Thursday

April 17, 2014

April 17, 2014

Number of results: 468

**Calc- Derivatives**

So, I have a bunch of derivative problems for homework and the only resource I have is the textbook, since we don't have notes. I have just started and want to make sure I'm doing them correctly. Our teacher said we do not have to simplify them either, so I'm also confused if ...
*Friday, October 22, 2010 at 6:42pm by Chelsea*

**Math**

solve by the elimination method 5u+3v=-17, 2u+v=-7 would there be a solution or not?
*Friday, February 8, 2013 at 4:09pm by tootles*

**Calculus**

First find the slope of the tangent line = y' y' = 5/2 * x^(3/2) + 1/2 * x^(-3/2) The line in question has slope m=4 So, you want y'=4 5/2 * x^(3/2) + 1/2 * x^(-3/2) = 4 let u = x^(3/2) We can rewrite that as 5u/2 + 1/2u = 4 Multiply by 2u 5u^2 + 1 = 8u 5u^2 - 8u + 1 = 0 u = 1...
*Monday, October 17, 2011 at 7:23am by Steve*

**Math**

without proper parentheses, it's hard to tell, but it looks like you want to solve 5u^2 - 2u - 3 = 0 (5u+3)(u-2) = 0 u = -3/5,2 so, (x+2)/(x-2) = -3/5, x = -1/2 or, (x+2)/(x-2) = 2, x=6 final solution: x = -1/2, 6
*Tuesday, May 1, 2012 at 12:29am by Steve*

**math**

since it's factorable, 2u^2 + 5u - 18 (2u + 9)(u - 2) hope this helps~ :)
*Thursday, April 14, 2011 at 9:02pm by Jai*

**Algebra (Verbal Expressions- More Difficult)**

6.5u + 5 - 2 + 3.5x = x + 4.5y - 10 x + y + z + 8.5 = 2x - 3y + 5(u - 7) 2 + 2u - 3(u + 8.5y) = y - 5.5u
*Saturday, November 23, 2013 at 10:46pm by Steve*

**exponential equation-Algebra**

Alright. I think I might have gotten the answer. Write back and tell me if you think it's right. If you think I messed up, I'll keep trying. First use ln to rearrange the original: 4^(x+4)=5^(2x+5) ln4^(x+4)=ln5^(2x+5) Put the exponents in front because of the properties of ...
*Friday, October 26, 2007 at 10:59pm by Corin*

**algebra**

4(3-u)+u=22+2u 12 - 4u + u = 22 + 2u -3u - 2u = 22 - 12 -5u = 10 u = -2
*Tuesday, December 7, 2010 at 5:57pm by Ms. Sue*

**plz integrate**

assume you mean (1+u) du /(3u+2u^2) which is (1+u) du/[u(3+2u)] which is 1 du/[u(3+2u)] + u du/[u(3+2u)] now let's see if we can expand 1/[u(3+2u)] into a/u + b/(3+2u) = 1/ [u(3+2u)] a(3+2u) + b(u) = 1 3 a = 1 so a = 1/3 2a + b = 0 so b = -2/3 so we have 1/[u(3+2u)] = (1/3)/u...
*Wednesday, October 8, 2008 at 7:22pm by Damon*

**Math**

just make a substitution using, say, u to get a quadratic. For example, in #6, let u = x^1/3 and you have 2u^2+5u-6=0 u = 1/4 (-5 ± √73) Since u=x^1/3, x = u^3, so x = 1/16 (-305 ± 37√73) Kinda nasty, but straightforward. How about #5? Let u=x^2-5, to get 2u^2 - ...
*Friday, February 15, 2013 at 12:11pm by Steve*

**Math**

since the lines have different slopes, they must intersect at a point somewhere. 5u+3v = -17 6u+3v = -21 now subtract one from the other to make the v's go away, and solve for u. Then plug u back in to get v.
*Friday, February 8, 2013 at 4:09pm by Steve*

**Algebra 2 URGENT**

The problem as you have expressed it is: 1/u^2 - 2u -1/u^2 - 4 = (1/u^2 -1/u^2) - 2u - 4 = -2u -4 I suspect that maybe there are brackets missng, maybe 1/(u^2-2u) -1/(u^2-4) ? or maybe not, or maybe different, like 1/u^2 - (2u-1)/(u^2-4) ? but I can't tell.
*Monday, October 19, 2009 at 7:46pm by jim*

**math**

2u (squared) + 5u - 18
*Thursday, April 14, 2011 at 9:02pm by Sheldon*

**trig**

u = (9, 2) v = (-5, -2) 2u - 3v = ?
*Wednesday, August 28, 2013 at 3:07pm by Vanessa*

**Algebra**

3v^2 + 10v + 8. Factor using AC Method: A * C = 3 * 8 = 24 = 4 * 6, Group the 4 terms in 2 factorable pairs: (3V^2 + 6) + (4V + 8), 3V(V + 2) + 4(V + 2), (V + 2) (3V + 4).
*Tuesday, August 31, 2010 at 6:31pm by Henry*

**calculus**

Find the limit. lim (5u^4+7)/(u^2-2)(2u^2-1) u-->infinity
*Friday, October 2, 2009 at 12:21am by Anonymous*

**Math**

1. Write the expression in symbols. The sum of 5u and v A) u + 5v B) 5u/v C) 5uv D) 5u + v
*Sunday, January 15, 2012 at 8:01pm by Lela*

**Algebra 2**

Subtract & Simplify if possible: 9/5u^2-5u - 2/5u-5 I ended up with 35u-45-10u^2 Doesn't seem correct. can anyone help?
*Tuesday, January 26, 2010 at 6:59pm by Please HELP*

**11th grade**

LS =sin(4u) = sin(2u + 2u) = sin(2u)cos(2u) + cos(2u)sin(2u) = 2sin(2u)cos(2u) = RS
*Thursday, March 25, 2010 at 2:26pm by Reiny*

**Calculus HELP!!**

just add them up: 2u-3v-w = 12-6-6 8-6-2 10-9-1 = 0 0 0
*Monday, January 27, 2014 at 4:54pm by Steve*

**Math**

Evaluate each polynomial for the given value of x. 3x^2+2x^2-3 (a)x=-2 (b) x=t (c) x=2u (d) x=-3v
*Wednesday, September 29, 2010 at 4:21pm by Heather*

**Math**

Evaluate each polynomial for the given value of x. 3x^2+2x^2-3 (a)x=-2 (b) x=t (c) x=2u (d) x=-3v
*Wednesday, September 29, 2010 at 7:07pm by Heather*

**Algebra:'(**

just to be sure did i do this right? 3(3u+2)+5=2(2u-2) 9u+6+5=4u-4 5u=-15 5/5=-15/5 u=-3
*Wednesday, November 28, 2012 at 9:31pm by EmilyMay*

**algebra**

Let B = no. of bicycles, U = no. of unicycles and T = no. of tricycles. Then you're told that: B = 88 + U T = 5U B = 40 + T. But T=5U, so B = 40 + 5U So since B = 88 + U, you know that 40 + 5U = 88 + U, so 4U = 48. From there you can work out what all of U, B and T are, and ...
*Tuesday, September 30, 2008 at 9:33am by David Q*

**math**

How do you work out: 5u-v+2w=25 3u+2v-3w=16 2u-v+w=9 I have tried loads of times already and can't get the right answer.
*Sunday, October 21, 2007 at 9:23am by Anonymous*

**calculus**

d/du ( 1/(2u^2 - 1)^2 ) d/du ( (2u^2 - 1)^-2 ) = -2(4u)(2u^2 - 1)^-3 = -8u / (2u^2 - 1)^3 Hope this helps~ :3
*Wednesday, October 2, 2013 at 11:10am by Jai*

**Differential Equations**

du/dt = e^5u * e^7t du/e^5u = e^7t dt e^-5u du = e^7t dt (1/-5) e^-5u = (1/7) e^7t + C 7 e^-5u = -5 e^7t + c when t = 0, u = 12 7 e^-60 = -5 + c c = 5 +7/e^60 or c is about 5 7 e^-5u + 5 e^7t = 5
*Saturday, August 27, 2011 at 1:55pm by Damon*

**math**

-29 = -4 + 5u -29 + 4 = 5u -25 = 5u -5 = u
*Tuesday, July 10, 2012 at 7:44pm by Ms. Sue*

**Algebra2**

just like the one with x^1/2, I think you meant to type 6x^2/3 - 5x^1/3 - 6 = 0 can't do it if it is as you typed it. let u = x^1/3 then you have 6u^2 - 5u - 6 = 0 (3u+2)(2u-3) = 0 u = -2/3 or 3/2 so, x^1/3 = -2/3 or 3/2 x = -8/27 or 27/8
*Wednesday, August 29, 2012 at 12:14pm by Steve*

**Pre-Calculus Vectors**

Let u = 2i − j, v = −i + j. Find 2u - 3v.
*Monday, April 18, 2011 at 7:34pm by PETER*

**Calc- Derivatives**

1. My first-line derivative would be Y' (u) = (u^-2 + u^-3)(5u^4 - 4u) + (u^5-2u^2)(-2u^-3 - 3u^-4) If I were testing my students to see if they master the product rule, this is the line I would be looking for. The rest is "window dressing", that is, simplifying it. If you ...
*Friday, October 22, 2010 at 6:42pm by Reiny*

**math**

Let the Function a @ b be defined as 3a + 2b for all real numbers a and b. If u and v are real #'s for which u and v = v @ u = 20. What is the value of 2u @ 3V?
*Wednesday, January 27, 2010 at 5:14pm by Carmianerlo*

**Calculus HELP!!**

u=6 4 5 v=2 2 3 w=6 2 1 show that 2u - 3v - w = 0 Sorry!! I hope this makes a bit more sense...Can we try to do this step by step so I can understand it better?
*Monday, January 27, 2014 at 4:54pm by Sara*

**college physics**

Draw the diagram. alternate the charges. With some thinking, you can see this is the only solution. The two adjacent corners have an attractive net force, equal, so the resultant is toward the center: Force= k2(cos45)2u*2u/3^2= 1.41k*2u*2u/9 Now the replelling force frm across...
*Thursday, September 17, 2009 at 6:35pm by bobpursley*

**math-factoring**

hi i was reading through the tutorials and havent really understood how to factor out a trinomial like 12x^4 - 5x^2y^2 - 2y^4 what would the 1st few steps be? Do a substitution: let v= x^2 and u= y^2 Now you have... 12v^2 - 5uv - 2u^2 (3v -2u)(4v+u) then go back and put the x ...
*Tuesday, May 1, 2007 at 8:24pm by luke*

**physics**

for an object sliding down an uneven incline, which of the following represents the change in height necessary for the velocity to double in terms of its initial velocity V? a)2V 2(subscript)*g b)3V/g2(subscript) c)3V 2(subscript)/2g d)3V/2g e)2g/3v 2(subscript)
*Tuesday, November 2, 2010 at 3:29pm by Asim*

**8th grade**

v = (1/3)(ð)(r^2)h 3v = ð (r^2)h 3v/ð = (r^2)h 3v/ð(r^2)= h
*Wednesday, September 15, 2010 at 11:03pm by smile*

**Math**

Substitute u = x^2, and solve 25u^2 -15u +2 = 0 (5u -1)(5u-2) = 0 u = 1/5 or 2/5 x = sqrt u Take it from there.
*Sunday, April 24, 2011 at 1:04pm by drwls*

**algebra**

Question 1 3v + c = 22 (1) 2v + 4c = 28 (2) From (1) 3v + c = 22 c = 22 - 3v (3) Substitute (3) into (2) 2v + 4(22 - 3v) = 28 2v + 88 - 12v = 28 -10v = -60 v = 6 Therefore, the number of people that can be transported in a van is 6
*Tuesday, December 4, 2012 at 7:21pm by Ishu*

**Calculus HELP!!**

6 2 6 Let u = 4 , v = 2 , w = 2 5 3 1 Show that 2u - 3v - w = 0. Use that fact to find x1 and x2 that satisfy the equation 6 2 6 4 2 {x1} = 2 5 3 {x2} 1
*Monday, January 27, 2014 at 4:54pm by Sara*

**math**

5.3+u=3.2u-2.7 456789 times 567?!?!! First, subtract u from both sides so you get: 5.3 = 2.2u - 2.7. Then, add 2.7 to each side to get: 8 = 2.2u. Then, do 8/2.2, so u=3.63 (the 63 is repeating).
*Tuesday, January 23, 2007 at 7:18pm by jon*

**Algebra**

25u^2 - 81 This is a difference of two squares. Therefore, the factor is (5u - 9)(5u + 9) hope this helps :3
*Monday, November 4, 2013 at 10:41pm by Jai*

**Math (algebra)**

(y-1)/2u+x=m (y-1)/2u=m-x y-1=2u*(m-x) Divide with (m-x) 2u=(y-1)/(m-x) Divide with 2 u=(y-1)/[2*(m-x)]
*Thursday, January 6, 2011 at 8:10pm by Bosnian*

**Pre calculus**

How do you work this problem? Find the exact value of sin 2u, cos 2u, and tan 2u given that cot u=3 and 180<u<270
*Monday, May 14, 2012 at 5:56pm by Cynthia*

**Dma 040**

Since we're given the values of V and h, we'll solve for a: V = (1/3)ah 3V = ah 3V/h = a a = 3V/h a = 3*21 / 3 a = 21 hope this helps :3
*Friday, September 27, 2013 at 11:52pm by Jai*

**Dma 040**

Since we're given the values of V and h, we'll solve for a: V = (1/3)ah 3V = ah 3V/h = a a = 3V/h a = 3*21 / 3 a = 21 hope this helps :3
*Friday, September 27, 2013 at 11:52pm by Jai*

**Trig**

4tan^2u-1=tan^2u 3tan^2u=1 tan^2u=1/3 sq. root of (tan^2u)=sq. root of (1/3) tanu=sq. root of (3)/3 tanu=sq. root of 1 Did I do this one right? If not, could you please show me the correct method?? Thanks!
*Saturday, January 9, 2010 at 10:40am by Tara*

**MATH HELP!**

change sin(x) to u. u=1-2u^2 2u^2+u-1=0 (2u-1)(u+1)=0 u= 1/2 or -1 sin(x)=1/2 or sinx=-1 now solve.
*Tuesday, October 25, 2011 at 5:18pm by bobpursley*

**Math**

V = (4/3)π r^3 so you want to solve for r 3V = 4π r^3 r^3 = 3V/(4π) r = (3V/(4π))^(1/3) or cuberoot(3V/(4π))
*Monday, October 4, 2010 at 4:28pm by Reiny*

**Math**

integrate (x+1)sqrt(2-x)dx u = (sqrt(2 - x)) u^2 = 2 - x x = 2 - u^2 - 2u du = dx I = integral sign I (2 - u^2 + 1)u -2u du I (3 - u^2)-2u^2 du I (-6u^2 + 2u^4) du -6 I u^2 du + 2 I u^4 du 2 I u^4 du - 6 I u^2 du 2 (1/5 u^5) - 6 (1/3 u^3) 2/5 u^5 - 2u^3 substitute back in for ...
*Monday, January 17, 2011 at 6:08pm by helper*

**beginning algebra**

(u - 1)^2 = 2u^2 - 3u - 29 u^2 - 2u + 1 = 2u^2 - 3u - 29 u^2 - u - 30 = 0 This does not factor. Solve by using the quadratic formula or the method of completing the square. Post your answer and someone will check it for you.
*Saturday, January 22, 2011 at 10:28am by helper*

**Math**

Initial: number of boys to girls 3:5 =3U:5U U means unit Later (3U +5): (5U +3) = 5:7 3U+5 5 ----- = --- 5U+3 7 Cross multiply 21U+35 = 25U+15 35-15 = 25U-21U 20 = 4U Therefore 1U =5 Initially girls are 5Units. So the answer is 25.
*Saturday, February 11, 2012 at 1:05am by Surya*

**Pre Cal**

Sec^2 2u-1/Sec^2 2u = Sin^2 2u
*Tuesday, February 19, 2013 at 2:52am by Lisa*

**Algebra 2**

To solve for a variable, you just use algebraic operations to isolate it on one side of the equation, with everything else on the other side. The key to doing this is to remember that if an equation is true, doing the same thing to both sides of the equation leaves it still ...
*Wednesday, October 12, 2011 at 11:25pm by Steve*

**calculus**

sin^2(u/5) = (1/2)[1 - cos(2u/5)] The indefinite integral of that with respect to u is u/2 - (1/2)*sin(2u/5)*(5/2) = u/2 - (5/4)*sin(2u/5)
*Saturday, February 19, 2011 at 1:02pm by drwls*

**math**

3. Reduce the fraction −20t 5u 2v 3 48t 7u 4v . A. −5t 2v 2 12u 2 C. −5v 2 12t 2u 2 B. 5t 2v 2 12u 2 D. 5v 2 12t 2u 2 4. Reduce the fraction w 2 + 5w + 6 w 2 − w − 12 . A. w − 2 w − 4 C. w + 2 w + 4 B. w + 2 w − 4 D. w − 2 ...
*Tuesday, October 20, 2009 at 11:29am by jalisaj*

**Pre Cal**

since all angles are 2u , let Ø - 2u for ease of typing I will assume you are proving this as an identity LS = (1/cos^2 Ø - 1)/(1/cos^2 Ø) = (1 - cos^2 Ø)/cos^2 Ø * (cos^2 Ø) = 1 - cos^2 Ø = sin^2 Ø = RS replace Ø with 2u if you have to
*Tuesday, February 19, 2013 at 2:52am by Reiny*

**math**

Let x/8 = u dx = 8 du So you want the integral of 8*sin^2 u du sin^2 u = (1/2)[1 - cos(2u)] => integral of 4[1 - cos(2u)] du Let w = 2u; du = dw/2 = 4u - 2 sin(w) = x/2 - 2 sin(2u) = x/2 - 2sin(x/4) Check my thinking. I tend to be sloppy
*Wednesday, June 22, 2011 at 7:49am by drwls*

**mathematics: algebra;equations**

-12 + 5u= -48 add 12 to both sides 5u = -48+12 5u = -36 divide both sides by 5 u = -36/5
*Friday, May 23, 2008 at 10:43pm by Reiny*

**math**

Solve each equation: 11/3v+2 minus 3/4= 5 over 3v+2
*Saturday, May 1, 2010 at 12:14pm by Brian*

**Algebra**

When I factor an expression completely, I get 6(v^2 + 9)(3v - 5). Is it possible to write this as 6(v + 3)(v + 3)(3v - 5)?
*Monday, March 10, 2014 at 12:46pm by Anonymous*

**Math**

32. M = 3V+6 M-6 = 3V V = (M-6)/3 (J) if you use parentheses properly 34. a = b-2 b-a = 2 (b-a)^4 = 2^4 = 16 (K)
*Saturday, January 5, 2013 at 12:26pm by Steve*

**Algebra 2 PAP**

V=(1/3)pi r^2 h multiply by 3 3V = pi r^2 h divide by pi(h) 3V/(pi h) = r^2 take √ of both sides h = ±√[(3V/(pi h)]
*Sunday, August 30, 2009 at 7:08pm by Reiny*

**Algebra**

Could I get some help Please!!!!!!!!! (1) Find the LCD 3/3v^2-3v-7/3v-3 (2) Find the LCM 14z^7 and 98z^8 (3) Find LCM y^3+6y^2+9y,y^2-6y
*Wednesday, December 17, 2008 at 9:24pm by pj*

**math**

multipy both sides by 4(3v+2) 11*4-3(3v+2)=5*4 44-9v-6=20 then solve.
*Saturday, May 1, 2010 at 12:14pm by bobpursley*

**math-volume**

I'm confused with how to solve this problem, so help would be great! The volume of any spherical balloon can be found by using the formula V= 4/3 pi r^3. Write an equation for r in terms of V and pi All this is asking you to do is get r=something. First, I would divide both ...
*Sunday, January 21, 2007 at 10:26pm by julie*

**Math**

sum means add or "+" add 5u and v 5u + v D
*Sunday, January 15, 2012 at 8:01pm by Steve*

**Trigonometry**

I need help with I just can't seem to get anywhere. this is as far as I have got: Solve for b arcsin(b)+ 2arctan(b)=pi arcsin(b)=pi-2arctan(b) b=sin(pi-2arctan(b)) Sub in Sin difference identity let 2U=(2arctan(b)) sin(a-b)=sinacosb-cosasinb =(sin(pi))(cos(2U))-(cos(pi))(sin(...
*Friday, July 27, 2007 at 12:16am by Jen*

**mathematics: algebra;equations**

-12 + 5u= -48 -12 + 12 + 5u = -48 + 12 5u = -36 u = -7.2 Check it out: -12 + (-36) = -48 -48 = -48
*Friday, May 23, 2008 at 10:43pm by Ms. Sue*

**beginning algebra**

This was answered the first time you posted it. I pasted the answer below. (u - 1)^2 = 2u^2 - 3u - 29 u^2 - 2u + 1 = 2u^2 - 3u - 29 u^2 - u - 30 = 0 This does not factor. Solve by using the quadratic formula or the method of completing the square. Post your answer and someone ...
*Saturday, January 22, 2011 at 7:50pm by helper*

**Math help**

Not trivial; some trial and error will probably be needed (5u+v)(u-2v) gives -9uv (5u+2v)(u-v) gives -3uv TA DAA!
*Monday, March 3, 2014 at 5:20pm by Steve*

**physics**

M = father's mass m = son's mass = M/3 V = father's initial speed v = son's initial speed (1/2)MV^2 = (1/3)*(1/2)*m v^2 M*V^2 = (1/3)(M/3)v^2 V^2/v^2 = 1/9 V = v/3 Second equation: (1/2)M*(V + 1.4)^2 = (1/2)m*v^2 = (1/2)*(M/3)*(3V)^2 cancel out the M's and (1/2)'s (V + 1.4)^2...
*Monday, October 3, 2011 at 9:40pm by drwls*

**Calculus**

Let u^2 = x+5 2u du =dx x = u^2 - 5 x^2 - 3 = u^4 - 10u^2 + 22 Now the integrand becomes (u^4 - 10u^2 + 22)(u)(2u du) = 2u^6 - 20u^5 + 44u^2 du That is easy to integrate. Substituting back to x at the end you have 2/21 (3x^2 - 12x + 19) (x+5)^(3/2) + C
*Wednesday, December 14, 2011 at 8:45pm by Steve*

**Calculus**

I think you have partially corrected your question. what about the v+w-3v ? Where does u come into the picture? v+w-3v would simply be w - 2v
*Saturday, February 11, 2012 at 7:54pm by Reiny*

**College Alegbra**

change sqrt x = u 2u^2-9u+4=0 (2u-1)(u-4)=0 solve for u, then x=u^2
*Thursday, March 3, 2011 at 7:39pm by bobpursley*

**calculus - PS**

Let's not forget d^2u/dx/dy = d^2u/dydx = 2
*Monday, April 23, 2012 at 1:13pm by Steve*

**math**

calculating for U: 2=sqrt(2U+7)-sqrt(U) 2+sqrt(U)=sqrt(2U+7) square both sides: 4 + 4*sqrt(U)+ U = 2U+7 transpose all terms not containing squareroot on one side of equation: 4*sqrt(U) = 2U + 7 -4 - U 4*sqrt(U) = U + 3 square both sides: 16U = U^2 + 6U + 9 U^2 -10U + 9 = 0 (U-...
*Tuesday, October 26, 2010 at 10:59pm by jai*

**algebra**

This is the difference of 2 squares: a^2 - b^2 = (a + b) (a - b). remember? 4u^2 - w^2 = (2u + w) (2u - w).
*Wednesday, September 8, 2010 at 6:33pm by Henry*

**integrate**

Is all of u -2 +2u^2 a denominator? That is (2u-1)(u+1) So you would be integrating 2u/[(2u-1)(u+1)] The method of partial fractions can be used. See http://www.math.ucdavis.edu/~kouba/CalcTwoDIRECTORY/partialfracdirectory/PartialFrac.html
*Wednesday, October 8, 2008 at 6:15pm by drwls*

**11th grade**

verify the identity sin(4u)=2sin(2u)cos(2u)
*Thursday, March 25, 2010 at 2:26pm by stacey graham*

**Physics Concepts**

Let the father's mass be M sos that the son's mass must be 2M/5. Let the father's initial speed be V, and the son's v. (1/2)MV^2 = (1/3)(2M/5)v^2 which leads to V^2 = (4/15)v^2 (1/2)M(V +1.5)^2 = (2M/5) v^2 V^2 + 3V + 2.25 = (4/5) v^2 3V^2 = (4/5)v^2 Now you can eliminate v. ...
*Saturday, March 5, 2011 at 11:37pm by drwls*

**math**

8(4u-1)-12u=11(2u-6) 32u-8-12u=22u-66 -12 20u-8=22u-66 -20u -8=2u-66 -8 2u=74 u=37 i kno 1 messed up but idk where
*Wednesday, January 12, 2011 at 6:53pm by bella*

**math**

8(4u-1)-12u=11(2u-6) 32u-8-12u=22u-66 -12 20u-8=22u-66 -20u -8=2u-66 -8 2u=74 u=37 i kno 1 messed up but idk where
*Wednesday, January 12, 2011 at 7:18pm by bella*

**math**

8(4u-1)-12u=11(2u-6) 32u-8-12u=22u-66 -12 20u-8=22u-66 -20u -8=2u-66 -8 2u=74 u=37 i kno 1 messed up but idk where
*Wednesday, January 12, 2011 at 7:22pm by angel*

**precalculus**

Let u = x^2 and solve 2u^2 -3u -20 = 0 That can be factored, to give (2u +5)(u-4) = 0 u = 4 OR -5/2 x = sqrt4 or sqrt(-3/2) The only REAL zeros are +2 and -2
*Sunday, December 12, 2010 at 5:53pm by drwls*

**algebra**

V = 1/3*6300*7 Multiply both sides by the denominator 3 3v = (6300)(7) 3v = 44,100 v = 14,700
*Monday, February 14, 2011 at 5:05pm by helper*

**math**

Increase in v: 3 1 3 Increase in f: 9 3 9 Looks like f increases to f+3 3 for every v+1 So, f = 3v+c Since f is exactly 3*v, c=0, and f(v) = 3v
*Monday, February 11, 2013 at 11:53pm by Steve*

**geometry**

Well, doesn't it say that they are equal ?? What does "bisect" mean ? 8v-2 = 3v+3 5v = 5 v=1 so 8v-2 = 6 and 3v+3 = 6 so I guess the big angle is 12
*Tuesday, August 28, 2012 at 10:29pm by Reiny*

**10th grade**

(2u+9)(2u+1)
*Friday, May 14, 2010 at 10:09am by Anonymous*

**pre-calculus**

4 - 3 (-2u) - (-2u)^2 4 + 6 u - 4 u^2
*Sunday, February 17, 2013 at 7:33am by Damon*

**Algebra**

3/v+8/v^2 = 3v/v^2 + 8/v^2 = (3v+8)/v^2
*Wednesday, October 26, 2011 at 9:07am by Reiny*

**math-volume**

I'm confused with how to solve this problem, so help would be great! The volume of any spherical balloon can be found by using the formula V= 4/3 pi r^3. Write an equation for r in terms of V and pi 4/3*pi*r3 = V Multiply by 3 3*(4/3)*pi*r3 = 3*V 4*pi*r3 = 3V r3 = 3V/(4*pi) r...
*Sunday, January 21, 2007 at 10:26pm by julie*

**physics**

replace v with 3v KE = 1/2*m(3v)^2 = 1/2 * m * 9v^2 KE is multiplied by 9.
*Tuesday, February 21, 2012 at 12:19pm by Steve*

**math**

How do you work out: 1--5u-v+2w=25 2--3u+2v-3w=16 3--2u-v+w=9 Multiply (1) by 2 and add to (1) giving you an equation in u and w. Multiply (3) by 2 and add to (2) giving you another equation in u and w. Multiply one of them by whatever makes the coefficients of u or w equal to...
*Sunday, October 21, 2007 at 9:23am by tchrwill*

**Calculus**

if u^2 = x-4 2u du = dx x = u^2+4 ∫x√(x-4) dx = ∫(u^2+4)u 2u du = ∫2u^4 + 8u^2 du = 2/5 u^5 + 8/3 u^3 = u^3 (2/5 u^2 + 8/3) = (x-4)^(3/2) (2/5 (x-4) + 8/3) = 2/15 (x-4)^(3/2) (3x+8)
*Monday, December 3, 2012 at 11:29am by Steve*

**Algebra 2**

You are still not using brackets in the proper way. I am sure the divisor is (v-5), the way you have it only the v would be divided. Let me assume you meant: (2-v)/(v-5) - (3v-5)/(5-v) = (2-v)/(v-5) + (3v - 5)/(v-5) , (I multiplied the last fraction by (-1)/(-1) = (2v -3)/(v-5)
*Thursday, March 10, 2011 at 11:26pm by Reiny*

**maths**

write down the equation d^2u/dt^2=c^2 grad^2u in a plane polar coordinates .by the method of separation of variables , reduce the PDE to obtained to a set of ODE's
*Saturday, February 11, 2012 at 1:14pm by ashely*

**math**

-8 = 2u - 66 Add 66 to both sides. 58 = 2u 29 = u
*Wednesday, January 12, 2011 at 7:18pm by PsyDAG*

**Calculus**

That is a fine substitution to make u = x + 1 dx = du x^2 = u^2 - 2u+1 so we have integral (u^2-2u+1)(u^.5) du that is integral of u^2.5 du - integral of 2u^1.5 du + integral of u^.5 du in general integral of u^n du = [u^(n+1)]/(n+1)
*Sunday, December 9, 2007 at 3:26pm by Damon*

**Pre-Calculus**

I will assume you mean 4u^2 + 4u + 1 = 75 (2u+1)^2 = 75 2u + 1 = ± √75 2u = -1 ± 5√3 u = (-1 ± 5√3)/2
*Monday, November 1, 2010 at 4:53pm by Reiny*

Pages: **1** | 2 | 3 | 4 | 5 | Next>>