Monday, April 7, 2008 at 7:57pm by Ross

chemistry
Look up Fe^3+ + e ==> Fe^2+ and Sn^2+ ==> Sn^4+ + 2e add Eocell and check if the number is positive. I think it will. As I recall in one of the determinations I did in quant (many years ago), we used Sn^2+ to oxidize Fe^2+ to Fe^3+ before titrating with KMnO4.
Monday, June 18, 2012 at 4:07pm by DrBob222

Chemistry
You're partly right and partly wrong. It can't be A but it isn't B. It is C. Look, here is how all of the cells that you draw operate. I'll use this cell as an example. Zn is oxidized. We put the metal being oxidized on the left. So the left electrode is the anode, it is ...
Monday, May 12, 2008 at 10:46pm by DrBob222

Math
Sn = P(1+i)^n Sn = 4000(1.11)^3 = $5,470.52.
Saturday, April 17, 2010 at 4:50pm by tchrwill

Chemistry
Sn + HNO3 ==> Sn^+2 + NO + H2O You balance.
Wednesday, April 28, 2010 at 6:17pm by DrBob222

Chemistry
Sn in SnCl4 has an oxidation state of +4; in Sn it is zero.
Saturday, October 16, 2010 at 12:47pm by DrBob222

Chemistry
I think I remember Sn(II) and Sn(IV) in one of my textbooks.
Saturday, April 24, 2010 at 6:34pm by DrBob222

Chemistry
Sngrey + O2 ==> SnO2 -578.6 SnO2 ==> Snwhite + O2 580.7 ----------------------------- Add the two equations Sngrey ==> Snwhite I have turned equation 2 around and changed the sign of dHf.
Saturday, October 20, 2012 at 10:13pm by DrBob222

Inorganic chemistry
I'm going to need some help getting this problem started Calculate E for the following electrochemial cell at 25 degrees Celsius Pt(s) ! Sn^2+(aq, 0.50M), Sn^4+(aq, 0.50Mz0 !! I^-(aq, 0.15M) ! AgI(s) !Ag(s) given the following standard reduction potentials AgI(s) + e^- ==> ...
Tuesday, April 14, 2009 at 5:23pm by Steve

Chemistry
............Sn(OH)2 ==> Sn^2+ + 2OH^- I............solid.......0........0 C............solid.......x........2x E............solid.......x........2x Ksp = (Sn^2+)(OH^-)^2 5.45E-27 = (x)(2x)^2 Solve for x = solubility in mols/L. Then grams = mols x molar mass
Tuesday, March 18, 2014 at 9:23pm by DrBob222

MATH HELP Calculus
Im stuck on a lot of questions, here they are: 24 + 12 + 6 + ...(S7) Sn = 24(2^7-1)/2-1 S7 = 24(127)/1 S7 = 3048/1 Thats what I got as an answer, but it's wrong, the real answer is a fraction answer, and its 381/8. How did they get that??? The other one was: 512 + (-256) + 128...
Sunday, September 18, 2011 at 7:53pm by Anonymous

science
what substance is being reduced in the following redox reaction? HgCl2 + Sn^2 = Sn^4 + Hg2Cl2 + Cl-
Friday, June 29, 2012 at 9:20pm by akos

Balance equation in acid solution
NO3^-1 + Sn^+2 ---> NO + Sn^+4 Do you know how to balance redox equations? If you do I can help by pointing out to you the elements that have changed oxidation state. N changes from +5 on the left to +2 on the right. Sn changes from +2 on the left to +4 on the right. Can ...
Wednesday, May 16, 2007 at 1:09pm by bik

Physics please help!!
I have already and the answers I submit is wrong. If M does not accelerate, then T ≤ μsN I M will accelerate if T exceed μsN I The NET force on M (if M does not move) is T C N equals Mg C T equals μsN if M remains at rest C M will accelerate if T exceeds...
Sunday, January 30, 2011 at 7:29pm by Megan

CHEMISTRY
Step 1 is to calculate the concn of the stock solution so you will know what you're starting with. mols Sn(NO3)4 = grams/molar mass Step 2. The M of the stock soln is mols/L soln or mol/0.250. Let's call this y molar. Then dilutions are handled with the dilution formula which ...
Thursday, October 17, 2013 at 9:41pm by DrBob222

Chemistry
First determine the OH^- already in the solution from Mg(OH)2. .......Mg(OH)2 ==> Mg2+ + 2OH^- I.......solid.......0......0 C.......solid.......x......2x E.......solid.......x......2x Ksp = (Mg^2+)(OH^-)^2 Solve for x = Mg and OH = 2x. Then go through the Sn(OH)2 the same ...
Thursday, March 14, 2013 at 10:19pm by DrBob222

Chemistry
The Al wire reduces any Sn^4+ to Sn^2 which forms Hg2Cl2 with HgCl2. Shouldn't you be looking for these answers in your text and/or notes.
Sunday, October 16, 2011 at 7:35pm by DrBob222

chemistry
Sn (s) + 2Cl2(g) --> SnCl4(l) Change in enthalpy = DH1 + DH2 + DH3 Sn(s) + Cl2(g) --> Sn Cl2(l) DH1 = -186.2 kJ Sn Cl2(l) --> SnCl2(s) DH2 = ? <-- find this either in a table in your book or online SnCl2(s) + Cl2(g) --> SnCl4(l) DH3 = -325.1 kJ
Saturday, March 9, 2013 at 10:39pm by blingblongyaomingde

CHEMISTRY
You must have 100 questions here. :-). We don't like to answer so many on one post. It takes too much time. For #1 I don't agree with your answers. Booth appear to be off by a factor of 10. 5/366.73 = mols Sn(NO3)4 = ? M = ?/0.250 = about 0.0545M Then 0.0545M x (15/90) = 0....
Friday, October 25, 2013 at 5:48pm by DrBob222

chemistry
Strychnine, C21H22N2)2(aq) is a weak base but a powerful poison. Calculate the pH of a 0.001 mol/L solution of strychnine. The Kb of strychnine is 1.0 x 10^-6 DrBob222, I am planning on obtaining a pHD in about nine years:P Can you give me some advice on how to be that 1% of ...
Sunday, April 6, 2008 at 11:04pm by Sarah

chemistry
Sn (s) + 2Cl2(g) --> SnCl4(l).Sn(s) + Cl2(g) --> Sn Cl2(l) DH = -186.2 kJSnCl2(s) + Cl2(g) --> SnCl4(l) DH = -325.1 kJWhat is the change in enthalpy?
Saturday, March 9, 2013 at 10:39pm by Sammantha

Alg 2
Schuyler, in order to solve your problem I had to turn it around (Gloria Estefan?). You said the last term was 13...I made it the first term. You said the common difference was a -10...I made it a +10. Now I had to find the last term so I used this formula: L=a+(n-1)d so 13+(...
Monday, June 20, 2011 at 10:02am by Raymond

english
dog is the sn The (a) hunging (adj) dog (sn)/ tracked (v) the (a) raccoon (do) through (p) the (a) brush (op).
Thursday, March 13, 2014 at 10:59pm by Aveary

Chemistry
Sn(IV) oxide is SnO2. The correct equation is Sn + O2 ==> SnO2.
Friday, May 29, 2009 at 9:58am by DrBob222

math
a= 12 d = 8 n = 7 Sn 1/2n[(2a+ (n-1)d)] 7/2[(2*12+ (7-1)8)] 7/2(24+48) Sn = 7/2(72) = 252
Monday, October 28, 2013 at 1:41am by Kuai

Chemistry
amperes x seconds/96,485 = Faradays and 1F which will convert 118.7/2 grams Sn from SnSO4 to Sn(SO4)2. Convert grams to moles and moles/L = M for Sn(SO4)2. For SnSO4, subtract moles converted from initial moles and change to molarity. I don't think PV = nRT will do anything ...
Monday, June 6, 2011 at 5:11pm by DrBob222

Math, Finance
You have the right formula typically shown in the form or Ri = Sn/[(1+i)^n - 1] Sn = 120,000 n = 15x2 = 30 i = .068/2 = .034 Make the keys dance.
Wednesday, November 9, 2011 at 9:14pm by tchrwill

Algebra II
find Sn for geometric sequence with a1 = 8, n = 9, and r = -1? Sn = a1(1-r ^n) / (1-r) = 8(1-1)/(1+1) = 8(0)/2 = 0 is this correct..?
Monday, April 18, 2011 at 10:05am by anonymous

Annuities
Sn = R[(1+i)^n - 1]/i Assuming you mean 20% per year going into the retirement fund Sn = 9300[(1.07)^10 - 1]/.07 =
Saturday, April 12, 2008 at 9:03am by tchrwill

Chemistry
1. If you add a more dilute acid, the ... 2. Copper and zinc form brass, which does not corrode. AT the juncture of the Zn-Cu interface, brass is formed. 3.Balancing by electrons and mass is a complication. In yours, you have two electrons missing on the left (the Sn+2, on ...
Friday, December 4, 2009 at 10:32am by bobpursley

Chemistry
Hint: The cell reaction is: Zn + Sn^+2 ==> Zn^+2 + Sn
Monday, May 12, 2008 at 10:46pm by DrBob222

Chemistry
In the reaction 2Mg + SnCl4 −> 2MgCl2 + Sn , how many electrons are involved in the conversion of SnCl4 to Sn? 1. three 2. one 3. four 4. two
Saturday, October 16, 2010 at 12:47pm by Elva

Chemistry
More finals review please... Ag^+ + 2e^- --> Ag E^nought = 0.800V Sn^4+ + 2e^- --> SN^2+ E^nought + 0.154V balanced equation: 2Ag^+ + Sn^4+ --> 2Ag + Sn^2+ E^nought cell = cathode - anode I thought I heard say that I had to flip the "less negative" half reaction (here...
Sunday, May 20, 2012 at 10:17pm by Miaow

Chemistry
A saturated solution of Mg(OH)2 is prepared having a large excess of Mg(OH)2. Sn(NO3)2 is added to the solution. Ksp = 1.8 10-11 for Mg(OH)2 and Ksp = 5.1 10-26 for Sn(OH)2. (a) What [Sn2+] is required to start the precipitation of Sn(OH)2? (b) What [Sn2+] is required so that ...
Thursday, March 14, 2013 at 10:19pm by Gregory

maths
Whoa - typo Sn = 1/(1+2/9) because r = -2/9 Sn = .818 so we want .818 -[1-2/9] .040
Friday, January 4, 2008 at 5:51am by Damon

chemistry
Obviously [Sn] can't be anything other than 1.00. You must mean [Sn^+2]. Same for Mn. The easiest way to handle this is to calculate the half cell potential for each half cell, then add them together. The reduction potential equation is Ehalfcell = Eo-(0.0592/n)*log(red/ox) ...
Sunday, April 19, 2009 at 9:56pm by DrBob222

Inorganic chemistry
What I would do is to calculate E for the Sn^+2 to Sn^+4 at the concns listed, do the same for the I^- to AgI couple, then add the oxdn half to the redn half. That will give you the cell potential.
Tuesday, April 14, 2009 at 5:23pm by DrBob222

chemistry
What is the mass of the tin produced? It is 0.71 grams OK here. What is the theoretical mass of tin that should have been produced? Theoretical mass means what is the theoretical mass based upon the electrolysis that took place. ampere x seconds = coulombs. How many mols is ...
Friday, April 18, 2008 at 9:40pm by DrBob222

help!
Yes, it can occur, Cr is more active than Sn and can displace it, however, the product will depend on temperature. The most common reaction will be 2Cr(s)+SnCl4(aq)>>2CrCl2 + Sn(s)
Thursday, April 16, 2009 at 6:27pm by bobpursley

Chemistry
Mg ==> Mg^+2 + 2e Eo = 2.37 = E1 Sn^+2 + 2e ==> Sn Eo = -0.14 = E2 ------------------------------- Mg + Sn^+2 ==> Mg^+2 + Sn Eo = E1+E2 = 2.23 v. Note that you should look up these values. My tables are 20 years old. Ecell = Eocell - (0.0592/n)*log Q. Q is where you ...
Tuesday, May 11, 2010 at 2:32pm by DrBob222

Chemistry Stoichiometry
Step 1. Write and balance the equation. Sn + O2 ==> SnO2 Step 2. How much Sn do you have? You can find the volume (length x width x thickness but change the thickness of 0.60 mm tp 0.060 cm so that all of the units will be the same). Now you know mass = volume x density. ...
Friday, May 29, 2009 at 1:40pm by DrBob222

MATH HELP HELP HELP HELP HELP
Sn=(n^2+n)^1/2 - n Prove that Sn < 1/2 for all n
Friday, November 4, 2011 at 6:50am by MATH HELP HELPPP

Physics please help!!
A mass M is initially at rest on a horizontal surface, μs=0.30 and μk=0.20 . A horizontal string then pulls M with a tension T. Forces below are magnitudes. Indicate if each statement is correct or incorrect If M does not accelerate, then T ≤ μsN M will ...
Sunday, January 30, 2011 at 7:29pm by Megan

Physics please help!!
A mass M is initially at rest on a horizontal surface, μs=0.30 and μk=0.20 . A horizontal string then pulls M with a tension T. Forces below are magnitudes. Indicate if each statement is correct or incorrect If M does not accelerate, then T ≤ μsN M will ...
Sunday, January 30, 2011 at 8:08pm by Megan

chemestry
I need serious help on this....please help guys.. i've to turn it in in an hours... Balance th following equation in acid Solutiong and determind if it is spontaneous under standard conditions. NO3^-1 + Sn^+2 ---> NO + Sn^+4 Please do not post duplicates.
Wednesday, May 16, 2007 at 1:16pm by bik

Chemistry
For Sn-134 yes. That looks high on my N/P chart but that's the way the numbers work out. That's a queer looking isotope of Sn which I guess is why. The ratio for Ag looks better on my chart.
Monday, April 12, 2010 at 10:03pm by DrBob222

MATH HELP PLEASE!
Let c be a positive integer with 1<=c<=n. Show that the set: W ={ exists in Sn such that (c)=c} is a subgroup of Sn. (The set W is called the stabilizer of c, because every element in W leaves c fixed.)
Friday, October 14, 2011 at 1:19pm by Mary

Physics please help!!
I got this exact homework but my questions are slightly different. Maybe it can help u or some one else. N equals Mg [Correct] If M does not accelerate, then T ≤ μsN [Correct] M will accelerate if T exceed μsN [Correct] The NET force on M (if M does not move) ...
Sunday, January 30, 2011 at 7:29pm by Aubrie

chemistry
moles Sn = 0.225 moles S = 0.450 ratio. divide by smallest number to make it 1.00 Sn = 0.225/0.225 = 1.00 S = 0.450/0.225 = 2.00 empirical formula is Sn1S2. Of course the 1 is not needed so it is SnS2.
Monday, November 23, 2009 at 9:26pm by DrBob222

Pre Calc
Write as a series and express as a rational number: 1. 5.36363636.... 2. 0.0123123.... Use this series and find S1,S2,S3,S4,Sn, and lim Sn. 1/1*3 + 1/3*5 + 1/5*7+...+ 1/(2n-1)(2n+1)
Sunday, March 15, 2009 at 1:02pm by Masha

Science
The following heats of formation are used to find the change in enthalpy for the formation of tin chloride in the following reaction Sn (s) + 2Cl2(g) --> SnCl4(l).Sn(s) + Cl2(g) --> Sn Cl2(l) DH = -186.2 kJSnCl2(s) + Cl2(g) --> SnCl4(l) DH = -325.1 kJWhat is the ...
Sunday, April 7, 2013 at 12:32pm by Mary

CHEMISTRY
I checked only #1. You were to calculate concns of Sn and NO3^- and I showed by calculations. Check those against yours. My answers are 0.00909 for Sn and 4*that for NO3^-. Your numbers are 10x smaller than those (for each one).
Friday, October 25, 2013 at 7:55pm by DrBob222

Chemistry
Iron(III) nitrate is Fe(NO3)3. Sn(IV) nitrate is Sn(NO3)4
Tuesday, November 16, 2010 at 7:56pm by DrBob222

Inorganic chemistry
Calc1ulate E for the following electrochemical cell at 25 degrees Celsius Pt(s) ! Sn^2+ (aq, 0.50M), S^4+(aq, 0.50M !!I^-(aq, 0.15M) ! AgI(s) ! Ag(s)! given the following standard reduction potentials. AgI(s) = e^- ==> Ag(s) + I^-(aq) E naught = -0.15V Sn^4+(aq) + 2e^- ==&...
Saturday, April 11, 2009 at 11:09pm by Steve

chemistry ASAP
First, its Sn and not SN. Next, tin(IV) means tin with a valence of 4. Dichromate is Cr2O7^2- (I don't know if the dichromate ion is given in the chart I gave you or not). Sn2(Cr2O7)4 is exactly the answer you would get; however, we USUALLY (not always) reduce the fractions if...
Wednesday, November 2, 2011 at 6:13pm by DrBob222

chemistry
the activity series of metals is: Au < Ag < Cu < Sn < Cd < Zn < Al < Mg < Na < Cs which reaction below occutrs spontaneously upong mixing the reageant shown? a) Sn(s) + Al3+ (aq)-> sn2+(aq) + al(s) b) sn(s) + zn 2+ (aq) -> sn 2+ (aq) +zn (s) c...
Sunday, October 23, 2011 at 7:54pm by Dani

Chemistry
Can you start with finding the weight of the tin foil? Tin (IV) means that the resulting compound is Sn++++, or equivalent meaning: Sn + 2O2 = SnO4 With the ATOMIC mass of tin=118.17, and 16 for O2, you should be able to complete the calculations.
Friday, May 29, 2009 at 9:58am by PC

Chemistry
Au has changed from +3 in AuCl4^- top zero in Au. Sn has changed from +2 to +4. I think the easy way is this. Au^3+ + 3e ==> Au Sn^2+ ==> Sn^4+ + 2e ---------------------- Multiply eqn 1 by 2 and eqn 2 by 3 and add. 2Au^3+ + 3Sn^2+ ==> 2Au + 3Sn^4+ Then add 8Cl^- to ...
Thursday, June 14, 2012 at 9:37pm by DrBob222

Chemistry
I would do this. (Mg^+2)(OH^-)^2 = 1.9E-11 Plug in 0.15 for Mg and solve for (OH^-)^2. Then (Sn^+2)(OH^-)^2 = 6.0E-26 Plug in (OH^-)^2 from above and solve for (Sn^+2)
Saturday, March 26, 2011 at 6:16pm by DrBob222

apchemistry
The activity series of metals is Tl Co Ni Sn Pb Hydrogen Any metal at the top will displace the ION of any metal BELOW it in the series. Therefore, Co, Ni, and Sn will displace Pb^+2 from solution and deposit Pb metal but will not displace an ion ABOVE it (so Tl^+ doesn't get ...
Monday, March 29, 2010 at 9:13pm by DrBob222

Math
A pile of bricks has 85 bricks in the bottom row, 81 bricks in the second row up, 77 in the third, and so on up to the top row that contains only 1 brick. How many bricks are in the 12th row? I don't know if I'm right but I attempted this problem below c = a1 - d c = 85 - 4 = ...
Monday, December 27, 2010 at 10:17am by Anonymous

Chemistry
Rank the following three elements in order of increasing Young'sModulus: Ge, Sn, Si. My answer is as follows: Sn<Ge<Si. I am not sure if this correct. Can someone verify. Thanks.
Friday, December 20, 2013 at 1:43pm by Hil

Chemistry 30
According to the data booklet Cu(NO3)2 and Sn(s) are spontaneous Cu2+ being a strong reducing agent and Sn(s) being a strong oxidizing agent but according this lab: d2l.adlc.ca/content/ADLC-Depts/ScienceSH/SCN3796-5cBl-08Feb10/chemistry_30/mm/m3/m3_l3_testing_predictions/...
Thursday, June 10, 2010 at 7:21pm by Jenna

chemistry
Sn(s) + Cu^2+ ==>Cu(s) + Sn^2+(aq) Please note that copper 2 sulfate is NOT the same as copper(II) sulfate.
Saturday, April 23, 2011 at 5:16pm by DrBob222

chemistry
Hy Dr Bob222 this will be the last time I will bother you about this type of question. Can you please tell what I am doing wrong? This is the best answer I could come up with: Question: Strychnine, C21H22N2O2(aq) is a weak base but a powerful poison. Calculate the pH of a 0....
Tuesday, April 8, 2008 at 1:45pm by Kelsy

chemistry
balance the following ionic equation: Sn(2+)(aq)+ Mn(2+)(aq)----- Mn(5+)(aq)+ Sn (s)
Monday, October 21, 2013 at 7:09pm by joanne

Chemistry
Which of the following substances will oxidize Sn(s) to Sn^2+? a) Cu(s) b) Cl2(g) c)Cl-(g) d) Mg(s) e) Cu^2+(aq) f) Mg^2+(aq)
Monday, April 4, 2011 at 6:15pm by Lauren

C++
Write a MAIN function and a FUNCTION to compute the sum of the below series. ((-1)^(n+1)*n!)/(n*n) (from n=1 to infinity) Within the MAIN function: . Read a variable EPSILON of type DOUBLE (desired accuracy) from the standard input. EPSILON is an extremely small positive ...
Friday, March 9, 2012 at 2:40pm by maria PLEASE HELP

C++
Write a MAIN function and a FUNCTION to compute the sum of the below series. ((-1)^(n+1)*n!)/(n*n) (from n=1 to infinity) Within the MAIN function: . Read a variable EPSILON of type DOUBLE (desired accuracy) from the standard input. EPSILON is an extremely small positive ...
Friday, March 9, 2012 at 4:22pm by maria PLEASE HELP

C++
Write a MAIN function and a FUNCTION to compute the sum of the below series. (n!)/(2n+1)! (from n=1 to infinity) Within the MAIN function: . Read a variable EPSILON of type DOUBLE (desired accuracy) from the standard input. EPSILON is an extremely small positive number which ...
Sunday, November 11, 2012 at 10:44am by Emre

AP Chemistry
0.0145533713 is the number of moles of Sn present, found from the fact that the number of moles of Sn is 1/4 the number of moles of Cl (massCl/molmassCl) MolmassSn=massSn/numbermolesSn 117.98 according to the numbers. Check my thinking.
Friday, September 5, 2008 at 2:41pm by bobpursley

Inorganic chemistry
Given the following two half-reactions, determine which overall reaction is spontaneous and calculate its standard cell potential. Cd^2+(aq) + 2e^- ==> Cd(s) E naught = -1.21V Sn^2+ + 2e^- ==Sn(s) E naught = -0.14V
Saturday, April 11, 2009 at 10:26pm by Steve

Chemistry
With no arrows how in the world do I know the reactants from the products? Anyway, you know these are spontaneous reactions so you know Cr displaces Sn^2+ and Al displaces Cr^3+ so the series would be Al, Cr, Sn with the strongest reducing agent being at the top.
Tuesday, May 15, 2012 at 2:37pm by DrBob222

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