Friday

April 18, 2014

April 18, 2014

Number of results: 42,792

**007031 Quadratic Equations**

complete the square factor by grouping use the quadratic equation what? study? try that too.
*Tuesday, March 19, 2013 at 10:19am by Steve*

**Math(Algebra)**

An arrow is shot vertically upward from the top of a cliff 80 feet tall, with an initial velocity of 64 ft/s, (the acceleration due to gravity is -16ft/sec). a. Write the quadratic equation representing this scenario when h is 0. b. Find the roots (solutions) for this ...
*Friday, October 5, 2012 at 3:34pm by Joshua*

**math**

x ^ 4 + 2 x ^ 2 - 15 = 0 Substitute : u = x ^ 2 ________________________________ Remark : If u = x ^ 2 then x ^ 4 = u ^ 2 ________________________________ You must solve equation : u ^ 2 + 2 u - 15 = 0 The exact solutions are : u = 3 and u = - 5 So solutions are : x ^ 2 = 3 x...
*Saturday, April 28, 2012 at 6:06pm by Bosnian*

**MATH**

In google type: quadratic equation online When you see list of results click on: Free Online Quadratic Equation Solver:Solve by Quadratic Formula When page be open click option Solve by Factoring (includes Factoring by Grouping) then in rectangle type 2x^2+5x+3=0 and click ...
*Sunday, March 9, 2014 at 10:16pm by Bosnian*

**math**

In google type : quadratic equation online When you see list of results click on : Free Online Quadratic Equation Solver: Solve by Quadratic Formula When page be open click on : Solve by Completing the Square then type : 2x^2-5x-12=0 and click option : solve it! You will see ...
*Tuesday, September 10, 2013 at 12:29am by Bosnian*

**math**

In google type: quadratic equation online When you see list of results click on: Free Online Quadratic Equation Solver:Solve by Quadratic Formula When page be open click option Solve by Factoring (includes Factoring by Grouping) then in rectangle type 2x^2 + 13x + 20=0 and ...
*Sunday, March 9, 2014 at 10:13pm by Bosnian*

**Please help! quadratic equation**

Given the following quadratic equation find. a) the vertex b) the axis of symmetry c) the intercepts d) the domain e) the range f) the interval where the function is increasing g) the interval where the function is decreasing h) graph the function y= -x^2-6x
*Saturday, March 16, 2013 at 12:25pm by Jenn*

**Math**

make it a quadratic equation.. x^2+3x+4=0 Now, use the quadratic formula. I think it will have complex roots.
*Wednesday, May 6, 2009 at 9:29pm by bobpursley*

**quadratic equations**

can you solve the equation using the quadratic formula x2 + 3x = 7? Explain and provide an exact answer.
*Tuesday, January 17, 2012 at 10:01pm by becca*

**math**

quadratic equation of 48x^2-32x-35=0 i need both answers you must use the quadratic formula
*Friday, October 26, 2012 at 2:54pm by danica *

**Algebra**

I assume you mean x - (1/x) and not (x-1)/x, and that 77/12(x - 1/x) means (77/12)[x - (1/x)]. If not, please write your equation in an unambiguous manner, using more parentheses. Treat (x - 1/x) as a new variable y, and solve the equation y^2 - (77/12) y + 10 = 0 That cannot ...
*Thursday, September 27, 2007 at 10:17pm by drwls*

**math**

your equation leads to a quadratic equation. If you have not studied that topic, an explanation is beyond what I can do here in a simple post here is my result from a Google search http://www.google.ca/search?hl=en&q=the+quadratic+equation&btnG=Google+Search&meta=
*Tuesday, December 2, 2008 at 8:38pm by Reiny*

**College Math II**

I would multiply all out, rearrange into a quadratic, then factor or use the quadratic equation.
*Saturday, November 21, 2009 at 11:50am by bobpursley*

**Factoring Trinomials**

I never heard of the criss cross method. I used the quadratic equation to solve for zeros of the quadratic expression.
*Monday, October 31, 2011 at 6:40pm by Damon*

**math**

about nine weeks is spent on this in Alg I. methods: factoring, quadratic equation, graphing. Google quadratic equations
*Saturday, October 6, 2012 at 3:06am by bobpursley*

**calculus**

2x^3 -3x +1 = 0 x = 1 is one solution. That is obvious by inspection. Therefore (x-1) is a factor of the equation. Divide the cubic by (x-1) to get the quadratic factor, (2x^2 +2x -1). That can be solved using the quadratic equation to get the other two roots x = (1/4)[-2 +/- ...
*Tuesday, November 18, 2008 at 5:39am by drwls*

**Math**

excuse me? You're in calculus, and don't know what a parabola is? Regardless, just work with the math. y'(x) = 6x-5 y'(2) = 7 y(2) = 2 So, you want the equation of the line passing through (2,2) with slope 7: (y-2) = 7(x-2) Your answer is correct. Any quadratic equation ...
*Sunday, October 28, 2012 at 10:55am by Steve*

**Math**

I am stumped could someone please explain this problem? Give the solutions to the following quadratic equation by examining the graph of the related quadratic function: Graph: y=x^2+2x-15 Equation: x^2+2x-15=0 Thanks so much.
*Friday, September 18, 2009 at 6:55am by B.B.*

**math **

State the solutions, or estimated solutions, to each quadratic equation in Exercises 2326 by examining the graph of the related quadratic function equation 2x2 - 3x - 4 = 0 and Graph:y=2x^2-3x-4 Can someone help me with this
*Friday, April 23, 2010 at 9:19pm by Alex*

**Algebra Quadratic Equations**

You are referring to the discriminant, which is part of the quadratic formula in the RADICAND section. Here is how the discriminant works: Given a quadratic equation in the forn ax^2 + bx + c = 0, plug the coefficients into the expression b^2 - 4ac to see what happens. The ...
*Wednesday, February 13, 2008 at 7:31am by Guido*

**Math**

Use the quadratic formula to solve each of the following quadratic equations... 1. 2x^2-5x=3 2. 3x^2-2x+1=0 Rearrange the equation in quadratic formula form. 2x^2 -5x -3 = 0 Then use the formula. Tell me what you don't understand about it if you don't know what to do next. I ...
*Wednesday, June 13, 2007 at 3:43pm by Tomika*

**Math**

I am stumped on this problem could someone please help? Give the solutions to the following quadratic equation by examining the graph of the related quadratic function: Graph: y=x^2+2x-15 Equation: x^2+2x-15=0 Thanks.
*Thursday, September 17, 2009 at 5:42pm by B.B.*

**algebra**

which quadratic formula would be used to solve the following quadratic equation? 4x^2 - 5x = -2 can you show me the correct answer and how do it please
*Tuesday, June 8, 2010 at 8:42am by gabriel*

**Algebra**

Another way : x + 8 / x = - 9 Multiply both sides by x x ^ 2 + 8 = - 9 x Add 9 x to both sides x ^ 2 + 8 + 9 x = - 9 x + 9 x x ^ 2 + 9 x + 8 = 0 In google type: quadratic equation online When you see list of results click on: Free Online Quadratic Equation Solver:Solve by ...
*Monday, May 28, 2012 at 1:57am by Bosnian*

**Algebra 2**

Get to know the "quadratic formula" for problems like this. The formula is at http://www.mathsisfun.com/quadratic-equation-solver.html (You can also plug in coefficients and get answers directly there). It should be also in your textbook.
*Friday, August 20, 2010 at 2:51pm by drwls*

**Algebra**

( 3 x ^ 2 - 7 x ) / 2 = 3 Multiply both sides by 2 3 x ^ 2 - 7 x = 6 Subtract 6 to both sides 3 x ^ 2 - 7 x - 6 = 6 - 6 3 x ^ 2 - 7 x - 6 = 0 in google type : quadratic equation online When you see list of results click on : Free Online Quadratic Equation Solver: Solve by ...
*Wednesday, October 30, 2013 at 1:01pm by Bosnian*

**ALGEBRA**

What does it mean to give the solutions to the following quadratic equation by examining the graph of the related quadratic function: Graph: y = x^2 + 2x - 15 Equation: x^2 + 2x - 15 = 0
*Wednesday, September 16, 2009 at 10:51pm by ggift*

**Algebra I**

What is the quadratic equation? In the standard form of the quadratic, ax2 + b x + c=0 a, b and c are constants. Then x is equal to (-b +- sqrt (b2 -4ac) )/2a huh?? You asked what the quadratic equation was, I gave it to you. You need to read your text on this if you are lost...
*Saturday, July 14, 2007 at 7:40pm by April*

**algebra 2**

In google type: quadratic equation online When you see list of results click on: Free Online Quadratic Equation Solver:Solve by Quadratic Formula When page be open click option : Solve by Completing the Square Then in rectangle type: x^2-4x-32=0 and click option: solve it You ...
*Wednesday, May 9, 2012 at 6:41pm by Bosnian*

**maths**

for this quadratic equation: y2-4y-16 = 0 which two options are correct solutions, rounded to three decimal places? 1) -4.483 2) -3.243 3)-2.472 4) -1.472 5) -0.536 6) 5.243 7) 6.472 8) 12.443 Use the quadratic equation, we will be happy to critique your solution.
*Sunday, April 15, 2007 at 8:11pm by angel*

**math**

expand the two binomials, combine like terms, then put it in the form of a quadratic...you can then use the quadratic equation, or perhaps factor to find x.
*Tuesday, March 10, 2009 at 2:00pm by bobpursley*

**Math(Please check, urgent)**

Use the quadratic formula. You be able to do work of this nature you MUST have learned how to solve a quadratic equation.
*Monday, September 17, 2012 at 10:53pm by Reiny*

**College Algebra**

4x^2 = 8x-5 You must bring every term to one side of the equation. I would bring 8x - 5 to the left side. Don't forget change the sign of each term when crossing the equal sign. We now have this: 4x^2 -8x + 5 = 0 This is called a quadratic equation. The exponent of 2 gives ...
*Tuesday, October 21, 2008 at 4:55pm by Feliz*

**algebra**

1. All parts must be great of 0 less numbe is 11 solution x > 11 2. In google type: quadratic equation online When you see list of results click on: Free Online Quadratic Equation Solver:Solve by Quadratic Formula When page be open in rectangle type: 2x^2-x=-7 and click ...
*Saturday, December 31, 2011 at 12:02am by Bosnian*

**maths**

how do i find out the the equation of the line of symmetry for f(x)=ax^2+bx+c ? please explain it do me thanks! The line of symmetry runs through the vertex. so the x of the vertex is -b/(2a) and the equation of the line of symmetry is x = -b/(2a) e.g. for f(x) = 2x^2 - 12x + ...
*Friday, May 25, 2007 at 4:04am by Emma*

**chemistry**

You have two choices. 1)The simple choice, and one which doesn't always work, is to assume x is very small in comparison with 0.001 so that 0.001 - x = 0.001. That way you don't have a quadratic equation. You can try that, then see if 0.001 - x = about 0.001 or not. If x is ...
*Sunday, April 6, 2008 at 10:42pm by DrBob222*

**algebra**

i have very little information in my math book on the following questions. can you either tell me the answer or a link where i can find my own answer. thanks How do you know if a quadratic equation will have one, two, or no solutions? How do you find a quadratic equation if ...
*Monday, November 15, 2010 at 7:07pm by Donni*

**math**

x^2=3x-6 x^2-3x+6=0 In quadratic equation y=ax^2+bx+c discriminate is D=b^2-4ac In your case a=1 b= -3 c=6 D=b^2-4ac=(-3)^2-4*1*6=9-24= -15 When discriminante is negative quadratic have two imaginare solutions. If you want to know that solutions in google type: quadratic ...
*Thursday, February 17, 2011 at 1:11am by Bosnian*

**Algebra**

I do not know what your problem is. That is sort of the quadratic equation: x = [-b +/- sqrt(b^2-4ac)]/2a and you would get the two answers but I did not see the original quadratic so do not know if right or not (although I can do it backwards).
*Wednesday, March 19, 2008 at 7:21pm by Damon*

**Algebra**

Can someone help me with this question. I thought it was quadratic but now I am not sure. State whether the equation represents a linear, quadratic, exponential function or none of the above. x^2+ 6 = -8 x
*Thursday, January 14, 2010 at 1:44pm by Kate*

**Algebra**

I was given this answers to a problems I solved but I do not understand what she means hope you can help. Before attempting to solve this quadratic equation, determine how many solutions there will be for this quadratic equation. Explain your reasoning. Finally, solve the ...
*Thursday, June 2, 2011 at 9:57am by Charly*

**Algebra**

I was given this answers to a problems I solved but I do not understand what she means hope you can help. Before attempting to solve this quadratic equation, determine how many solutions there will be for this quadratic equation. Explain your reasoning. Finally, solve the ...
*Thursday, June 2, 2011 at 10:03am by Charly*

**algebra**

can someone explain the benefits of writing a quadratic equation in vertex form and benefits of writing a quadratic equation in standard form? Name specific methods you can use while working with one form or the other. Any help will be appreciated.
*Monday, November 5, 2012 at 10:01pm by Lee*

**algebra**

Solve the quadratic equation: 2x(squared)+6x+12=0 I know you have to find two numbers that =24 (2 times 12) and have a sum of 6. But I can't think of any! Can someone please help? Use the quadratic. And this problem has no real answers, they are imaginary. Oh, the quadratic ...
*Saturday, December 9, 2006 at 5:19pm by Sir Galahad*

**Math**

Have you ever heard of the quadratic formula? It's the easiest solution here. In the quadratic formula, for any quadratic equation in the for ax^2+bx+c=0 x=(-b}(b^2-4ac))/2a In this case: 4.905=a 2.93=b -10=c Think you can solve it from here? The rest is some simple ...
*Sunday, February 28, 2010 at 7:48pm by anonymous*

**chem**

In one of your earlier posts, you asked if this was the correct quadratic equation and it was. X^2 + 0.022X - 1.2E-4 = 0 Using the quadratic formula, which is X=(-b +/- sqrt[b^2-4ac])/2a solve for X. What is that value?
*Wednesday, March 26, 2008 at 12:42pm by DBob222*

**algebra**

In google type: quadratic equation online When you see list of result click on: Free Online Quadratic Equation Solver:Solve by Quadratic Formula When page be open in rectangle type: 2a^2-3a=-5 (Exactly in this form) Then click option: 2a^2-3a=-5 and cilck option: solve it! You...
*Tuesday, July 19, 2011 at 2:50pm by Bosnian*

**math**

If h = -16t^2 + 156t + 105 = 0 then In google type: quadratic equation online When you see list of results click on: Free Online Quadratic Equation Solver:Solve by Quadratic Formula When page be open in rectangle type: 16t^2 + 156t + 105 = 0 and click option: solve it! You wil...
*Saturday, April 14, 2012 at 10:17am by Bosnian*

**Math**

Solve quadratic equation: 11 m ^2 + 14m - 16 = 0 The solutions are: m1 = -2 m2= 8/11 Use formula for factoring quadratic equation: a m ^ 2 + b m + c = a(m - m1)(m - m2) Where m1 and m2 are solutions of quadratic equation In our case we have: 11 m^ 2 + 14 m - 16 = 11(m - (-2...
*Thursday, November 3, 2011 at 1:39am by Anonymous*

**math-calculus**

| x ^ 2 - 2 x - 6 |= 4 Eliminate the absolute value : x ^ 2 - 2 x - 6 = 4 OR x ^ 2 - 2 x - 6 = - 4 Your must solve both equations. In google type: quadratic equation online When you see list of results click on: Free Online Quadratic Equation Solver:Solve by Quadratic Formula ...
*Wednesday, January 18, 2012 at 11:25pm by Bosnian*

**algebra2**

This looks like a "prime" quadratic. With trial and error trying: (-4t )(t ) or (-2t )(t ) you cannot get it to work. So there are no "interger" solutions. You can use the famous "quadratic equation" to get an approximation. ARe you familiar with this?
*Tuesday, January 29, 2008 at 9:21pm by DanH*

**calculus**

from the second,y=15-3x then square it... 225-90x+9x^2 check that, and put it in for y^2 in the first equation, rearrange it in quadratic form, and solve for x using the quadratic formula.
*Tuesday, January 20, 2009 at 5:28pm by bobpursley*

**algebra**

I would multiply by 10 and re-arrange into a standard quadratic equation. t^2 + 500t - 11000 = 0 now use the quadratic formula to find the two real roots.
*Monday, August 24, 2009 at 10:11pm by Reiny*

**Chemistry**

Ksp = (Pb^+2)(SO4^=) = 1,8 x 10^-8 (Pb^+2) = x (SO4^=) = x+0.001 (x)(x+0.001) = 1.8 x 10^-8 You can see that this is a quadratic equation and we could solve it as a quadratic. The exact solution is (and I'm switching to y so as not to confuse the x with the times sign), y^2 + ...
*Monday, April 14, 2008 at 8:06pm by DrBob222*

**math**

In google type : quadratic equation calculator steps When you see list of results click on : algebra . com / algebra / homework / quadratic / When page be open type your equation and click option : Submit Query You will see solution
*Friday, October 26, 2012 at 3:09pm by Bosnian*

**Math**

Equate the two equation to get: x^2 - 8x - 35=-2(x^2) + 16x +3 Arrange terms and solve the quadratic equation using the quadratic formula (or otherwise) to get: x=(-sqrt(258)+12)/3 and x=(sqrt(258)+12)/3 The sum of the two roots give 24/3 = 8
*Wednesday, February 2, 2011 at 6:04pm by MathMate*

**Math**

A = 2 r h + 2 r ^ 2 2 r 10 + 2 r ^ 2 = 200 Divide both sides by 2 10 r + r ^ 2 = 100 / r ^ 2 + 10 r - 100 / = 0 100 / = 31.831 Y>ou nust solve equation : r ^ 2 + 10 r - 31.831 = 0 The solutions are : 2.54 in and - 12.54 in Radius can't be negative, so ...
*Sunday, April 29, 2012 at 7:49pm by Bosnian*

**Math (Trig)**

put it in quadratic form. 2 (sinX)^2 + sinX-1=0 now solve for sin x using the quadratic equation a=2 b=1 c=-1
*Sunday, December 16, 2007 at 6:55pm by bobpursley*

**MATH**

Put 125 as C, and solve for x. It will be a quadratic equation, use the quadratic formula (if you cant factor) and solve.
*Sunday, September 28, 2008 at 8:50pm by bobpursley*

**math-calculus**

solve equation |x^2-2x-6| using quadratic formula. i not get how to do this and it says quadratic formula.
*Wednesday, January 18, 2012 at 9:40pm by Shreya*

**Math**

L = 2 + 2 W = 2 ( 1 + W ) A = L * W 24 = 2 * ( 1 + W ) * W 24 = 2 * ( W + W ^ 2 ) Divide both sides by 2 12 = W + W ^ 2 Subtract 12 to both sides 0 = W + W ^ 2 - 12 Now you must solwe equation : W ^ 2 + W - 12 = 0 The exact solutions are 3 and - 4 Width cannot be negative so W...
*Friday, July 27, 2012 at 5:58am by Bosnian*

**trig**

In the quadratic equation ax²+bx+c=0 b/a = -(sum of the two roots) c/a = product of the two roots. Assume a=1, then b=-(7-3i+7+3i)=-14 c=(7-3i)*(7+3i)=49+9=58 So the quadratic equation is x²-14x+58=0 Check by solving the equation and you should get back 7±3i ...
*Tuesday, December 21, 2010 at 5:33pm by MathMate*

**Algebra Quadratic Equations**

When a quadratic equation has one solution, there will be one x-intercept; when there are two solutions, there will be two x-intercepts and when the equation has no solution, the graph will have no x-intercepts",is there another way of determining this?
*Wednesday, February 13, 2008 at 7:31am by Marysvoice*

**Math**

* By equation, I meant quadratic formula. Sorry for being vague. ** As well, I typed the quadratic formula wrong. It's: x = [-b (+ or -) [sqroot](b^2 -4ac)] / [2a]
*Thursday, June 10, 2010 at 4:28pm by Anonymous*

**math-calculus (quadratic formula)**

it actually say to use quadratic formula so i subtract 4 from both sides to get an equation by itself so i plug it in?
*Tuesday, January 17, 2012 at 11:49pm by Shreya*

**Math**

We have a quadratic equation here. Do you want to factor this equation? What exactly do you want to do with this equation?
*Tuesday, February 19, 2008 at 7:32pm by Guido*

**math**

If -16t^2+104 mean : - 16 t ^ 2 + 104 t then : in google type : quadratic equation online Wfen you see list of results click on : Free Online Quadratic Equation Solver: Solve by Quadratic Formula Select one of method. Then in rectangle type : - 16 t ^ 2 + 104 t = 169 and click...
*Wednesday, October 2, 2013 at 11:50am by Bosnian*

**Algebra Quadratic Equations**

I am supposed to write a quadratic equation using only the solutions and I am only given one solution:4. It can't be (x-4)=0. Can I use 0 to make (x-4)(x+0)=0?
*Thursday, February 28, 2008 at 9:25am by Micah*

**math The function D(x) models the cumulative numbe**

D(x)=2386x^2+5147x+5398=89000 2386x^2+5147x+5398-89000=0 2386x^2+5147x-83602=0 If you don't know solve that equation in google type: quadratic equation online When you see list of results click on: Free Online Quadratic Equation Solver:Solve by Quadratic Formula When page be ...
*Saturday, June 18, 2011 at 7:36pm by Anonymous*

**Mathematics**

in the first: notice that one equation is quadratic, the other is linear. sub the linear into the quadratic x^2 - 3x - 12 = y = 2x - 16 x^2 - 3x - 12 = 2x - 16 x^2 - 5x + 4 = 0 (x-1)(x-4) = 0 x = 1 or x = 4 sub into the easier of the two, namely into y = 2x - 16 if x = 1 then ...
*Thursday, June 25, 2009 at 10:35am by Reiny*

**trig**

cos ^ 2 ( x ) = 1 - sin ^ 2 ( x ) 2 cos ^ 2 ( x ) - sin ( x ) = 1 2 * [ 1 - sin ^ 2 ( x ) ] - sin ( x ) = 1 2 - 2 sin ^ 2 ( x ) - sin ( x ) = 1 Subtract 1 to both sides 2 - 2 sin ^ 2 ( x ) - sin ( x ) - 1 = 1 - 1 - 2 sin ^ 2 ( x ) - sin ( x ) + 1 = 0 Substitute : sin ( x ) = u...
*Thursday, May 17, 2012 at 4:47pm by Bosnian*

**Algebra**

For a quadratic equation ax²+bx+c = 0 ...(1) the discriminant is the algebraic value of b²-4ac For any given quadratic, you would rearrange it to have the form of equation (1) above, and calculate b²-4ac. For example, x^2 = 4 can be written as x^2 + 0x -4 =0 ...
*Wednesday, September 22, 2010 at 5:13pm by MathMate*

**Algebra**

w = width l = length A = Area l = w + 8 A = l * w A = ( w + 8 ) * w = 48 w ^ 2 + 8 w = 48 Subtract 48 to both sides w ^ 2 + 8 w - 48 = 48 - 48 w ^ 2 + 8 w - 48 = 0 The exact solutions are : w = 4 and w = - 12 Width can't be negative so : w = 4 cm l = w + 8 l = 4 + 8 = 12 cm A...
*Saturday, May 26, 2012 at 1:17pm by Bosnian*

**Math**

1) [x - (root1)][x - (root2)] = 0 Substitute in the two roots and multiply it out. 2) You should be able to do your own verification using the quadratic formula, x = [-b +/- sqrt(b^2/4ac)]/(2a) a,b and c are the coefficients in your quadratic equation from part 1.
*Thursday, December 11, 2008 at 11:27pm by drwls*

**Quadratic Equations**

two consecutive integers: x and x+1 <the sum of whose squares is 1 more than twelve times the larger..> x^2 + (x+1)^2 = 12(x+1) + 1 expand and solve as a quadratic equation. (see if you can come up with 6,7 or -1,0 )
*Sunday, March 29, 2009 at 12:54pm by Reiny*

**Math; Please Help!o:**

y=-1/4x^2-24 Hints: If the leading coefficient of a quadratic expression is negative, it opens downwards. For a general quadratic equation y=ax²+bx+c, The axis of symmetry is at the line y=-b/2a
*Thursday, March 1, 2012 at 7:32pm by MathMate*

**math: precal**

LOL lots of ways. If it is quadratic, use the quadratic equation. Try to factor it. If (ax+b)is a factor then it is zero when x = -b/a Graph it and look for crossings of the x axis. etc
*Sunday, March 20, 2011 at 4:54pm by Damon*

**algebra**

by inspection, x=-3 is a solution. -27+72-30-15=0 so, divide (x+3) into x^3+8x^2+10x-15 and get the quadratic. Then solve it with the quadratic equation. I get x^2+5x-5 check that.
*Friday, December 9, 2011 at 4:36pm by bobpursley*

**algebra 2**

I will do number 2 only. We have this: (x-3)^2 = -4 The left side becomes x^2 - 6x + 9. We now have this: x^2 - 6x + 9 = -4 Add 4 to both sides and then equate to zero. x^2 - 6x + 9 + 4 = 0 x^2 - 6x + 13 = 0 This quadratic equation cannot be solved by factoring. In that case, ...
*Tuesday, February 12, 2008 at 2:25pm by Guido*

**math**

a = first side b = second side A = Area b = a + 7 A = a * b A = a * ( a + 7 ) A = a ^ 2 + 7 a a ^ 2 + 7 a = 330 a ^ 2 + 7 a - 330 = 0 The exact solutions are: a = -22 and a = 15 The length can't be negative, so a = 15 m b = a + 7 b = 15 + 7 b = 22 m A = a * b A = 15 * 22 A = ...
*Thursday, October 20, 2011 at 4:57pm by Bosnian*

**trig**

find the exact solutions ( in degrees) sin^2+2cos=-2 change the sin^2 to 1-cos^2, then rearrage the equation into quadratic form, use the quadratic equaion.
*Monday, April 16, 2007 at 7:44pm by Devon*

**algebra**

if x=3, then f(x)=0, so put in x=3 into f(x)=0 and solve for b. Now that you know b, you can divide out the factor (x-2) and are left with a quadratic 3x^2+ ... which if =0, then you can factor or use the quadratic equation to find those two roots.
*Monday, April 16, 2012 at 4:03am by bobpursley*

**Algebra2**

1. Eliminate the absoulute value : x ^ 2 - 3 x + 3 = 3 x ^ 2 - 3 x + 3 = - 3 ______________________ x ^ 2 - 3 x + 3 = 3 Subtract 3 to both sides x ^ 2 - 3 x + 3 - 3 = 3 - 3 x ^ 2 - 3 x = 0 x ( x - 3 ) = 0 Solutions : x = 0 and x = 3 x ^ 2 - 3 x + 3 = - 3 Add 3 to both sides x...
*Friday, August 17, 2012 at 10:57am by Bosnian*

**Algebra**

Not quite: A: x-coordinate of the vertex, also of the axis of symmetry B: not a quadratic at all; just a line C: the discriminant D: likely the parent equation E: quadratic formula. Note how the roots are equally spaced around x = -b/2a
*Friday, February 28, 2014 at 2:21am by Steve*

**mathematics**

I am assuming there is only the one equation x^2 - 3x - 12 = 0, because what follows makes no sense First of all your quadratic does not factor, so you will have to either use the quadratic equation formula or complete the square. let's use the formula: x = (3 √(9-4(1...
*Saturday, June 27, 2009 at 10:56am by Reiny*

**Algebra1 HELP PLEASE**

A little technicality : A quadratic equation does not have an axis of symmetry, a quadratic function does. the corresponding quadratic function would be f(x) = (x+1)(x-7), which would have zeros of -1 and 7 the axis of symmetry would be half-way between these two values, or x = 4
*Wednesday, July 3, 2013 at 2:49pm by Reiny*

**Math**

there is only one Quadratic Formula. It allows you to compute the roots of any quadratic equation. Given the equation ax^2 + bx + c = 0, the roots are given by x = [-b √(b^2 - 4ac)]/2a Now, you have x^2 + 8x + 12 = 0 so, the two roots of this equation are [-8 √...
*Wednesday, January 18, 2012 at 10:34am by Steve*

**math**

Yes, the quadratic formula is a way of solving for x (or p in this case). The Quadratic Formula states that for any equation ax^2 + bx + c... x = -b +- √(b^2 - 4ac) all over 2a. Identify your a, b, and c, and then plug and chug.
*Sunday, November 25, 2007 at 9:50pm by Michael*

**Physics**

vertical speed initially: 2.4*sin30 time to ground: h=vi*t+1/2 g t^2 1.2=2.4*sin30*t+4.9t^2 put this in quadratic form, and solve for t using the quadratic equation. horizonal distance= 2.4cos30*t
*Friday, October 14, 2011 at 8:12pm by bobpursley*

**phy**

in the vertical: hf=hi+vi*t-4.9t^2 0=45+20*sin30*t-4.9t^2 put that in standard form for a quadratic at^2+bt+c=0 use the quadratic equation t=(-b+-sqrt(b^2-4ac))/2a
*Friday, October 12, 2012 at 2:50pm by bobpursley*

**trigonometry**

6 cos ^ 2 ( x ) + sin ( x ) = 4 Then : 6 * [ 1 - sin ^ 2 ( x ) ] + sin ( x )= 4 6 - 6 sin ^ 2 ( x ) + sin ( x ) = 4 - 6 sin ^ 2 ( x ) + sin ( x ) + 6 - 4 = 0 - 6 sin ^ 2 ( x ) + sin ( x ) + 2 = 0 Substitution : sin ( x ) = u - 6 u ^ 2 + u + 2 = 0 The exact solutions are : u = ...
*Monday, April 23, 2012 at 10:17pm by Bosnian*

**Quadratic equations**

OK. I think I have my head around most of this but for one question. I have plotted a graph with the quadratic equation tickets=-02x^2+12x+11. My graph opens down and shows I will sell tickets for 60 days peaking at the vertex at 30 days where I sell 191 tickets. Now I have to...
*Monday, February 11, 2008 at 10:32am by Marysvoice*

**calculus**

The y-axis is the line x=0. Thus substitute x=0 in the given equation and solve for y: x^2+y^2+2x-2y-14=0, substitute x=0 0+y²+0-2y-14=0 y²-2y-14=0 The resulting quadratic equation can be solved using the quadratic formula. If you need further help, please post a ...
*Sunday, March 11, 2012 at 9:46am by MathMate*

**Math**

You must solve two quadratic equations. 0.02 s ^ 2 + 1.1 s = 51 and 0.02 s ^ 2 + 1.1 s = 315.12 If you dont know how solve equations in google type: quadratic equation online When you see list of results click on: Free Online Quadratic Equation Solver:Solve by Quadratic ...
*Saturday, February 25, 2012 at 9:24pm by Bosnian*

**Math x-int's**

It is actually very simple. To solve an equation of the form: x^3 + a x^2 + b x + c = 0 you follow the following steps. First, get rid of the quadratic term a x^2 using the substitution: x = y - a/3 This step is analogous to how you solve the quadratic equation when you write ...
*Saturday, December 8, 2007 at 6:01pm by Count Iblis*

**chemistry**

Two problems with what you did. 1. %ion = [(H3O^+)/0.025]*100 = ?? 2. Your equation is set up correctly; i.e., x^2/(0.025-x) = Ka. However, with Ka so large and (HClO2) so small, you MUST solve the quadratic equation. That is, you may not assume 0.025-x = 0.025. 3. I get 47.9...
*Saturday, July 30, 2011 at 7:13pm by DrBob222*

**MATH**

Find all real solutions of the equation by first rewriting the equation as a quadratic equation. (Enter your answers as a comma-separated list.) 4x4 + 15x2 − 4 = 0
*Saturday, August 4, 2012 at 8:17pm by Emmett*

**trig**

3 cos ^ 2 theta - 5 cos theta - 1 - 3 sin ^ 2 theta = 0 3 cos ^ 2 theta - 5 cos theta - 1 - 3 ( 1 - cos ^ 2 theta ) = 0 3 cos ^ 2 theta - 5 cos theta - 1 - 3 + 3 cos ^ 2 theta = 0 6 cos ^ 2 theta - 5 cos theta - 4 = 0 Substitute : u = cos theta 6 u ^ 2 - 5 u - 4 = 0 The exact ...
*Monday, April 9, 2012 at 10:29pm by Bosnian*

**math**

Factoring a quadratic and solving the corresponding quadratic equation are closely related. in the first case I would consider solving it as x^2 + 8x + 53 = 0 since the only factors of 53 are 1 and 53 itself, there is no way we can get that 8 in the middle. using the formula ...
*Monday, November 1, 2010 at 9:36pm by Reiny*

**Linear Algebra**

The solution to the problem is based on two key questions: 1. How to find eigenvalues of a given matrix? 2. What are the conditions for a quadratic equation to have real roots of multiplicity two? We will answer the questions one by one. 1. For a given (square) matrix A, the ...
*Wednesday, April 27, 2011 at 11:58pm by MathMate*

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